Utils

sympy.geometry.util.intersection(*entities, **kwargs)[source]

The intersection of a collection of GeometryEntity instances.

Parameters

entities : sequence of GeometryEntity

pairwise (keyword argument) : Can be either True or False

Returns

intersection : list of GeometryEntity

Raises

NotImplementedError

When unable to calculate intersection.

Notes

The intersection of any geometrical entity with itself should return a list with one item: the entity in question. An intersection requires two or more entities. If only a single entity is given then the function will return an empty list. It is possible for \(intersection\) to miss intersections that one knows exists because the required quantities were not fully simplified internally. Reals should be converted to Rationals, e.g. Rational(str(real_num)) or else failures due to floating point issues may result.

Case 1: When the keyword argument ‘pairwise’ is False (default value): In this case, the function returns a list of intersections common to all entities.

Case 2: When the keyword argument ‘pairwise’ is True: In this case, the functions returns a list intersections that occur between any pair of entities.

Examples

>>> from sympy.geometry import Ray, Circle, intersection
>>> c = Circle((0, 1), 1)
>>> intersection(c, c.center)
[]
>>> right = Ray((0, 0), (1, 0))
>>> up = Ray((0, 0), (0, 1))
>>> intersection(c, right, up)
[Point2D(0, 0)]
>>> intersection(c, right, up, pairwise=True)
[Point2D(0, 0), Point2D(0, 2)]
>>> left = Ray((1, 0), (0, 0))
>>> intersection(right, left)
[Segment2D(Point2D(0, 0), Point2D(1, 0))]
sympy.geometry.util.convex_hull(*args, polygon=True)[source]

The convex hull surrounding the Points contained in the list of entities.

Parameters

args : a collection of Points, Segments and/or Polygons

Returns

convex_hull : Polygon if polygon is True else as a tuple \((U, L)\) where

L and U are the lower and upper hulls, respectively.

Optional Parameters

polygonBoolean. If True, returns a Polygon, if false a tuple, see below.

Default is True.

Notes

This can only be performed on a set of points whose coordinates can be ordered on the number line.

Examples

>>> from sympy.geometry import Point, convex_hull
>>> points = [(1, 1), (1, 2), (3, 1), (-5, 2), (15, 4)]
>>> convex_hull(*points)
Polygon(Point2D(-5, 2), Point2D(1, 1), Point2D(3, 1), Point2D(15, 4))
>>> convex_hull(*points, **dict(polygon=False))
([Point2D(-5, 2), Point2D(15, 4)],
 [Point2D(-5, 2), Point2D(1, 1), Point2D(3, 1), Point2D(15, 4)])

References

[1] https://en.wikipedia.org/wiki/Graham_scan

[2] Andrew’s Monotone Chain Algorithm (A.M. Andrew, “Another Efficient Algorithm for Convex Hulls in Two Dimensions”, 1979) http://geomalgorithms.com/a10-_hull-1.html

sympy.geometry.util.are_similar(e1, e2)[source]

Are two geometrical entities similar.

Can one geometrical entity be uniformly scaled to the other?

Parameters

e1 : GeometryEntity

e2 : GeometryEntity

Returns

are_similar : boolean

Raises

GeometryError

When \(e1\) and \(e2\) cannot be compared.

Notes

If the two objects are equal then they are similar.

Examples

>>> from sympy import Point, Circle, Triangle, are_similar
>>> c1, c2 = Circle(Point(0, 0), 4), Circle(Point(1, 4), 3)
>>> t1 = Triangle(Point(0, 0), Point(1, 0), Point(0, 1))
>>> t2 = Triangle(Point(0, 0), Point(2, 0), Point(0, 2))
>>> t3 = Triangle(Point(0, 0), Point(3, 0), Point(0, 1))
>>> are_similar(t1, t2)
True
>>> are_similar(t1, t3)
False
sympy.geometry.util.centroid(*args)[source]

Find the centroid (center of mass) of the collection containing only Points, Segments or Polygons. The centroid is the weighted average of the individual centroid where the weights are the lengths (of segments) or areas (of polygons). Overlapping regions will add to the weight of that region.

If there are no objects (or a mixture of objects) then None is returned.

Examples

>>> from sympy import Point, Segment, Polygon
>>> from sympy.geometry.util import centroid
>>> p = Polygon((0, 0), (10, 0), (10, 10))
>>> q = p.translate(0, 20)
>>> p.centroid, q.centroid
(Point2D(20/3, 10/3), Point2D(20/3, 70/3))
>>> centroid(p, q)
Point2D(20/3, 40/3)
>>> p, q = Segment((0, 0), (2, 0)), Segment((0, 0), (2, 2))
>>> centroid(p, q)
Point2D(1, 2 - sqrt(2))
>>> centroid(Point(0, 0), Point(2, 0))
Point2D(1, 0)

Stacking 3 polygons on top of each other effectively triples the weight of that polygon:

>>> p = Polygon((0, 0), (1, 0), (1, 1), (0, 1))
>>> q = Polygon((1, 0), (3, 0), (3, 1), (1, 1))
>>> centroid(p, q)
Point2D(3/2, 1/2)
>>> centroid(p, p, p, q) # centroid x-coord shifts left
Point2D(11/10, 1/2)

Stacking the squares vertically above and below p has the same effect:

>>> centroid(p, p.translate(0, 1), p.translate(0, -1), q)
Point2D(11/10, 1/2)
sympy.geometry.util.idiff(eq, y, x, n=1)[source]

Return dy/dx assuming that eq == 0.

Parameters

y : the dependent variable or a list of dependent variables (with y first)

x : the variable that the derivative is being taken with respect to

n : the order of the derivative (default is 1)

Examples

>>> from sympy.abc import x, y, a
>>> from sympy.geometry.util import idiff
>>> circ = x**2 + y**2 - 4
>>> idiff(circ, y, x)
-x/y
>>> idiff(circ, y, x, 2).simplify()
-(x**2 + y**2)/y**3

Here, a is assumed to be independent of x:

>>> idiff(x + a + y, y, x)
-1

Now the x-dependence of a is made explicit by listing a after y in a list.

>>> idiff(x + a + y, [y, a], x)
-Derivative(a, x) - 1

See also

sympy.core.function.Derivative

represents unevaluated derivatives

sympy.core.function.diff

explicitly differentiates wrt symbols