Plane

class sympy.geometry.plane.Plane(p1, a=None, b=None, **kwargs)

A plane is a flat, two-dimensional surface. A plane is the two-dimensional analogue of a point (zero-dimensions), a line (one-dimension) and a solid (three-dimensions). A plane can generally be constructed by two types of inputs. They are: - three non-collinear points - a point and the plane’s normal vector

Examples

>>> from sympy import Plane, Point3D
>>> Plane(Point3D(1, 1, 1), Point3D(2, 3, 4), Point3D(2, 2, 2))
Plane(Point3D(1, 1, 1), (-1, 2, -1))
>>> Plane((1, 1, 1), (2, 3, 4), (2, 2, 2))
Plane(Point3D(1, 1, 1), (-1, 2, -1))
>>> Plane(Point3D(1, 1, 1), normal_vector=(1,4,7))
Plane(Point3D(1, 1, 1), (1, 4, 7))

Attributes

p1
normal_vector

angle_between(o)

Angle between the plane and other geometric entity.

Parameters:

LinearEntity3D, Plane.

Returns:

angle : angle in radians

Notes

This method accepts only 3D entities as it’s parameter, but if you want to calculate the angle between a 2D entity and a plane you should first convert to a 3D entity by projecting onto a desired plane and then proceed to calculate the angle.

Examples

>>> from sympy import Point3D, Line3D, Plane
>>> a = Plane(Point3D(1, 2, 2), normal_vector=(1, 2, 3))
>>> b = Line3D(Point3D(1, 3, 4), Point3D(2, 2, 2))
>>> a.angle_between(b)
-asin(sqrt(21)/6)

arbitrary_point(u=None, v=None)

Returns an arbitrary point on the Plane. If given two parameters, the point ranges over the entire plane. If given 1 or no parameters, returns a point with one parameter which, when varying from 0 to 2*pi, moves the point in a circle of radius 1 about p1 of the Plane.

Returns:

Point3D

Examples

>>> from sympy import Plane, Ray
>>> from sympy.abc import u, v, t, r
>>> p = Plane((1, 1, 1), normal_vector=(1, 0, 0))
>>> p.arbitrary_point(u, v)
Point3D(1, u + 1, v + 1)
>>> p.arbitrary_point(t)
Point3D(1, cos(t) + 1, sin(t) + 1)

While arbitrary values of u and v can move the point anywhere in the plane, the single-parameter point can be used to construct a ray whose arbitrary point can be located at angle t and radius r from p.p1:

>>> Ray(p.p1, _).arbitrary_point(r)
Point3D(1, r*cos(t) + 1, r*sin(t) + 1)

static are_concurrent(*planes)

Is a sequence of Planes concurrent?

Two or more Planes are concurrent if their intersections are a common line.

Parameters:

planes: list

Returns:

Boolean

Examples

>>> from sympy import Plane, Point3D
>>> a = Plane(Point3D(5, 0, 0), normal_vector=(1, -1, 1))
>>> b = Plane(Point3D(0, -2, 0), normal_vector=(3, 1, 1))
>>> c = Plane(Point3D(0, -1, 0), normal_vector=(5, -1, 9))
>>> Plane.are_concurrent(a, b)
True
>>> Plane.are_concurrent(a, b, c)
False

distance(o)

Distance between the plane and another geometric entity.

Parameters:

Point3D, LinearEntity3D, Plane.

Returns:

distance

Notes

This method accepts only 3D entities as it’s parameter, but if you want to calculate the distance between a 2D entity and a plane you should first convert to a 3D entity by projecting onto a desired plane and then proceed to calculate the distance.

Examples

>>> from sympy import Point3D, Line3D, Plane
>>> a = Plane(Point3D(1, 1, 1), normal_vector=(1, 1, 1))
>>> b = Point3D(1, 2, 3)
>>> a.distance(b)
sqrt(3)
>>> c = Line3D(Point3D(2, 3, 1), Point3D(1, 2, 2))
>>> a.distance(c)
0

equals(o)

Returns True if self and o are the same mathematical entities.

Examples

>>> from sympy import Plane, Point3D
>>> a = Plane(Point3D(1, 2, 3), normal_vector=(1, 1, 1))
>>> b = Plane(Point3D(1, 2, 3), normal_vector=(2, 2, 2))
>>> c = Plane(Point3D(1, 2, 3), normal_vector=(-1, 4, 6))
>>> a.equals(a)
True
>>> a.equals(b)
True
>>> a.equals(c)
False

equation(x=None, y=None, z=None)

The equation of the Plane.

Examples

>>> from sympy import Point3D, Plane
>>> a = Plane(Point3D(1, 1, 2), Point3D(2, 4, 7), Point3D(3, 5, 1))
>>> a.equation()
-23*x + 11*y - 2*z + 16
>>> a = Plane(Point3D(1, 4, 2), normal_vector=(6, 6, 6))
>>> a.equation()
6*x + 6*y + 6*z - 42

intersection(o)

The intersection with other geometrical entity.

Parameters:

Point, Point3D, LinearEntity, LinearEntity3D, Plane

Returns:

List

Examples

>>> from sympy import Point3D, Line3D, Plane
>>> a = Plane(Point3D(1, 2, 3), normal_vector=(1, 1, 1))
>>> b = Point3D(1, 2, 3)
>>> a.intersection(b)
[Point3D(1, 2, 3)]
>>> c = Line3D(Point3D(1, 4, 7), Point3D(2, 2, 2))
>>> a.intersection(c)
[Point3D(2, 2, 2)]
>>> d = Plane(Point3D(6, 0, 0), normal_vector=(2, -5, 3))
>>> e = Plane(Point3D(2, 0, 0), normal_vector=(3, 4, -3))
>>> d.intersection(e)
[Line3D(Point3D(78/23, -24/23, 0), Point3D(147/23, 321/23, 23))]

is_coplanar(o)

Returns True if \(o\) is coplanar with self, else False.

Examples

>>> from sympy import Plane
>>> o = (0, 0, 0)
>>> p = Plane(o, (1, 1, 1))
>>> p2 = Plane(o, (2, 2, 2))
>>> p == p2
False
>>> p.is_coplanar(p2)
True

is_parallel(l)

Is the given geometric entity parallel to the plane?

Parameters:

LinearEntity3D or Plane

Returns:

Boolean

Examples

>>> from sympy import Plane, Point3D
>>> a = Plane(Point3D(1,4,6), normal_vector=(2, 4, 6))
>>> b = Plane(Point3D(3,1,3), normal_vector=(4, 8, 12))
>>> a.is_parallel(b)
True

is_perpendicular(l)

Is the given geometric entity perpendicualar to the given plane?

Parameters:

LinearEntity3D or Plane

Returns:

Boolean

Examples

>>> from sympy import Plane, Point3D
>>> a = Plane(Point3D(1,4,6), normal_vector=(2, 4, 6))
>>> b = Plane(Point3D(2, 2, 2), normal_vector=(-1, 2, -1))
>>> a.is_perpendicular(b)
True

property normal_vector

Normal vector of the given plane.

Examples

>>> from sympy import Point3D, Plane
>>> a = Plane(Point3D(1, 1, 1), Point3D(2, 3, 4), Point3D(2, 2, 2))
>>> a.normal_vector
(-1, 2, -1)
>>> a = Plane(Point3D(1, 1, 1), normal_vector=(1, 4, 7))
>>> a.normal_vector
(1, 4, 7)

property p1

The only defining point of the plane. Others can be obtained from the arbitrary_point method.

Examples

>>> from sympy import Point3D, Plane
>>> a = Plane(Point3D(1, 1, 1), Point3D(2, 3, 4), Point3D(2, 2, 2))
>>> a.p1
Point3D(1, 1, 1)

See also

sympy.geometry.point.Point3D

parallel_plane(pt)

Plane parallel to the given plane and passing through the point pt.

Parameters:

pt: Point3D

Returns:

Plane

Examples

>>> from sympy import Plane, Point3D
>>> a = Plane(Point3D(1, 4, 6), normal_vector=(2, 4, 6))
>>> a.parallel_plane(Point3D(2, 3, 5))
Plane(Point3D(2, 3, 5), (2, 4, 6))

parameter_value(other, u, v=None)

Return the parameter(s) corresponding to the given point.

Examples

>>> from sympy import pi, Plane
>>> from sympy.abc import t, u, v
>>> p = Plane((2, 0, 0), (0, 0, 1), (0, 1, 0))

By default, the parameter value returned defines a point that is a distance of 1 from the Plane’s p1 value and in line with the given point:

>>> on_circle = p.arbitrary_point(t).subs(t, pi/4)
>>> on_circle.distance(p.p1)
1
>>> p.parameter_value(on_circle, t)
{t: pi/4}

Moving the point twice as far from p1 does not change the parameter value:

>>> off_circle = p.p1 + (on_circle - p.p1)*2
>>> off_circle.distance(p.p1)
2
>>> p.parameter_value(off_circle, t)
{t: pi/4}

If the 2-value parameter is desired, supply the two parameter symbols and a replacement dictionary will be returned:

>>> p.parameter_value(on_circle, u, v)
{u: sqrt(10)/10, v: sqrt(10)/30}
>>> p.parameter_value(off_circle, u, v)
{u: sqrt(10)/5, v: sqrt(10)/15}

perpendicular_line(pt)

A line perpendicular to the given plane.

Parameters:

pt: Point3D

Returns:

Line3D

Examples

>>> from sympy import Plane, Point3D
>>> a = Plane(Point3D(1,4,6), normal_vector=(2, 4, 6))
>>> a.perpendicular_line(Point3D(9, 8, 7))
Line3D(Point3D(9, 8, 7), Point3D(11, 12, 13))

perpendicular_plane(*pts)

Return a perpendicular passing through the given points. If the direction ratio between the points is the same as the Plane’s normal vector then, to select from the infinite number of possible planes, a third point will be chosen on the z-axis (or the y-axis if the normal vector is already parallel to the z-axis). If less than two points are given they will be supplied as follows: if no point is given then pt1 will be self.p1; if a second point is not given it will be a point through pt1 on a line parallel to the z-axis (if the normal is not already the z-axis, otherwise on the line parallel to the y-axis).

Parameters:

pts: 0, 1 or 2 Point3D

Returns:

Plane

Examples

>>> from sympy import Plane, Point3D
>>> a, b = Point3D(0, 0, 0), Point3D(0, 1, 0)
>>> Z = (0, 0, 1)
>>> p = Plane(a, normal_vector=Z)
>>> p.perpendicular_plane(a, b)
Plane(Point3D(0, 0, 0), (1, 0, 0))

projection(pt)

Project the given point onto the plane along the plane normal.

Parameters:

Point or Point3D

Returns:

Point3D

Examples

>>> from sympy import Plane, Point3D
>>> A = Plane(Point3D(1, 1, 2), normal_vector=(1, 1, 1))

The projection is along the normal vector direction, not the z axis, so (1, 1) does not project to (1, 1, 2) on the plane A:

>>> b = Point3D(1, 1)
>>> A.projection(b)
Point3D(5/3, 5/3, 2/3)
>>> _ in A
True

But the point (1, 1, 2) projects to (1, 1) on the XY-plane:

>>> XY = Plane((0, 0, 0), (0, 0, 1))
>>> XY.projection((1, 1, 2))
Point3D(1, 1, 0)

projection_line(line)

Project the given line onto the plane through the normal plane containing the line.

Parameters:

LinearEntity or LinearEntity3D

Returns:

Point3D, Line3D, Ray3D or Segment3D

Notes

For the interaction between 2D and 3D lines(segments, rays), you should convert the line to 3D by using this method. For example for finding the intersection between a 2D and a 3D line, convert the 2D line to a 3D line by projecting it on a required plane and then proceed to find the intersection between those lines.

Examples

>>> from sympy import Plane, Line, Line3D, Point3D
>>> a = Plane(Point3D(1, 1, 1), normal_vector=(1, 1, 1))
>>> b = Line(Point3D(1, 1), Point3D(2, 2))
>>> a.projection_line(b)
Line3D(Point3D(4/3, 4/3, 1/3), Point3D(5/3, 5/3, -1/3))
>>> c = Line3D(Point3D(1, 1, 1), Point3D(2, 2, 2))
>>> a.projection_line(c)
Point3D(1, 1, 1)

random_point(seed=None)

Returns a random point on the Plane.

Returns:

Point3D

Examples

>>> from sympy import Plane
>>> p = Plane((1, 0, 0), normal_vector=(0, 1, 0))
>>> r = p.random_point(seed=42)  # seed value is optional
>>> r.n(3)
Point3D(2.29, 0, -1.35)

The random point can be moved to lie on the circle of radius 1 centered on p1:

>>> c = p.p1 + (r - p.p1).unit
>>> c.distance(p.p1).equals(1)
True