# Source code for sympy.integrals.integrals

from __future__ import print_function, division

from sympy.core.basic import Basic
from sympy.core.compatibility import is_sequence, range
from sympy.core.containers import Tuple
from sympy.core.expr import Expr
from sympy.core.function import diff
from sympy.core.mul import Mul
from sympy.core.numbers import oo
from sympy.core.relational import Eq
from sympy.core.singleton import S
from sympy.core.symbol import (Dummy, Symbol, Wild)
from sympy.core.sympify import sympify
from sympy.integrals.manualintegrate import manualintegrate
from sympy.integrals.trigonometry import trigintegrate
from sympy.integrals.meijerint import meijerint_definite, meijerint_indefinite
from sympy.matrices import MatrixBase
from sympy.utilities.misc import filldedent
from sympy.polys import Poly, PolynomialError
from sympy.functions import Piecewise, sqrt, sign
from sympy.functions.elementary.exponential import log
from sympy.series import limit
from sympy.series.order import Order

"""Represents unevaluated integral."""

__slots__ = ['is_commutative']

def __new__(cls, function, *symbols, **assumptions):
"""Create an unevaluated integral.

Arguments are an integrand followed by one or more limits.

If no limits are given and there is only one free symbol in the
expression, that symbol will be used, otherwise an error will be
raised.

>>> from sympy import Integral
>>> from sympy.abc import x, y
>>> Integral(x)
Integral(x, x)
>>> Integral(y)
Integral(y, y)

When limits are provided, they are interpreted as follows (using
x as though it were the variable of integration):

(x,) or x - indefinite integral
(x, a) - "evaluate at" integral is an abstract antiderivative
(x, a, b) - definite integral

The as_dummy method can be used to see which symbols cannot be
targeted by subs: those with a preppended underscore cannot be
changed with subs. (Also, the integration variables themselves --
the first element of a limit -- can never be changed by subs.)

>>> i = Integral(x, x)
>>> at = Integral(x, (x, x))
>>> i.as_dummy()
Integral(x, x)
>>> at.as_dummy()
Integral(_x, (_x, x))

"""

#This will help other classes define their own definitions
#of behaviour with Integral.
if hasattr(function, '_eval_Integral'):
return function._eval_Integral(*symbols, **assumptions)

obj = AddWithLimits.__new__(cls, function, *symbols, **assumptions)
return obj

def __getnewargs__(self):
return (self.function,) + tuple([tuple(xab) for xab in self.limits])

@property
def free_symbols(self):
"""
This method returns the symbols that will exist when the
integral is evaluated. This is useful if one is trying to
determine whether an integral depends on a certain
symbol or not.

Examples
========

>>> from sympy import Integral
>>> from sympy.abc import x, y
>>> Integral(x, (x, y, 1)).free_symbols
{y}

========

function, limits, variables
"""

def _eval_is_zero(self):
# This is a very naive and quick test, not intended to do the integral to
# answer whether it is zero or not, e.g. Integral(sin(x), (x, 0, 2*pi))
# is zero but this routine should return None for that case. But, like
# Mul, there are trivial situations for which the integral will be
# zero so we check for those.
if self.function.is_zero:
return True
got_none = False
for l in self.limits:
if len(l) == 3:
z = (l[1] == l[2]) or (l[1] - l[2]).is_zero
if z:
return True
elif z is None:
got_none = True
free = self.function.free_symbols
for xab in self.limits:
if len(xab) == 1:
continue
if len(xab) == 2 and xab[0] not in free:
if xab[1].is_zero:
return True
elif xab[1].is_zero is None:
got_none = True
# take integration symbol out of free since it will be replaced
# with the free symbols in the limits
# add in the new symbols
for i in xab[1:]:
free.update(i.free_symbols)
if self.function.is_zero is False and got_none is False:
return False

[docs]    def transform(self, x, u):
r"""
Performs a change of variables from x to u using the relationship
given by x and u which will define the transformations f and F
(which are inverses of each other) as follows:

1) If x is a Symbol (which is a variable of integration) then u
will be interpreted as some function, f(u), with inverse F(u).
This, in effect, just makes the substitution of x with f(x).

2) If u is a Symbol then x will be interpreted as some function,
F(x), with inverse f(u). This is commonly referred to as
u-substitution.

Once f and F have been identified, the transformation is made as
follows:

.. math:: \int_a^b x \mathrm{d}x \rightarrow \int_{F(a)}^{F(b)} f(x)
\frac{\mathrm{d}}{\mathrm{d}x}

where F(x) is the inverse of f(x) and the limits and integrand have
been corrected so as to retain the same value after integration.

Notes
=====

The mappings, F(x) or f(u), must lead to a unique integral. Linear
or rational linear expression, 2*x, 1/x and sqrt(x), will
always work; quadratic expressions like x**2 - 1 are acceptable
as long as the resulting integrand does not depend on the sign of
the solutions (see examples).

The integral will be returned unchanged if x is not a variable of
integration.

x must be (or contain) only one of of the integration variables. If
u has more than one free symbol then it should be sent as a tuple
(u, uvar) where uvar identifies which variable is replacing
the integration variable.
XXX can it contain another integration variable?

Examples
========

>>> from sympy.abc import a, b, c, d, x, u, y
>>> from sympy import Integral, S, cos, sqrt

>>> i = Integral(x*cos(x**2 - 1), (x, 0, 1))

transform can change the variable of integration

>>> i.transform(x, u)
Integral(u*cos(u**2 - 1), (u, 0, 1))

transform can perform u-substitution as long as a unique
integrand is obtained:

>>> i.transform(x**2 - 1, u)
Integral(cos(u)/2, (u, -1, 0))

This attempt fails because x = +/-sqrt(u + 1) and the
sign does not cancel out of the integrand:

>>> Integral(cos(x**2 - 1), (x, 0, 1)).transform(x**2 - 1, u)
Traceback (most recent call last):
...
ValueError:
The mapping between F(x) and f(u) did not give a unique integrand.

transform can do a substitution. Here, the previous
result is transformed back into the original expression
using "u-substitution":

>>> ui = _
>>> _.transform(sqrt(u + 1), x) == i
True

We can accomplish the same with a regular substitution:

>>> ui.transform(u, x**2 - 1) == i
True

If the x does not contain a symbol of integration then
the integral will be returned unchanged. Integral i does
not have an integration variable a so no change is made:

>>> i.transform(a, x) == i
True

When u has more than one free symbol the symbol that is
replacing x must be identified by passing u as a tuple:

>>> Integral(x, (x, 0, 1)).transform(x, (u + a, u))
Integral(a + u, (u, -a, -a + 1))
>>> Integral(x, (x, 0, 1)).transform(x, (u + a, a))
Integral(a + u, (a, -u, -u + 1))

========

variables : Lists the integration variables
as_dummy : Replace integration variables with dummy ones
"""
from sympy.solvers.solvers import solve, posify
d = Dummy('d')

xfree = x.free_symbols.intersection(self.variables)
if len(xfree) > 1:
raise ValueError(
'F(x) can only contain one of: %s' % self.variables)
xvar = xfree.pop() if xfree else d

if xvar not in self.variables:
return self

u = sympify(u)
if isinstance(u, Expr):
ufree = u.free_symbols
if len(ufree) != 1:
raise ValueError(filldedent('''
When f(u) has more than one free symbol, the one replacing x
must be identified: pass f(u) as (f(u), u)'''))
uvar = ufree.pop()
else:
u, uvar = u
if uvar not in u.free_symbols:
raise ValueError(filldedent('''
Expecting a tuple (expr, symbol) where symbol identified
a free symbol in expr, but symbol is not in expr's free
symbols.'''))
if not isinstance(uvar, Symbol):
raise ValueError(filldedent('''
Expecting a tuple (expr, symbol) but didn't get
a symbol; got %s''' % uvar))

if x.is_Symbol and u.is_Symbol:
return self.xreplace({x: u})

if not x.is_Symbol and not u.is_Symbol:
raise ValueError('either x or u must be a symbol')

if uvar == xvar:
return self.transform(x, (u.subs(uvar, d), d)).xreplace({d: uvar})

if uvar in self.limits:
raise ValueError(filldedent('''
u must contain the same variable as in x
or a variable that is not already an integration variable'''))

if not x.is_Symbol:
F = [x.subs(xvar, d)]
soln = solve(u - x, xvar, check=False)
if not soln:
raise ValueError('no solution for solve(F(x) - f(u), x)')
f = [fi.subs(uvar, d) for fi in soln]
else:
f = [u.subs(uvar, d)]
pdiff, reps = posify(u - x)
puvar = uvar.subs([(v, k) for k, v in reps.items()])
soln = [s.subs(reps) for s in solve(pdiff, puvar)]
if not soln:
raise ValueError('no solution for solve(F(x) - f(u), u)')
F = [fi.subs(xvar, d) for fi in soln]

newfuncs = set([(self.function.subs(xvar, fi)*fi.diff(d)
).subs(d, uvar) for fi in f])
if len(newfuncs) > 1:
raise ValueError(filldedent('''
The mapping between F(x) and f(u) did not give
a unique integrand.'''))
newfunc = newfuncs.pop()

def _calc_limit_1(F, a, b):
"""
replace d with a, using subs if possible, otherwise limit
where sign of b is considered
"""
wok = F.subs(d, a)
if wok is S.NaN or wok.is_finite is False and a.is_finite:
return limit(sign(b)*F, d, a)
return wok

def _calc_limit(a, b):
"""
replace d with a, using subs if possible, otherwise limit
where sign of b is considered
"""
avals = list({_calc_limit_1(Fi, a, b) for Fi in F})
if len(avals) > 1:
raise ValueError(filldedent('''
The mapping between F(x) and f(u) did not
give a unique limit.'''))
return avals[0]

newlimits = []
for xab in self.limits:
sym = xab[0]
if sym == xvar:
if len(xab) == 3:
a, b = xab[1:]
a, b = _calc_limit(a, b), _calc_limit(b, a)
if a - b > 0:
a, b = b, a
newfunc = -newfunc
newlimits.append((uvar, a, b))
elif len(xab) == 2:
a = _calc_limit(xab[1], 1)
newlimits.append((uvar, a))
else:
newlimits.append(uvar)
else:
newlimits.append(xab)

return self.func(newfunc, *newlimits)

[docs]    def doit(self, **hints):
"""
Perform the integration using any hints given.

Examples
========

>>> from sympy import Integral
>>> from sympy.abc import x, i
>>> Integral(x**i, (i, 1, 3)).doit()
Piecewise((2, Eq(log(x), 0)), (x**3/log(x) - x/log(x), True))

========

sympy.integrals.trigonometry.trigintegrate
sympy.integrals.risch.heurisch
sympy.integrals.rationaltools.ratint
as_sum : Approximate the integral using a sum
"""
if not hints.get('integrals', True):
return self

deep = hints.get('deep', True)
meijerg = hints.get('meijerg', None)
conds = hints.get('conds', 'piecewise')
risch = hints.get('risch', None)
manual = hints.get('manual', None)

if conds not in ['separate', 'piecewise', 'none']:
raise ValueError('conds must be one of "separate", "piecewise", '
'"none", got: %s' % conds)

if risch and any(len(xab) > 1 for xab in self.limits):
raise ValueError('risch=True is only allowed for indefinite integrals.')

# check for the trivial zero
if self.is_zero:
return S.Zero

# now compute and check the function
function = self.function
if deep:
function = function.doit(**hints)
if function.is_zero:
return S.Zero

if isinstance(function, MatrixBase):
return function.applyfunc(lambda f: self.func(f, self.limits).doit(**hints))

# There is no trivial answer, so continue

undone_limits = []
# ulj = free symbols of any undone limits' upper and lower limits
ulj = set()
for xab in self.limits:
# compute uli, the free symbols in the
# Upper and Lower limits of limit I
if len(xab) == 1:
uli = set(xab[:1])
elif len(xab) == 2:
uli = xab[1].free_symbols
elif len(xab) == 3:
uli = xab[1].free_symbols.union(xab[2].free_symbols)
# this integral can be done as long as there is no blocking
# limit that has been undone. An undone limit is blocking if
# it contains an integration variable that is in this limit's
# upper or lower free symbols or vice versa
if xab[0] in ulj or any(v[0] in uli for v in undone_limits):
undone_limits.append(xab)
ulj.update(uli)
function = self.func(*([function] + [xab]))
factored_function = function.factor()
if not isinstance(factored_function, Integral):
function = factored_function
continue

# There are a number of tradeoffs in using the Meijer G method.
# It can sometimes be a lot faster than other methods, and
# sometimes slower. And there are certain types of integrals for
# which it is more likely to work than others.
# These heuristics are incorporated in deciding what integration
# methods to try, in what order.
# See the integrate() docstring for details.
def try_meijerg(function, xab):
ret = None
if len(xab) == 3 and meijerg is not False:
x, a, b = xab
try:
res = meijerint_definite(function, x, a, b)
except NotImplementedError:
from sympy.integrals.meijerint import _debug
_debug('NotImplementedError from meijerint_definite')
res = None
if res is not None:
f, cond = res
if conds == 'piecewise':
ret = Piecewise((f, cond),
(self.func(function, (x, a, b)), True))
elif conds == 'separate':
if len(self.limits) != 1:
raise ValueError('conds=separate not supported in '
'multiple integrals')
ret = f, cond
else:
ret = f
return ret

meijerg1 = meijerg
if len(xab) == 3 and xab[1].is_real and xab[2].is_real \
and not function.is_Poly and \
(xab[1].has(oo, -oo) or xab[2].has(oo, -oo)):
ret = try_meijerg(function, xab)
if ret is not None:
function = ret
continue
else:
meijerg1 = False

# If the special meijerg code did not succeed in finding a definite
# integral, then the code using meijerint_indefinite will not either
# (it might find an antiderivative, but the answer is likely to be
#  nonsensical).
# Thus if we are requested to only use Meijer G-function methods,
# we give up at this stage. Otherwise we just disable G-function
# methods.
if meijerg1 is False and meijerg is True:
antideriv = None
else:
antideriv = self._eval_integral(
function, xab[0],
meijerg=meijerg1, risch=risch, manual=manual,
conds=conds)
if antideriv is None and meijerg1 is True:
ret = try_meijerg(function, xab)
if ret is not None:
function = ret
continue

if antideriv is None:
undone_limits.append(xab)
function = self.func(*([function] + [xab])).factor()
factored_function = function.factor()
if not isinstance(factored_function, Integral):
function = factored_function
continue
else:
if len(xab) == 1:
function = antideriv
else:
if len(xab) == 3:
x, a, b = xab
elif len(xab) == 2:
x, b = xab
a = None
else:
raise NotImplementedError

if deep:
if isinstance(a, Basic):
a = a.doit(**hints)
if isinstance(b, Basic):
b = b.doit(**hints)

if antideriv.is_Poly:
gens = list(antideriv.gens)
gens.remove(x)

antideriv = antideriv.as_expr()

function = antideriv._eval_interval(x, a, b)
function = Poly(function, *gens)
else:
def is_indef_int(g, x):
return (isinstance(g, Integral) and
any(i == (x,) for i in g.limits))

def eval_factored(f, x, a, b):
# _eval_interval for integrals with
# (constant) factors
# a single indefinite integral is assumed
args = []
for g in Mul.make_args(f):
if is_indef_int(g, x):
args.append(g._eval_interval(x, a, b))
else:
args.append(g)
return Mul(*args)

integrals, others = [], []
if any(is_indef_int(g, x)
for g in Mul.make_args(f)):
integrals.append(f)
else:
others.append(f)
uneval = Add(*[eval_factored(f, x, a, b)
for f in integrals])
try:
function = uneval + evalued
except NotImplementedError:
# This can happen if _eval_interval depends in a
# complicated way on limits that cannot be computed
undone_limits.append(xab)
function = self.func(*([function] + [xab]))
factored_function = function.factor()
if not isinstance(factored_function, Integral):
function = factored_function
return function

def _eval_derivative(self, sym):
"""Evaluate the derivative of the current Integral object by
differentiating under the integral sign [1], using the Fundamental
Theorem of Calculus [2] when possible.

Whenever an Integral is encountered that is equivalent to zero or
has an integrand that is independent of the variable of integration
those integrals are performed. All others are returned as Integral
instances which can be resolved with doit() (provided they are integrable).

References:
[1] http://en.wikipedia.org/wiki/Differentiation_under_the_integral_sign
[2] http://en.wikipedia.org/wiki/Fundamental_theorem_of_calculus

Examples
========

>>> from sympy import Integral
>>> from sympy.abc import x, y
>>> i = Integral(x + y, y, (y, 1, x))
>>> i.diff(x)
Integral(x + y, (y, x)) + Integral(1, y, (y, 1, x))
>>> i.doit().diff(x) == i.diff(x).doit()
True
>>> i.diff(y)
0

The previous must be true since there is no y in the evaluated integral:

>>> i.free_symbols
{x}
>>> i.doit()
2*x**3/3 - x/2 - 1/6

"""

# differentiate under the integral sign; we do not
# check for regularity conditions (TODO), see issue 4215

# get limits and the function
f, limits = self.function, list(self.limits)

# the order matters if variables of integration appear in the limits
# so work our way in from the outside to the inside.
limit = limits.pop(-1)
if len(limit) == 3:
x, a, b = limit
elif len(limit) == 2:
x, b = limit
a = None
else:
a = b = None
x = limit[0]

if limits:  # f is the argument to an integral
f = self.func(f, *tuple(limits))

# assemble the pieces
def _do(f, ab):
dab_dsym = diff(ab, sym)
if not dab_dsym:
return S.Zero
if isinstance(f, Integral):
limits = [(x, x) if (len(l) == 1 and l[0] == x) else l
for l in f.limits]
f = self.func(f.function, *limits)
return f.subs(x, ab)*dab_dsym
rv = 0
if b is not None:
rv += _do(f, b)
if a is not None:
rv -= _do(f, a)
if len(limit) == 1 and sym == x:
# the dummy variable *is* also the real-world variable
arg = f
rv += arg
else:
# the dummy variable might match sym but it's
# only a dummy and the actual variable is determined
# by the limits, so mask off the variable of integration
# while differentiating
u = Dummy('u')
arg = f.subs(x, u).diff(sym).subs(u, x)
rv += self.func(arg, Tuple(x, a, b))
return rv

def _eval_integral(self, f, x, meijerg=None, risch=None, manual=None,
conds='piecewise'):
"""
Calculate the anti-derivative to the function f(x).

The following algorithms are applied (roughly in this order):

1. Simple heuristics (based on pattern matching and integral table):

- most frequently used functions (e.g. polynomials, products of trig functions)

2. Integration of rational functions:

- A complete algorithm for integrating rational functions is
implemented (the Lazard-Rioboo-Trager algorithm).  The algorithm
also uses the partial fraction decomposition algorithm
implemented in apart() as a preprocessor to make this process
faster.  Note that the integral of a rational function is always
elementary, but in general, it may include a RootSum.

3. Full Risch algorithm:

- The Risch algorithm is a complete decision
procedure for integrating elementary functions, which means that
given any elementary function, it will either compute an
elementary antiderivative, or else prove that none exists.
Currently, part of transcendental case is implemented, meaning
elementary integrals containing exponentials, logarithms, and
(soon!) trigonometric functions can be computed.  The algebraic
case, e.g., functions containing roots, is much more difficult
and is not implemented yet.

- If the routine fails (because the integrand is not elementary, or
because a case is not implemented yet), it continues on to the
next algorithms below.  If the routine proves that the integrals
is nonelementary, it still moves on to the algorithms below,
because we might be able to find a closed-form solution in terms
of special functions.  If risch=True, however, it will stop here.

4. The Meijer G-Function algorithm:

- This algorithm works by first rewriting the integrand in terms of
very general Meijer G-Function (meijerg in SymPy), integrating
it, and then rewriting the result back, if possible.  This
algorithm is particularly powerful for definite integrals (which
is actually part of a different method of Integral), since it can
compute closed-form solutions of definite integrals even when no
closed-form indefinite integral exists.  But it also is capable
of computing many indefinite integrals as well.

- Another advantage of this method is that it can use some results
about the Meijer G-Function to give a result in terms of a
Piecewise expression, which allows to express conditionally
convergent integrals.

- Setting meijerg=True will cause integrate() to use only this
method.

5. The "manual integration" algorithm:

- This algorithm tries to mimic how a person would find an
antiderivative by hand, for example by looking for a
substitution or applying integration by parts. This algorithm
does not handle as many integrands but can return results in a
more familiar form.

- Sometimes this algorithm can evaluate parts of an integral; in
this case integrate() will try to evaluate the rest of the
integrand using the other methods here.

- Setting manual=True will cause integrate() to use only this
method.

6. The Heuristic Risch algorithm:

- This is a heuristic version of the Risch algorithm, meaning that
it is not deterministic.  This is tried as a last resort because
it can be very slow.  It is still used because not enough of the
full Risch algorithm is implemented, so that there are still some
integrals that can only be computed using this method.  The goal
is to implement enough of the Risch and Meijer G-function methods
so that this can be deleted.

"""
from sympy.integrals.deltafunctions import deltaintegrate
from sympy.integrals.singularityfunctions import singularityintegrate
from sympy.integrals.heurisch import heurisch, heurisch_wrapper
from sympy.integrals.rationaltools import ratint
from sympy.integrals.risch import risch_integrate

if risch:
try:
return risch_integrate(f, x, conds=conds)
except NotImplementedError:
return None

if manual:
try:
result = manualintegrate(f, x)
if result is not None and result.func != Integral:
return result
except (ValueError, PolynomialError):
pass

# if it is a poly(x) then let the polynomial integrate itself (fast)
#
# It is important to make this check first, otherwise the other code
# will return a sympy expression instead of a Polynomial.
#
# see Polynomial for details.
if isinstance(f, Poly) and not meijerg:
return f.integrate(x)

# Piecewise antiderivatives need to call special integrate.
if f.func is Piecewise:
return f._eval_integral(x)

# let's cut it short if f does not depend on x
if not f.has(x):
return f*x

# try to convert to poly(x) and then integrate if successful (fast)
poly = f.as_poly(x)
if poly is not None and not meijerg:
return poly.integrate().as_expr()

if risch is not False:
try:
result, i = risch_integrate(f, x, separate_integral=True, conds=conds)
except NotImplementedError:
pass
else:
if i:
# There was a nonelementary integral. Try integrating it.
return result + i.doit(risch=False)
else:
return result

# since Integral(f=g1+g2+...) == Integral(g1) + Integral(g2) + ...
# we are going to handle Add terms separately,
# if f is not Add -- we only have one term

# Note that in general, this is a bad idea, because Integral(g1) +
# Integral(g2) might not be computable, even if Integral(g1 + g2) is.
# For example, Integral(x**x + x**x*log(x)).  But many heuristics only
# work term-wise.  So we compute this step last, after trying
# risch_integrate.  We also try risch_integrate again in this loop,
# because maybe the integral is a sum of an elementary part and a
# nonelementary part (like erf(x) + exp(x)).  risch_integrate() is
# quite fast, so this is acceptable.
parts = []
for g in args:
coeff, g = g.as_independent(x)

# g(x) = const
if g is S.One and not meijerg:
parts.append(coeff*x)
continue

# g(x) = expr + O(x**n)
order_term = g.getO()

if order_term is not None:
h = self._eval_integral(g.removeO(), x)

if h is not None:
h_order_expr = self._eval_integral(order_term.expr, x)

if h_order_expr is not None:
h_order_term = order_term.func(
h_order_expr, *order_term.variables)
parts.append(coeff*(h + h_order_term))
continue

# NOTE: if there is O(x**n) and we fail to integrate then there is
# no point in trying other methods because they will fail anyway.
return None

#               c
# g(x) = (a*x+b)
if g.is_Pow and not g.exp.has(x) and not meijerg:
a = Wild('a', exclude=[x])
b = Wild('b', exclude=[x])

M = g.base.match(a*x + b)

if M is not None:
if g.exp == -1:
h = log(g.base)
elif conds != 'piecewise':
h = g.base**(g.exp + 1) / (g.exp + 1)
else:
h1 = log(g.base)
h2 = g.base**(g.exp + 1) / (g.exp + 1)
h = Piecewise((h1, Eq(g.exp, -1)), (h2, True))

parts.append(coeff * h / M[a])
continue

#        poly(x)
# g(x) = -------
#        poly(x)
if g.is_rational_function(x) and not meijerg:
parts.append(coeff * ratint(g, x))
continue

if not meijerg:
# g(x) = Mul(trig)
h = trigintegrate(g, x, conds=conds)
if h is not None:
parts.append(coeff * h)
continue

# g(x) has at least a DiracDelta term
h = deltaintegrate(g, x)
if h is not None:
parts.append(coeff * h)
continue

# g(x) has at least a Singularity Function term
h = singularityintegrate(g, x)
if h is not None:
parts.append(coeff * h)
continue

# Try risch again.
if risch is not False:
try:
h, i = risch_integrate(g, x, separate_integral=True, conds=conds)
except NotImplementedError:
h = None
else:
if i:
h = h + i.doit(risch=False)

parts.append(coeff*h)
continue

# fall back to heurisch
try:
if conds == 'piecewise':
h = heurisch_wrapper(g, x, hints=[])
else:
h = heurisch(g, x, hints=[])
except PolynomialError:
# XXX: this exception means there is a bug in the
# implementation of heuristic Risch integration
# algorithm.
h = None
else:
h = None

if meijerg is not False and h is None:
# rewrite using G functions
try:
h = meijerint_indefinite(g, x)
except NotImplementedError:
from sympy.integrals.meijerint import _debug
_debug('NotImplementedError from meijerint_definite')
res = None
if h is not None:
parts.append(coeff * h)
continue

if h is None and manual is not False:
try:
result = manualintegrate(g, x)
if result is not None and not isinstance(result, Integral):
if result.has(Integral):
# try to have other algorithms do the integrals
# manualintegrate can't handle
result = result.func(*[
arg.doit(manual=False) if arg.has(Integral) else arg
for arg in result.args
]).expand(multinomial=False,
log=False,
power_exp=False,
power_base=False)
if not result.has(Integral):
parts.append(coeff * result)
continue
except (ValueError, PolynomialError):
# can't handle some SymPy expressions
pass

# if we failed maybe it was because we had
# a product that could have been expanded,
# so let's try an expansion of the whole
# thing before giving up; we don't try this
# at the outset because there are things
# that cannot be solved unless they are
# NOT expanded e.g., x**x*(1+log(x)). There
# should probably be a checker somewhere in this
# routine to look for such cases and try to do
# collection on the expressions if they are already
# in an expanded form
if not h and len(args) == 1:
f = f.expand(mul=True, deep=False)
# Note: risch will be identical on the expanded
# expression, but maybe it will be able to pick out parts,
# like x*(exp(x) + erf(x)).
return self._eval_integral(f, x, meijerg=meijerg, risch=risch, conds=conds)

if h is not None:
parts.append(coeff * h)
else:
return None

def _eval_lseries(self, x, logx):
expr = self.as_dummy()
symb = x
for l in expr.limits:
if x in l[1:]:
symb = l[0]
break
for term in expr.function.lseries(symb, logx):
yield integrate(term, *expr.limits)

def _eval_nseries(self, x, n, logx):
expr = self.as_dummy()
symb = x
for l in expr.limits:
if x in l[1:]:
symb = l[0]
break
terms, order = expr.function.nseries(
order = [o.subs(symb, x) for o in order]

series_gen = self.args[0].lseries(x)
break

[docs]    def as_sum(self, n, method="midpoint"):
"""
Approximates the definite integral by a sum.

method ... one of: left, right, midpoint, trapezoid

These are all basically the rectangle method [1], the only difference
is where the function value is taken in each interval to define the
rectangle.

[1] http://en.wikipedia.org/wiki/Rectangle_method

Examples
========

>>> from sympy import sin, sqrt
>>> from sympy.abc import x
>>> from sympy.integrals import Integral
>>> e = Integral(sin(x), (x, 3, 7))
>>> e
Integral(sin(x), (x, 3, 7))

For demonstration purposes, this interval will only be split into 2
regions, bounded by [3, 5] and [5, 7].

The left-hand rule uses function evaluations at the left of each
interval:

>>> e.as_sum(2, 'left')
2*sin(5) + 2*sin(3)

The midpoint rule uses evaluations at the center of each interval:

>>> e.as_sum(2, 'midpoint')
2*sin(4) + 2*sin(6)

The right-hand rule uses function evaluations at the right of each
interval:

>>> e.as_sum(2, 'right')
2*sin(5) + 2*sin(7)

The trapezoid rule uses function evaluations on both sides of the
intervals. This is equivalent to taking the average of the left and
right hand rule results:

>>> e.as_sum(2, 'trapezoid')
2*sin(5) + sin(3) + sin(7)
>>> (e.as_sum(2, 'left') + e.as_sum(2, 'right'))/2 == _
True

All but the trapexoid method may be used when dealing with a function
with a discontinuity. Here, the discontinuity at x = 0 can be avoided
by using the midpoint or right-hand method:

>>> e = Integral(1/sqrt(x), (x, 0, 1))
>>> e.as_sum(5).n(4)
1.730
>>> e.as_sum(10).n(4)
1.809
>>> e.doit().n(4)  # the actual value is 2
2.000

The left- or trapezoid method will encounter the discontinuity and
return oo:

>>> e.as_sum(5, 'left')
oo
>>> e.as_sum(5, 'trapezoid')
oo

========

Integral.doit : Perform the integration using any hints
"""

limits = self.limits
if len(limits) > 1:
raise NotImplementedError(
"Multidimensional midpoint rule not implemented yet")
else:
limit = limits[0]
if len(limit) != 3:
raise ValueError("Expecting a definite integral.")
if n <= 0:
raise ValueError("n must be > 0")
if n == oo:
raise NotImplementedError("Infinite summation not yet implemented")
sym, lower_limit, upper_limit = limit
dx = (upper_limit - lower_limit)/n

if method == 'trapezoid':
l = self.function.limit(sym, lower_limit)
r = self.function.limit(sym, upper_limit, "-")
result = (l + r)/2
for i in range(1, n):
x = lower_limit + i*dx
result += self.function.subs(sym, x)
return result*dx
elif method not in ('left', 'right', 'midpoint'):
raise NotImplementedError("Unknown method %s" % method)

result = 0
for i in range(n):
if method == "midpoint":
xi = lower_limit + i*dx + dx/2
elif method == "left":
xi = lower_limit + i*dx
if i == 0:
result = self.function.limit(sym, lower_limit)
continue
elif method == "right":
xi = lower_limit + i*dx + dx
if i == n:
result += self.function.limit(sym, upper_limit, "-")
continue
result += self.function.subs(sym, xi)
return result*dx

def _sage_(self):
import sage.all as sage
f, limits = self.function._sage_(), list(self.limits)
for limit in limits:
if len(limit) == 1:
x = limit[0]
f = sage.integral(f,
x._sage_(),
hold=True)
elif len(limit) == 2:
x, b = limit
f = sage.integral(f,
x._sage_(),
b._sage_(),
hold=True)
else:
x, a, b = limit
f = sage.integral(f,
(x._sage_(),
a._sage_(),
b._sage_()),
hold=True)
return f

[docs]def integrate(*args, **kwargs):
"""integrate(f, var, ...)

Compute definite or indefinite integral of one or more variables
using Risch-Norman algorithm and table lookup. This procedure is
able to handle elementary algebraic and transcendental functions
and also a huge class of special functions, including Airy,
Bessel, Whittaker and Lambert.

var can be:

- a symbol                   -- indefinite integration
- a tuple (symbol, a)        -- indefinite integration with result
given with a replacing symbol
- a tuple (symbol, a, b)     -- definite integration

Several variables can be specified, in which case the result is
multiple integration. (If var is omitted and the integrand is
univariate, the indefinite integral in that variable will be performed.)

Indefinite integrals are returned without terms that are independent
of the integration variables. (see examples)

Definite improper integrals often entail delicate convergence
conditions. Pass conds='piecewise', 'separate' or 'none' to have
these returned, respectively, as a Piecewise function, as a separate
result (i.e. result will be a tuple), or not at all (default is
'piecewise').

**Strategy**

SymPy uses various approaches to definite integration. One method is to
find an antiderivative for the integrand, and then use the fundamental
theorem of calculus. Various functions are implemented to integrate
polynomial, rational and trigonometric functions, and integrands
containing DiracDelta terms.

SymPy also implements the part of the Risch algorithm, which is a decision
procedure for integrating elementary functions, i.e., the algorithm can
either find an elementary antiderivative, or prove that one does not
exist.  There is also a (very successful, albeit somewhat slow) general
implementation of the heuristic Risch algorithm.  This algorithm will
eventually be phased out as more of the full Risch algorithm is
implemented. See the docstring of Integral._eval_integral() for more
details on computing the antiderivative using algebraic methods.

The option risch=True can be used to use only the (full) Risch algorithm.
This is useful if you want to know if an elementary function has an
elementary antiderivative.  If the indefinite Integral returned by this
function is an instance of NonElementaryIntegral, that means that the
Risch algorithm has proven that integral to be non-elementary.  Note that
by default, additional methods (such as the Meijer G method outlined
below) are tried on these integrals, as they may be expressible in terms
of special functions, so if you only care about elementary answers, use
risch=True.  Also note that an unevaluated Integral returned by this
function is not necessarily a NonElementaryIntegral, even with risch=True,
as it may just be an indication that the particular part of the Risch
algorithm needed to integrate that function is not yet implemented.

Another family of strategies comes from re-writing the integrand in
terms of so-called Meijer G-functions. Indefinite integrals of a
single G-function can always be computed, and the definite integral
of a product of two G-functions can be computed from zero to
infinity. Various strategies are implemented to rewrite integrands
as G-functions, and use this information to compute integrals (see
the meijerint module).

The option manual=True can be used to use only an algorithm that tries
to mimic integration by hand. This algorithm does not handle as many
integrands as the other algorithms implemented but may return results in
a more familiar form. The manualintegrate module has functions that

In general, the algebraic methods work best for computing
antiderivatives of (possibly complicated) combinations of elementary
functions. The G-function methods work best for computing definite
integrals from zero to infinity of moderately complicated
combinations of special functions, or indefinite integrals of very
simple combinations of special functions.

The strategy employed by the integration code is as follows:

- If computing a definite integral, and both limits are real,
and at least one limit is +- oo, try the G-function method of
definite integration first.

- Try to find an antiderivative, using all available methods, ordered
by performance (that is try fastest method first, slowest last; in
particular polynomial integration is tried first, Meijer
G-functions second to last, and heuristic Risch last).

- If still not successful, try G-functions irrespective of the
limits.

The option meijerg=True, False, None can be used to, respectively:
always use G-function methods and no others, never use G-function
methods, or use all available methods (in order as described above).
It defaults to None.

Examples
========

>>> from sympy import integrate, log, exp, oo
>>> from sympy.abc import a, x, y

>>> integrate(x*y, x)
x**2*y/2

>>> integrate(log(x), x)
x*log(x) - x

>>> integrate(log(x), (x, 1, a))
a*log(a) - a + 1

>>> integrate(x)
x**2/2

Terms that are independent of x are dropped by indefinite integration:

>>> from sympy import sqrt
>>> integrate(sqrt(1 + x), (x, 0, x))
2*(x + 1)**(3/2)/3 - 2/3
>>> integrate(sqrt(1 + x), x)
2*(x + 1)**(3/2)/3

>>> integrate(x*y)
Traceback (most recent call last):
...
ValueError: specify integration variables to integrate x*y

Note that integrate(x) syntax is meant only for convenience
in interactive sessions and should be avoided in library code.

>>> integrate(x**a*exp(-x), (x, 0, oo)) # same as conds='piecewise'
Piecewise((gamma(a + 1), -re(a) < 1),
(Integral(x**a*exp(-x), (x, 0, oo)), True))

>>> integrate(x**a*exp(-x), (x, 0, oo), conds='none')
gamma(a + 1)

>>> integrate(x**a*exp(-x), (x, 0, oo), conds='separate')
(gamma(a + 1), -re(a) < 1)

========

Integral, Integral.doit

"""
meijerg = kwargs.pop('meijerg', None)
conds = kwargs.pop('conds', 'piecewise')
risch = kwargs.pop('risch', None)
manual = kwargs.pop('manual', None)
integral = Integral(*args, **kwargs)

if isinstance(integral, Integral):
return integral.doit(deep=False, meijerg=meijerg, conds=conds,
risch=risch, manual=manual)
else:
return integral

[docs]def line_integrate(field, curve, vars):
"""line_integrate(field, Curve, variables)

Compute the line integral.

Examples
========

>>> from sympy import Curve, line_integrate, E, ln
>>> from sympy.abc import x, y, t
>>> C = Curve([E**t + 1, E**t - 1], (t, 0, ln(2)))
>>> line_integrate(x + y, C, [x, y])
3*sqrt(2)

========

integrate, Integral
"""
from sympy.geometry import Curve
F = sympify(field)
if not F:
raise ValueError(
"Expecting function specifying field as first argument.")
if not isinstance(curve, Curve):
raise ValueError("Expecting Curve entity as second argument.")
if not is_sequence(vars):
raise ValueError("Expecting ordered iterable for variables.")
if len(curve.functions) != len(vars):
raise ValueError("Field variable size does not match curve dimension.")

if curve.parameter in vars:
raise ValueError("Curve parameter clashes with field parameters.")

# Calculate derivatives for line parameter functions
# F(r) -> F(r(t)) and finally F(r(t)*r'(t))
Ft = F
dldt = 0
for i, var in enumerate(vars):
_f = curve.functions[i]
_dn = diff(_f, curve.parameter)
# ...arc length
dldt = dldt + (_dn * _dn)
Ft = Ft.subs(var, _f)
Ft = Ft * sqrt(dldt)

integral = Integral(Ft, curve.limits).doit(deep=False)
return integral