Source code for sympy.utilities.pkgdata

pkgdata is a simple, extensible way for a package to acquire data file

The getResource function is equivalent to the standard idioms, such as
the following minimal implementation::

    import sys, os

    def getResource(identifier, pkgname=__name__):
        pkgpath = os.path.dirname(sys.modules[pkgname].__file__)
        path = os.path.join(pkgpath, identifier)
        return open(os.path.normpath(path), mode='rb')

When a __loader__ is present on the module given by __name__, it will defer
getResource to its get_data implementation and return it as a file-like
object (such as StringIO).

from __future__ import print_function, division

import sys
import os
from sympy.core.compatibility import cStringIO as StringIO

[docs]def get_resource(identifier, pkgname=__name__): """ Acquire a readable object for a given package name and identifier. An IOError will be raised if the resource can not be found. For example:: mydata = get_esource('mypkgdata.jpg').read() Note that the package name must be fully qualified, if given, such that it would be found in sys.modules. In some cases, getResource will return a real file object. In that case, it may be useful to use its name attribute to get the path rather than use it as a file-like object. For example, you may be handing data off to a C API. """ mod = sys.modules[pkgname] fn = getattr(mod, '__file__', None) if fn is None: raise IOError("%r has no __file__!") path = os.path.join(os.path.dirname(fn), identifier) loader = getattr(mod, '__loader__', None) if loader is not None: try: data = loader.get_data(path) except (IOError,AttributeError): pass else: return StringIO(data) return open(os.path.normpath(path), 'rb')