This tutorial tries to give an overview of the functionality concerning polynomials within SymPy. All code examples assume:
>>> from sympy import *
>>> x, y, z = symbols('x,y,z')
>>> init_printing(use_unicode=False, wrap_line=False, no_global=True)
These functions provide different algorithms dealing with polynomials in the form of SymPy expression, like symbols, sums etc.
The function div() provides division of polynomials with remainder. That is, for polynomials f and g, it computes q and r, such that \(f = g \cdot q + r\) and \(\deg(r) < q\). For polynomials in one variables with coefficients in a field, say, the rational numbers, q and r are uniquely defined this way:
>>> f = 5*x**2 + 10*x + 3
>>> g = 2*x + 2
>>> q, r = div(f, g, domain='QQ')
>>> q
5*x 5
 + 
2 2
>>> r
2
>>> (q*g + r).expand()
2
5*x + 10*x + 3
As you can see, q has a noninteger coefficient. If you want to do division only in the ring of polynomials with integer coefficients, you can specify an additional parameter:
>>> q, r = div(f, g, domain='ZZ')
>>> q
0
>>> r
2
5*x + 10*x + 3
But be warned, that this ring is no longer Euclidean and that the degree of the remainder doesn’t need to be smaller than that of f. Since 2 doesn’t divide 5, \(2 x\) doesn’t divide \(5 x^2\), even if the degree is smaller. But:
>>> g = 5*x + 1
>>> q, r = div(f, g, domain='ZZ')
>>> q
x
>>> r
9*x + 3
>>> (q*g + r).expand()
2
5*x + 10*x + 3
This also works for polynomials with multiple variables:
>>> f = x*y + y*z
>>> g = 3*x + 3*z
>>> q, r = div(f, g, domain='QQ')
>>> q
y

3
>>> r
0
In the last examples, all of the three variables x, y and z are assumed to be variables of the polynomials. But if you have some unrelated constant as coefficient, you can specify the variables explicitly:
>>> a, b, c = symbols('a,b,c')
>>> f = a*x**2 + b*x + c
>>> g = 3*x + 2
>>> q, r = div(f, g, domain='QQ')
>>> q
a*x 2*a b
   + 
3 9 3
>>> r
4*a 2*b
   + c
9 3
With division, there is also the computation of the greatest common divisor and the least common multiple.
When the polynomials have integer coefficients, the contents’ gcd is also considered:
>>> f = (12*x + 12)*x
>>> g = 16*x**2
>>> gcd(f, g)
4*x
But if the polynomials have rational coefficients, then the returned polynomial is monic:
>>> f = 3*x**2/2
>>> g = 9*x/4
>>> gcd(f, g)
x
It also works with multiple variables. In this case, the variables are ordered alphabetically, be default, which has influence on the leading coefficient:
>>> f = x*y/2 + y**2
>>> g = 3*x + 6*y
>>> gcd(f, g)
x + 2*y
The lcm is connected with the gcd and one can be computed using the other:
>>> f = x*y**2 + x**2*y
>>> g = x**2*y**2
>>> gcd(f, g)
x*y
>>> lcm(f, g)
3 2 2 3
x *y + x *y
>>> (f*g).expand()
4 3 3 4
x *y + x *y
>>> (gcd(f, g, x, y)*lcm(f, g, x, y)).expand()
4 3 3 4
x *y + x *y
The squarefree factorization of a univariate polynomial is the product of all factors (not necessarily irreducible) of degree 1, 2 etc.:
>>> f = 2*x**2 + 5*x**3 + 4*x**4 + x**5
>>> sqf_list(f)
(1, [(x + 2, 1), (x, 2), (x + 1, 2)])
>>> sqf(f)
2 2
x *(x + 1) *(x + 2)
This function provides factorization of univariate and multivariate polynomials with rational coefficients:
>>> factor(x**4/2 + 5*x**3/12  x**2/3)
2
x *(2*x  1)*(3*x + 4)

12
>>> factor(x**2 + 4*x*y + 4*y**2)
2
(x + 2*y)
Buchberger’s algorithm is implemented, supporting various monomial orders:
>>> groebner([x**2 + 1, y**4*x + x**3], x, y, order='lex')
/[ 2 4 ] \
GroebnerBasis\[x + 1, y  1], x, y, domain=ZZ, order=lex/
>>> groebner([x**2 + 1, y**4*x + x**3, x*y*z**3], x, y, z, order='grevlex')
/[ 4 3 2 ] \
GroebnerBasis\[y  1, z , x + 1], x, y, z, domain=ZZ, order=grevlex/
We have (incomplete) methods to find the complex or even symbolic roots of polynomials and to solve some systems of polynomial equations:
>>> from sympy import roots, solve_poly_system
>>> solve(x**3 + 2*x + 3, x)
____ ____
1 \/ 11 *I 1 \/ 11 *I
[1,   ,  + ]
2 2 2 2
>>> p = Symbol('p')
>>> q = Symbol('q')
>>> solve(x**2 + p*x + q, x)
__________ __________
/ 2 / 2
p \/ p  4*q p \/ p  4*q
[   ,   + ]
2 2 2 2
>>> solve_poly_system([y  x, x  5], x, y)
[(5, 5)]
>>> solve_poly_system([y**2  x**3 + 1, y*x], x, y)
___ ___
1 \/ 3 *I 1 \/ 3 *I
[(0, I), (0, I), (1, 0), (   , 0), (  + , 0)]
2 2 2 2