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Refine¶

sympy.assumptions.refine.refine(expr, assumptions=True)[source]

Simplify an expression using assumptions.

Gives the form of expr that would be obtained if symbols in it were replaced by explicit numerical expressions satisfying the assumptions.

Examples

>>> from sympy import refine, sqrt, Q
>>> from sympy.abc import x
>>> refine(sqrt(x**2), Q.real(x))
Abs(x)
>>> refine(sqrt(x**2), Q.positive(x))
x

sympy.assumptions.refine.refine_Pow(expr, assumptions)[source]

Handler for instances of Pow.

>>> from sympy import Symbol, Q
>>> from sympy.assumptions.refine import refine_Pow
>>> from sympy.abc import x,y,z
>>> refine_Pow((-1)**x, Q.real(x))
>>> refine_Pow((-1)**x, Q.even(x))
1
>>> refine_Pow((-1)**x, Q.odd(x))
-1


For powers of -1, even parts of the exponent can be simplified:

>>> refine_Pow((-1)**(x+y), Q.even(x))
(-1)**y
>>> refine_Pow((-1)**(x+y+z), Q.odd(x) & Q.odd(z))
(-1)**y
>>> refine_Pow((-1)**(x+y+2), Q.odd(x))
(-1)**(y + 1)
>>> refine_Pow((-1)**(x+3), True)
(-1)**(x + 1)

sympy.assumptions.refine.refine_abs(expr, assumptions)[source]

Handler for the absolute value.

Examples

>>> from sympy import Symbol, Q, refine, Abs
>>> from sympy.assumptions.refine import refine_abs
>>> from sympy.abc import x
>>> refine_abs(Abs(x), Q.real(x))
>>> refine_abs(Abs(x), Q.positive(x))
x
>>> refine_abs(Abs(x), Q.negative(x))
-x

sympy.assumptions.refine.refine_exp(expr, assumptions)[source]

Handler for exponential function.

>>> from sympy import Symbol, Q, exp, I, pi
>>> from sympy.assumptions.refine import refine_exp
>>> from sympy.abc import x
>>> refine_exp(exp(pi*I*2*x), Q.real(x))
>>> refine_exp(exp(pi*I*2*x), Q.integer(x))
1


Assume

Handlers