# Stats#

SymPy statistics module

Introduces a random variable type into the SymPy language.

Random variables may be declared using prebuilt functions such as Normal, Exponential, Coin, Die, etc… or built with functions like FiniteRV.

Queries on random expressions can be made using the functions

 Expression Meaning P(condition) Probability E(expression) Expected value H(expression) Entropy variance(expression) Variance density(expression) Probability Density Function sample(expression) Produce a realization where(condition) Where the condition is true

## Examples#

>>> from sympy.stats import P, E, variance, Die, Normal
>>> from sympy import simplify
>>> X, Y = Die('X', 6), Die('Y', 6) # Define two six sided dice
>>> Z = Normal('Z', 0, 1) # Declare a Normal random variable with mean 0, std 1
>>> P(X>3) # Probability X is greater than 3
1/2
>>> E(X+Y) # Expectation of the sum of two dice
7
>>> variance(X+Y) # Variance of the sum of two dice
35/6
>>> simplify(P(Z>1)) # Probability of Z being greater than 1
1/2 - erf(sqrt(2)/2)/2


One could also create custom distribution and define custom random variables as follows:

1. If you want to create a Continuous Random Variable:

>>> from sympy.stats import ContinuousRV, P, E
>>> from sympy import exp, Symbol, Interval, oo
>>> x = Symbol('x')
>>> pdf = exp(-x) # pdf of the Continuous Distribution
>>> Z = ContinuousRV(x, pdf, set=Interval(0, oo))
>>> E(Z)
1
>>> P(Z > 5)
exp(-5)


1.1 To create an instance of Continuous Distribution:

>>> from sympy.stats import ContinuousDistributionHandmade
>>> from sympy import Lambda
>>> dist = ContinuousDistributionHandmade(Lambda(x, pdf), set=Interval(0, oo))
>>> dist.pdf(x)
exp(-x)

1. If you want to create a Discrete Random Variable:

>>> from sympy.stats import DiscreteRV, P, E
>>> from sympy import Symbol, S
>>> p = S(1)/2
>>> x = Symbol('x', integer=True, positive=True)
>>> pdf = p*(1 - p)**(x - 1)
>>> D = DiscreteRV(x, pdf, set=S.Naturals)
>>> E(D)
2
>>> P(D > 3)
1/8


2.1 To create an instance of Discrete Distribution:

>>> from sympy.stats import DiscreteDistributionHandmade
>>> from sympy import Lambda
>>> dist = DiscreteDistributionHandmade(Lambda(x, pdf), set=S.Naturals)
>>> dist.pdf(x)
2**(1 - x)/2

1. If you want to create a Finite Random Variable:

>>> from sympy.stats import FiniteRV, P, E
>>> from sympy import Rational, Eq
>>> pmf = {1: Rational(1, 3), 2: Rational(1, 6), 3: Rational(1, 4), 4: Rational(1, 4)}
>>> X = FiniteRV('X', pmf)
>>> E(X)
29/12
>>> P(X > 3)
1/4


3.1 To create an instance of Finite Distribution:

>>> from sympy.stats import FiniteDistributionHandmade
>>> dist.pmf(x)
Lambda(x, Piecewise((1/3, Eq(x, 1)), (1/6, Eq(x, 2)), (1/4, Eq(x, 3) | Eq(x, 4)), (0, True)))


## Random Variable Types#

### Finite Types#

sympy.stats.DiscreteUniform(name, items)[source]#

Create a Finite Random Variable representing a uniform distribution over the input set.

Parameters:

items : list/tuple

Items over which Uniform distribution is to be made

Returns:

RandomSymbol

Examples

>>> from sympy.stats import DiscreteUniform, density
>>> from sympy import symbols

>>> X = DiscreteUniform('X', symbols('a b c')) # equally likely over a, b, c
>>> density(X).dict
{a: 1/3, b: 1/3, c: 1/3}

>>> Y = DiscreteUniform('Y', list(range(5))) # distribution over a range
>>> density(Y).dict
{0: 1/5, 1: 1/5, 2: 1/5, 3: 1/5, 4: 1/5}


References

sympy.stats.Die(name, sides=6)[source]#

Create a Finite Random Variable representing a fair die.

Parameters:

sides : Integer

Represents the number of sides of the Die, by default is 6

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Die, density
>>> from sympy import Symbol

>>> D6 = Die('D6', 6) # Six sided Die
>>> density(D6).dict
{1: 1/6, 2: 1/6, 3: 1/6, 4: 1/6, 5: 1/6, 6: 1/6}

>>> D4 = Die('D4', 4) # Four sided Die
>>> density(D4).dict
{1: 1/4, 2: 1/4, 3: 1/4, 4: 1/4}

>>> n = Symbol('n', positive=True, integer=True)
>>> Dn = Die('Dn', n) # n sided Die
>>> density(Dn).dict
Density(DieDistribution(n))
>>> density(Dn).dict.subs(n, 4).doit()
{1: 1/4, 2: 1/4, 3: 1/4, 4: 1/4}

sympy.stats.Bernoulli(name, p, succ=1, fail=0)[source]#

Create a Finite Random Variable representing a Bernoulli process.

Parameters:

p : Rational number between 0 and 1

Represents probability of success

succ : Integer/symbol/string

Represents event of success

fail : Integer/symbol/string

Represents event of failure

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Bernoulli, density
>>> from sympy import S

>>> X = Bernoulli('X', S(3)/4) # 1-0 Bernoulli variable, probability = 3/4
>>> density(X).dict
{0: 1/4, 1: 3/4}

>>> X = Bernoulli('X', S.Half, 'Heads', 'Tails') # A fair coin toss
>>> density(X).dict


References

sympy.stats.Coin(name, p=1 / 2)[source]#

Create a Finite Random Variable representing a Coin toss.

Parameters:

p : Rational Number between 0 and 1

Represents probability of getting “Heads”, by default is Half

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Coin, density
>>> from sympy import Rational

>>> C = Coin('C') # A fair coin toss
>>> density(C).dict
{H: 1/2, T: 1/2}

>>> C2 = Coin('C2', Rational(3, 5)) # An unfair coin
>>> density(C2).dict
{H: 3/5, T: 2/5}


References

sympy.stats.Binomial(name, n, p, succ=1, fail=0)[source]#

Create a Finite Random Variable representing a binomial distribution.

Parameters:

n : Positive Integer

Represents number of trials

p : Rational Number between 0 and 1

Represents probability of success

succ : Integer/symbol/string

Represents event of success, by default is 1

fail : Integer/symbol/string

Represents event of failure, by default is 0

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Binomial, density
>>> from sympy import S, Symbol

>>> X = Binomial('X', 4, S.Half) # Four "coin flips"
>>> density(X).dict
{0: 1/16, 1: 1/4, 2: 3/8, 3: 1/4, 4: 1/16}

>>> n = Symbol('n', positive=True, integer=True)
>>> p = Symbol('p', positive=True)
>>> X = Binomial('X', n, S.Half) # n "coin flips"
>>> density(X).dict
Density(BinomialDistribution(n, 1/2, 1, 0))
>>> density(X).dict.subs(n, 4).doit()
{0: 1/16, 1: 1/4, 2: 3/8, 3: 1/4, 4: 1/16}


References

sympy.stats.BetaBinomial(name, n, alpha, beta)[source]#

Create a Finite Random Variable representing a Beta-binomial distribution.

Parameters:

n : Positive Integer

Represents number of trials

alpha : Real positive number

beta : Real positive number

Returns:

RandomSymbol

Examples

>>> from sympy.stats import BetaBinomial, density

>>> X = BetaBinomial('X', 2, 1, 1)
>>> density(X).dict
{0: 1/3, 1: 2*beta(2, 2), 2: 1/3}


References

sympy.stats.Hypergeometric(name, N, m, n)[source]#

Create a Finite Random Variable representing a hypergeometric distribution.

Parameters:

N : Positive Integer

Represents finite population of size N.

m : Positive Integer

Represents number of trials with required feature.

n : Positive Integer

Represents numbers of draws.

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Hypergeometric, density

>>> X = Hypergeometric('X', 10, 5, 3) # 10 marbles, 5 white (success), 3 draws
>>> density(X).dict
{0: 1/12, 1: 5/12, 2: 5/12, 3: 1/12}


References

sympy.stats.FiniteRV(name, density, **kwargs)[source]#

Create a Finite Random Variable given a dict representing the density.

Parameters:

name : Symbol

Represents name of the random variable.

density : dict

Dictionary containing the pdf of finite distribution

check : bool

If True, it will check whether the given density integrates to 1 over the given set. If False, it will not perform this check. Default is False.

Returns:

RandomSymbol

Examples

>>> from sympy.stats import FiniteRV, P, E

>>> density = {0: .1, 1: .2, 2: .3, 3: .4}
>>> X = FiniteRV('X', density)

>>> E(X)
2.00000000000000
>>> P(X >= 2)
0.700000000000000


Create a Finite Random Variable representing a Rademacher distribution.

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Rademacher, density

>>> X = Rademacher('X')
>>> density(X).dict
{-1: 1/2, 1: 1/2}


References

### Discrete Types#

sympy.stats.Geometric(name, p)[source]#

Create a discrete random variable with a Geometric distribution.

Parameters:

p : A probability between 0 and 1

Returns:

RandomSymbol

Explanation

The density of the Geometric distribution is given by

$f(k) := p (1 - p)^{k - 1}$

Examples

>>> from sympy.stats import Geometric, density, E, variance
>>> from sympy import Symbol, S

>>> p = S.One / 5
>>> z = Symbol("z")

>>> X = Geometric("x", p)

>>> density(X)(z)
(5/4)**(1 - z)/5

>>> E(X)
5

>>> variance(X)
20


References

sympy.stats.Hermite(name, a1, a2)[source]#

Create a discrete random variable with a Hermite distribution.

Parameters:

a1 : A Positive number greater than equal to 0.

a2 : A Positive number greater than equal to 0.

Returns:

RandomSymbol

Explanation

The density of the Hermite distribution is given by

$f(x):= e^{-a_1 -a_2}\sum_{j=0}^{\left \lfloor x/2 \right \rfloor} \frac{a_{1}^{x-2j}a_{2}^{j}}{(x-2j)!j!}$

Examples

>>> from sympy.stats import Hermite, density, E, variance
>>> from sympy import Symbol

>>> a1 = Symbol("a1", positive=True)
>>> a2 = Symbol("a2", positive=True)
>>> x = Symbol("x")

>>> H = Hermite("H", a1=5, a2=4)

>>> density(H)(2)
33*exp(-9)/2

>>> E(H)
13

>>> variance(H)
21


References

sympy.stats.Poisson(name, lamda)[source]#

Create a discrete random variable with a Poisson distribution.

Parameters:

lamda : Positive number, a rate

Returns:

RandomSymbol

Explanation

The density of the Poisson distribution is given by

$f(k) := \frac{\lambda^{k} e^{- \lambda}}{k!}$

Examples

>>> from sympy.stats import Poisson, density, E, variance
>>> from sympy import Symbol, simplify

>>> rate = Symbol("lambda", positive=True)
>>> z = Symbol("z")

>>> X = Poisson("x", rate)

>>> density(X)(z)
lambda**z*exp(-lambda)/factorial(z)

>>> E(X)
lambda

>>> simplify(variance(X))
lambda


References

sympy.stats.Logarithmic(name, p)[source]#

Create a discrete random variable with a Logarithmic distribution.

Parameters:

p : A value between 0 and 1

Returns:

RandomSymbol

Explanation

The density of the Logarithmic distribution is given by

$f(k) := \frac{-p^k}{k \ln{(1 - p)}}$

Examples

>>> from sympy.stats import Logarithmic, density, E, variance
>>> from sympy import Symbol, S

>>> p = S.One / 5
>>> z = Symbol("z")

>>> X = Logarithmic("x", p)

>>> density(X)(z)
-1/(5**z*z*log(4/5))

>>> E(X)
-1/(-4*log(5) + 8*log(2))

>>> variance(X)
-1/((-4*log(5) + 8*log(2))*(-2*log(5) + 4*log(2))) + 1/(-64*log(2)*log(5) + 64*log(2)**2 + 16*log(5)**2) - 10/(-32*log(5) + 64*log(2))


References

sympy.stats.NegativeBinomial(name, r, p)[source]#

Create a discrete random variable with a Negative Binomial distribution.

Parameters:

r : A positive value

p : A value between 0 and 1

Returns:

RandomSymbol

Explanation

The density of the Negative Binomial distribution is given by

$f(k) := \binom{k + r - 1}{k} (1 - p)^r p^k$

Examples

>>> from sympy.stats import NegativeBinomial, density, E, variance
>>> from sympy import Symbol, S

>>> r = 5
>>> p = S.One / 5
>>> z = Symbol("z")

>>> X = NegativeBinomial("x", r, p)

>>> density(X)(z)
1024*binomial(z + 4, z)/(3125*5**z)

>>> E(X)
5/4

>>> variance(X)
25/16


References

sympy.stats.Skellam(name, mu1, mu2)[source]#

Create a discrete random variable with a Skellam distribution.

Parameters:

mu1 : A non-negative value

mu2 : A non-negative value

Returns:

RandomSymbol

Explanation

The Skellam is the distribution of the difference N1 - N2 of two statistically independent random variables N1 and N2 each Poisson-distributed with respective expected values mu1 and mu2.

The density of the Skellam distribution is given by

$f(k) := e^{-(\mu_1+\mu_2)}(\frac{\mu_1}{\mu_2})^{k/2}I_k(2\sqrt{\mu_1\mu_2})$

Examples

>>> from sympy.stats import Skellam, density, E, variance
>>> from sympy import Symbol, pprint

>>> z = Symbol("z", integer=True)
>>> mu1 = Symbol("mu1", positive=True)
>>> mu2 = Symbol("mu2", positive=True)
>>> X = Skellam("x", mu1, mu2)

>>> pprint(density(X)(z), use_unicode=False)
z
-
2
/mu1\   -mu1 - mu2        /       _____   _____\
|---| *e          *besseli\z, 2*\/ mu1 *\/ mu2 /
\mu2/
>>> E(X)
mu1 - mu2
>>> variance(X).expand()
mu1 + mu2


References

sympy.stats.YuleSimon(name, rho)[source]#

Create a discrete random variable with a Yule-Simon distribution.

Parameters:

rho : A positive value

Returns:

RandomSymbol

Explanation

The density of the Yule-Simon distribution is given by

$f(k) := \rho B(k, \rho + 1)$

Examples

>>> from sympy.stats import YuleSimon, density, E, variance
>>> from sympy import Symbol, simplify

>>> p = 5
>>> z = Symbol("z")

>>> X = YuleSimon("x", p)

>>> density(X)(z)
5*beta(z, 6)

>>> simplify(E(X))
5/4

>>> simplify(variance(X))
25/48


References

sympy.stats.Zeta(name, s)[source]#

Create a discrete random variable with a Zeta distribution.

Parameters:

s : A value greater than 1

Returns:

RandomSymbol

Explanation

The density of the Zeta distribution is given by

$f(k) := \frac{1}{k^s \zeta{(s)}}$

Examples

>>> from sympy.stats import Zeta, density, E, variance
>>> from sympy import Symbol

>>> s = 5
>>> z = Symbol("z")

>>> X = Zeta("x", s)

>>> density(X)(z)
1/(z**5*zeta(5))

>>> E(X)
pi**4/(90*zeta(5))

>>> variance(X)
-pi**8/(8100*zeta(5)**2) + zeta(3)/zeta(5)


References

### Continuous Types#

sympy.stats.Arcsin(name, a=0, b=1)[source]#

Create a Continuous Random Variable with an arcsin distribution.

The density of the arcsin distribution is given by

$f(x) := \frac{1}{\pi\sqrt{(x-a)(b-x)}}$

with $$x \in (a,b)$$. It must hold that $$-\infty < a < b < \infty$$.

Parameters:

a : Real number, the left interval boundary

b : Real number, the right interval boundary

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Arcsin, density, cdf
>>> from sympy import Symbol

>>> a = Symbol("a", real=True)
>>> b = Symbol("b", real=True)
>>> z = Symbol("z")

>>> X = Arcsin("x", a, b)

>>> density(X)(z)
1/(pi*sqrt((-a + z)*(b - z)))

>>> cdf(X)(z)
Piecewise((0, a > z),
(2*asin(sqrt((-a + z)/(-a + b)))/pi, b >= z),
(1, True))


References

sympy.stats.Benini(name, alpha, beta, sigma)[source]#

Create a Continuous Random Variable with a Benini distribution.

The density of the Benini distribution is given by

$f(x) := e^{-\alpha\log{\frac{x}{\sigma}} -\beta\log^2\left[{\frac{x}{\sigma}}\right]} \left(\frac{\alpha}{x}+\frac{2\beta\log{\frac{x}{\sigma}}}{x}\right)$

This is a heavy-tailed distribution and is also known as the log-Rayleigh distribution.

Parameters:

alpha : Real number, $$\alpha > 0$$, a shape

beta : Real number, $$\beta > 0$$, a shape

sigma : Real number, $$\sigma > 0$$, a scale

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Benini, density, cdf
>>> from sympy import Symbol, pprint

>>> alpha = Symbol("alpha", positive=True)
>>> beta = Symbol("beta", positive=True)
>>> sigma = Symbol("sigma", positive=True)
>>> z = Symbol("z")

>>> X = Benini("x", alpha, beta, sigma)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
/                  /  z  \\             /  z  \            2/  z  \
|        2*beta*log|-----||  - alpha*log|-----| - beta*log  |-----|
|alpha             \sigma/|             \sigma/             \sigma/
|----- + -----------------|*e
\  z             z        /

>>> cdf(X)(z)
Piecewise((1 - exp(-alpha*log(z/sigma) - beta*log(z/sigma)**2), sigma <= z),
(0, True))


References

sympy.stats.Beta(name, alpha, beta)[source]#

Create a Continuous Random Variable with a Beta distribution.

The density of the Beta distribution is given by

$f(x) := \frac{x^{\alpha-1}(1-x)^{\beta-1}} {\mathrm{B}(\alpha,\beta)}$

with $$x \in [0,1]$$.

Parameters:

alpha : Real number, $$\alpha > 0$$, a shape

beta : Real number, $$\beta > 0$$, a shape

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Beta, density, E, variance
>>> from sympy import Symbol, simplify, pprint, factor

>>> alpha = Symbol("alpha", positive=True)
>>> beta = Symbol("beta", positive=True)
>>> z = Symbol("z")

>>> X = Beta("x", alpha, beta)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
alpha - 1        beta - 1
z         *(1 - z)
--------------------------
B(alpha, beta)

>>> simplify(E(X))
alpha/(alpha + beta)

>>> factor(simplify(variance(X)))
alpha*beta/((alpha + beta)**2*(alpha + beta + 1))


References

sympy.stats.BetaNoncentral(name, alpha, beta, lamda)[source]#

Create a Continuous Random Variable with a Type I Noncentral Beta distribution.

The density of the Noncentral Beta distribution is given by

$f(x) := \sum_{k=0}^\infty e^{-\lambda/2}\frac{(\lambda/2)^k}{k!} \frac{x^{\alpha+k-1}(1-x)^{\beta-1}}{\mathrm{B}(\alpha+k,\beta)}$

with $$x \in [0,1]$$.

Parameters:

alpha : Real number, $$\alpha > 0$$, a shape

beta : Real number, $$\beta > 0$$, a shape

lamda : Real number, $$\lambda \geq 0$$, noncentrality parameter

Returns:

RandomSymbol

Examples

>>> from sympy.stats import BetaNoncentral, density, cdf
>>> from sympy import Symbol, pprint

>>> alpha = Symbol("alpha", positive=True)
>>> beta = Symbol("beta", positive=True)
>>> lamda = Symbol("lamda", nonnegative=True)
>>> z = Symbol("z")

>>> X = BetaNoncentral("x", alpha, beta, lamda)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
oo
_____
\
\                                              -lamda
\                          k                  -------
\    k + alpha - 1 /lamda\         beta - 1     2
)  z             *|-----| *(1 - z)        *e
/                  \  2  /
/    ------------------------------------------------
/                  B(k + alpha, beta)*k!
/____,
k = 0


Compute cdf with specific ‘x’, ‘alpha’, ‘beta’ and ‘lamda’ values as follows:

>>> cdf(BetaNoncentral("x", 1, 1, 1), evaluate=False)(2).doit()
2*exp(1/2)


The argument evaluate=False prevents an attempt at evaluation of the sum for general x, before the argument 2 is passed.

References

sympy.stats.BetaPrime(name, alpha, beta)[source]#

Create a continuous random variable with a Beta prime distribution.

The density of the Beta prime distribution is given by

$f(x) := \frac{x^{\alpha-1} (1+x)^{-\alpha -\beta}}{B(\alpha,\beta)}$

with $$x > 0$$.

Parameters:

alpha : Real number, $$\alpha > 0$$, a shape

beta : Real number, $$\beta > 0$$, a shape

Returns:

RandomSymbol

Examples

>>> from sympy.stats import BetaPrime, density
>>> from sympy import Symbol, pprint

>>> alpha = Symbol("alpha", positive=True)
>>> beta = Symbol("beta", positive=True)
>>> z = Symbol("z")

>>> X = BetaPrime("x", alpha, beta)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
alpha - 1        -alpha - beta
z         *(z + 1)
-------------------------------
B(alpha, beta)


References

sympy.stats.BoundedPareto(name, alpha, left, right)[source]#

Create a continuous random variable with a Bounded Pareto distribution.

The density of the Bounded Pareto distribution is given by

$f(x) := \frac{\alpha L^{\alpha}x^{-\alpha-1}}{1-(\frac{L}{H})^{\alpha}}$
Parameters:

alpha : Real Number, $$\alpha > 0$$

Shape parameter

left : Real Number, $$left > 0$$

Location parameter

right : Real Number, $$right > left$$

Location parameter

Returns:

RandomSymbol

Examples

>>> from sympy.stats import BoundedPareto, density, cdf, E
>>> from sympy import symbols
>>> L, H = symbols('L, H', positive=True)
>>> X = BoundedPareto('X', 2, L, H)
>>> x = symbols('x')
>>> density(X)(x)
2*L**2/(x**3*(1 - L**2/H**2))
>>> cdf(X)(x)
Piecewise((-H**2*L**2/(x**2*(H**2 - L**2)) + H**2/(H**2 - L**2), L <= x), (0, True))
>>> E(X).simplify()
2*H*L/(H + L)


References

sympy.stats.Cauchy(name, x0, gamma)[source]#

Create a continuous random variable with a Cauchy distribution.

The density of the Cauchy distribution is given by

$f(x) := \frac{1}{\pi \gamma [1 + {(\frac{x-x_0}{\gamma})}^2]}$
Parameters:

x0 : Real number, the location

gamma : Real number, $$\gamma > 0$$, a scale

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Cauchy, density
>>> from sympy import Symbol

>>> x0 = Symbol("x0")
>>> gamma = Symbol("gamma", positive=True)
>>> z = Symbol("z")

>>> X = Cauchy("x", x0, gamma)

>>> density(X)(z)
1/(pi*gamma*(1 + (-x0 + z)**2/gamma**2))


References

sympy.stats.Chi(name, k)[source]#

Create a continuous random variable with a Chi distribution.

The density of the Chi distribution is given by

$f(x) := \frac{2^{1-k/2}x^{k-1}e^{-x^2/2}}{\Gamma(k/2)}$

with $$x \geq 0$$.

Parameters:

k : Positive integer, The number of degrees of freedom

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Chi, density, E
>>> from sympy import Symbol, simplify

>>> k = Symbol("k", integer=True)
>>> z = Symbol("z")

>>> X = Chi("x", k)

>>> density(X)(z)
2**(1 - k/2)*z**(k - 1)*exp(-z**2/2)/gamma(k/2)

>>> simplify(E(X))
sqrt(2)*gamma(k/2 + 1/2)/gamma(k/2)


References

sympy.stats.ChiNoncentral(name, k, l)[source]#

Create a continuous random variable with a non-central Chi distribution.

Parameters:

k : A positive Integer, $$k > 0$$

The number of degrees of freedom.

lambda : Real number, $$\lambda > 0$$

Shift parameter.

Returns:

RandomSymbol

Explanation

The density of the non-central Chi distribution is given by

$f(x) := \frac{e^{-(x^2+\lambda^2)/2} x^k\lambda} {(\lambda x)^{k/2}} I_{k/2-1}(\lambda x)$

with $$x \geq 0$$. Here, $$I_\nu (x)$$ is the modified Bessel function of the first kind.

Examples

>>> from sympy.stats import ChiNoncentral, density
>>> from sympy import Symbol

>>> k = Symbol("k", integer=True)
>>> l = Symbol("l")
>>> z = Symbol("z")

>>> X = ChiNoncentral("x", k, l)

>>> density(X)(z)
l*z**k*exp(-l**2/2 - z**2/2)*besseli(k/2 - 1, l*z)/(l*z)**(k/2)


References

sympy.stats.ChiSquared(name, k)[source]#

Create a continuous random variable with a Chi-squared distribution.

Parameters:

k : Positive integer

The number of degrees of freedom.

Returns:

RandomSymbol

Explanation

The density of the Chi-squared distribution is given by

$f(x) := \frac{1}{2^{\frac{k}{2}}\Gamma\left(\frac{k}{2}\right)} x^{\frac{k}{2}-1} e^{-\frac{x}{2}}$

with $$x \geq 0$$.

Examples

>>> from sympy.stats import ChiSquared, density, E, variance, moment
>>> from sympy import Symbol

>>> k = Symbol("k", integer=True, positive=True)
>>> z = Symbol("z")

>>> X = ChiSquared("x", k)

>>> density(X)(z)
z**(k/2 - 1)*exp(-z/2)/(2**(k/2)*gamma(k/2))

>>> E(X)
k

>>> variance(X)
2*k

>>> moment(X, 3)
k**3 + 6*k**2 + 8*k


References

sympy.stats.Dagum(name, p, a, b)[source]#

Create a continuous random variable with a Dagum distribution.

Parameters:

p : Real number

$$p > 0$$, a shape.

a : Real number

$$a > 0$$, a shape.

b : Real number

$$b > 0$$, a scale.

Returns:

RandomSymbol

Explanation

The density of the Dagum distribution is given by

$f(x) := \frac{a p}{x} \left( \frac{\left(\tfrac{x}{b}\right)^{a p}} {\left(\left(\tfrac{x}{b}\right)^a + 1 \right)^{p+1}} \right)$

with $$x > 0$$.

Examples

>>> from sympy.stats import Dagum, density, cdf
>>> from sympy import Symbol

>>> p = Symbol("p", positive=True)
>>> a = Symbol("a", positive=True)
>>> b = Symbol("b", positive=True)
>>> z = Symbol("z")

>>> X = Dagum("x", p, a, b)

>>> density(X)(z)
a*p*(z/b)**(a*p)*((z/b)**a + 1)**(-p - 1)/z

>>> cdf(X)(z)
Piecewise(((1 + (z/b)**(-a))**(-p), z >= 0), (0, True))


References

sympy.stats.Davis(name, b, n, mu)[source]#

Create a continuous random variable with Davis distribution.

Parameters:

b : Real number

$$p > 0$$, a scale.

n : Real number

$$n > 1$$, a shape.

mu : Real number

$$mu > 0$$, a location.

Returns:

RandomSymbol

Explanation

The density of Davis distribution is given by

$f(x; \mu; b, n) := \frac{b^{n}(x - \mu)^{1-n}}{ \left( e^{\frac{b}{x-\mu}} - 1 \right) \Gamma(n)\zeta(n)}$

with $$x \in [0,\infty]$$.

Davis distribution is a generalization of the Planck’s law of radiation from statistical physics. It is used for modeling income distribution.

Examples

>>> from sympy.stats import Davis, density
>>> from sympy import Symbol
>>> b = Symbol("b", positive=True)
>>> n = Symbol("n", positive=True)
>>> mu = Symbol("mu", positive=True)
>>> z = Symbol("z")
>>> X = Davis("x", b, n, mu)
>>> density(X)(z)
b**n*(-mu + z)**(-n - 1)/((exp(b/(-mu + z)) - 1)*gamma(n)*zeta(n))


References

sympy.stats.Erlang(name, k, l)[source]#

Create a continuous random variable with an Erlang distribution.

Parameters:

k : Positive integer

l : Real number, $$\lambda > 0$$, the rate

Returns:

RandomSymbol

Explanation

The density of the Erlang distribution is given by

$f(x) := \frac{\lambda^k x^{k-1} e^{-\lambda x}}{(k-1)!}$

with $$x \in [0,\infty]$$.

Examples

>>> from sympy.stats import Erlang, density, cdf, E, variance
>>> from sympy import Symbol, simplify, pprint

>>> k = Symbol("k", integer=True, positive=True)
>>> l = Symbol("l", positive=True)
>>> z = Symbol("z")

>>> X = Erlang("x", k, l)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
k  k - 1  -l*z
l *z     *e
---------------
Gamma(k)

>>> C = cdf(X)(z)
>>> pprint(C, use_unicode=False)
/lowergamma(k, l*z)
|------------------  for z > 0
<     Gamma(k)
|
\        0           otherwise

>>> E(X)
k/l

>>> simplify(variance(X))
k/l**2


References

sympy.stats.ExGaussian(name, mean, std, rate)[source]#

Create a continuous random variable with an Exponentially modified Gaussian (EMG) distribution.

Parameters:

name : A string giving a name for this distribution

mean : A Real number, the mean of Gaussian component

std : A positive Real number,

math:

$$\sigma^2 > 0$$ the variance of Gaussian component

rate : A positive Real number,

math:

$$\lambda > 0$$ the rate of Exponential component

Returns:

RandomSymbol

Explanation

The density of the exponentially modified Gaussian distribution is given by

$f(x) := \frac{\lambda}{2}e^{\frac{\lambda}{2}(2\mu+\lambda\sigma^2-2x)} \text{erfc}(\frac{\mu + \lambda\sigma^2 - x}{\sqrt{2}\sigma})$

with $$x > 0$$. Note that the expected value is $$1/\lambda$$.

Examples

>>> from sympy.stats import ExGaussian, density, cdf, E
>>> from sympy.stats import variance, skewness
>>> from sympy import Symbol, pprint, simplify

>>> mean = Symbol("mu")
>>> std = Symbol("sigma", positive=True)
>>> rate = Symbol("lamda", positive=True)
>>> z = Symbol("z")
>>> X = ExGaussian("x", mean, std, rate)

>>> pprint(density(X)(z), use_unicode=False)
/           2             \
lamda*\lamda*sigma  + 2*mu - 2*z/
---------------------------------     /  ___ /           2         \\
2                     |\/ 2 *\lamda*sigma  + mu - z/|
lamda*e                                 *erfc|-----------------------------|
\           2*sigma           /
----------------------------------------------------------------------------
2

>>> cdf(X)(z)
-(erf(sqrt(2)*(-lamda**2*sigma**2 + lamda*(-mu + z))/(2*lamda*sigma))/2 + 1/2)*exp(lamda**2*sigma**2/2 - lamda*(-mu + z)) + erf(sqrt(2)*(-mu + z)/(2*sigma))/2 + 1/2

>>> E(X)
(lamda*mu + 1)/lamda

>>> simplify(variance(X))
sigma**2 + lamda**(-2)

>>> simplify(skewness(X))
2/(lamda**2*sigma**2 + 1)**(3/2)


References

sympy.stats.Exponential(name, rate)[source]#

Create a continuous random variable with an Exponential distribution.

Parameters:

rate : A positive Real number, $$\lambda > 0$$, the rate (or inverse scale/inverse mean)

Returns:

RandomSymbol

Explanation

The density of the exponential distribution is given by

$f(x) := \lambda \exp(-\lambda x)$

with $$x > 0$$. Note that the expected value is $$1/\lambda$$.

Examples

>>> from sympy.stats import Exponential, density, cdf, E
>>> from sympy.stats import variance, std, skewness, quantile
>>> from sympy import Symbol

>>> l = Symbol("lambda", positive=True)
>>> z = Symbol("z")
>>> p = Symbol("p")
>>> X = Exponential("x", l)

>>> density(X)(z)
lambda*exp(-lambda*z)

>>> cdf(X)(z)
Piecewise((1 - exp(-lambda*z), z >= 0), (0, True))

>>> quantile(X)(p)
-log(1 - p)/lambda

>>> E(X)
1/lambda

>>> variance(X)
lambda**(-2)

>>> skewness(X)
2

>>> X = Exponential('x', 10)

>>> density(X)(z)
10*exp(-10*z)

>>> E(X)
1/10

>>> std(X)
1/10


References

sympy.stats.FDistribution(name, d1, d2)[source]#

Create a continuous random variable with a F distribution.

Parameters:

d1 : $$d_1 > 0$$, where $$d_1$$ is the degrees of freedom ($$n_1 - 1$$)

d2 : $$d_2 > 0$$, where $$d_2$$ is the degrees of freedom ($$n_2 - 1$$)

Returns:

RandomSymbol

Explanation

The density of the F distribution is given by

$f(x) := \frac{\sqrt{\frac{(d_1 x)^{d_1} d_2^{d_2}} {(d_1 x + d_2)^{d_1 + d_2}}}} {x \mathrm{B} \left(\frac{d_1}{2}, \frac{d_2}{2}\right)}$

with $$x > 0$$.

Examples

>>> from sympy.stats import FDistribution, density
>>> from sympy import Symbol, pprint

>>> d1 = Symbol("d1", positive=True)
>>> d2 = Symbol("d2", positive=True)
>>> z = Symbol("z")

>>> X = FDistribution("x", d1, d2)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
d2
--    ______________________________
2    /       d1            -d1 - d2
d2  *\/  (d1*z)  *(d1*z + d2)
--------------------------------------
/d1  d2\
z*B|--, --|
\2   2 /


References

sympy.stats.FisherZ(name, d1, d2)[source]#

Create a Continuous Random Variable with an Fisher’s Z distribution.

Parameters:

d1 : $$d_1 > 0$$

Degree of freedom.

d2 : $$d_2 > 0$$

Degree of freedom.

Returns:

RandomSymbol

Explanation

The density of the Fisher’s Z distribution is given by

$f(x) := \frac{2d_1^{d_1/2} d_2^{d_2/2}} {\mathrm{B}(d_1/2, d_2/2)} \frac{e^{d_1z}}{\left(d_1e^{2z}+d_2\right)^{\left(d_1+d_2\right)/2}}$

Examples

>>> from sympy.stats import FisherZ, density
>>> from sympy import Symbol, pprint

>>> d1 = Symbol("d1", positive=True)
>>> d2 = Symbol("d2", positive=True)
>>> z = Symbol("z")

>>> X = FisherZ("x", d1, d2)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
d1   d2
d1   d2               - -- - --
--   --                 2    2
2    2  /    2*z     \           d1*z
2*d1  *d2  *\d1*e    + d2/         *e
-----------------------------------------
/d1  d2\
B|--, --|
\2   2 /


References

sympy.stats.Frechet(name, a, s=1, m=0)[source]#

Create a continuous random variable with a Frechet distribution.

Parameters:

a : Real number, $$a \in \left(0, \infty\right)$$ the shape

s : Real number, $$s \in \left(0, \infty\right)$$ the scale

m : Real number, $$m \in \left(-\infty, \infty\right)$$ the minimum

Returns:

RandomSymbol

Explanation

The density of the Frechet distribution is given by

$f(x) := \frac{\alpha}{s} \left(\frac{x-m}{s}\right)^{-1-\alpha} e^{-(\frac{x-m}{s})^{-\alpha}}$

with $$x \geq m$$.

Examples

>>> from sympy.stats import Frechet, density, cdf
>>> from sympy import Symbol

>>> a = Symbol("a", positive=True)
>>> s = Symbol("s", positive=True)
>>> m = Symbol("m", real=True)
>>> z = Symbol("z")

>>> X = Frechet("x", a, s, m)

>>> density(X)(z)
a*((-m + z)/s)**(-a - 1)*exp(-1/((-m + z)/s)**a)/s

>>> cdf(X)(z)
Piecewise((exp(-1/((-m + z)/s)**a), m <= z), (0, True))


References

sympy.stats.Gamma(name, k, theta)[source]#

Create a continuous random variable with a Gamma distribution.

Parameters:

k : Real number, $$k > 0$$, a shape

theta : Real number, $$\theta > 0$$, a scale

Returns:

RandomSymbol

Explanation

The density of the Gamma distribution is given by

$f(x) := \frac{1}{\Gamma(k) \theta^k} x^{k - 1} e^{-\frac{x}{\theta}}$

with $$x \in [0,1]$$.

Examples

>>> from sympy.stats import Gamma, density, cdf, E, variance
>>> from sympy import Symbol, pprint, simplify

>>> k = Symbol("k", positive=True)
>>> theta = Symbol("theta", positive=True)
>>> z = Symbol("z")

>>> X = Gamma("x", k, theta)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
-z
-----
-k  k - 1  theta
theta  *z     *e
---------------------
Gamma(k)

>>> C = cdf(X, meijerg=True)(z)
>>> pprint(C, use_unicode=False)
/            /     z  \
|k*lowergamma|k, -----|
|            \   theta/
<----------------------  for z >= 0
|     Gamma(k + 1)
|
\          0             otherwise

>>> E(X)
k*theta

>>> V = simplify(variance(X))
>>> pprint(V, use_unicode=False)
2
k*theta


References

sympy.stats.GammaInverse(name, a, b)[source]#

Create a continuous random variable with an inverse Gamma distribution.

Parameters:

a : Real number, $$a > 0$$, a shape

b : Real number, $$b > 0$$, a scale

Returns:

RandomSymbol

Explanation

The density of the inverse Gamma distribution is given by

$f(x) := \frac{\beta^\alpha}{\Gamma(\alpha)} x^{-\alpha - 1} \exp\left(\frac{-\beta}{x}\right)$

with $$x > 0$$.

Examples

>>> from sympy.stats import GammaInverse, density, cdf
>>> from sympy import Symbol, pprint

>>> a = Symbol("a", positive=True)
>>> b = Symbol("b", positive=True)
>>> z = Symbol("z")

>>> X = GammaInverse("x", a, b)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
-b
---
a  -a - 1   z
b *z      *e
---------------
Gamma(a)

>>> cdf(X)(z)
Piecewise((uppergamma(a, b/z)/gamma(a), z > 0), (0, True))


References

sympy.stats.Gompertz(name, b, eta)[source]#

Create a Continuous Random Variable with Gompertz distribution.

Parameters:

b : Real number, $$b > 0$$, a scale

eta : Real number, $$\eta > 0$$, a shape

Returns:

RandomSymbol

Explanation

The density of the Gompertz distribution is given by

$f(x) := b \eta e^{b x} e^{\eta} \exp \left(-\eta e^{bx} \right)$

with $$x \in [0, \infty)$$.

Examples

>>> from sympy.stats import Gompertz, density
>>> from sympy import Symbol

>>> b = Symbol("b", positive=True)
>>> eta = Symbol("eta", positive=True)
>>> z = Symbol("z")

>>> X = Gompertz("x", b, eta)

>>> density(X)(z)
b*eta*exp(eta)*exp(b*z)*exp(-eta*exp(b*z))


References

sympy.stats.Gumbel(name, beta, mu, minimum=False)[source]#

Create a Continuous Random Variable with Gumbel distribution.

Parameters:

mu : Real number, $$\mu$$, a location

beta : Real number, $$\beta > 0$$, a scale

minimum : Boolean, by default False, set to True for enabling minimum distribution

Returns:

RandomSymbol

Explanation

The density of the Gumbel distribution is given by

For Maximum

$f(x) := \dfrac{1}{\beta} \exp \left( -\dfrac{x-\mu}{\beta} - \exp \left( -\dfrac{x - \mu}{\beta} \right) \right)$

with $$x \in [ - \infty, \infty ]$$.

For Minimum

$f(x) := \frac{e^{- e^{\frac{- \mu + x}{\beta}} + \frac{- \mu + x}{\beta}}}{\beta}$

with $$x \in [ - \infty, \infty ]$$.

Examples

>>> from sympy.stats import Gumbel, density, cdf
>>> from sympy import Symbol
>>> x = Symbol("x")
>>> mu = Symbol("mu")
>>> beta = Symbol("beta", positive=True)
>>> X = Gumbel("x", beta, mu)
>>> density(X)(x)
exp(-exp(-(-mu + x)/beta) - (-mu + x)/beta)/beta
>>> cdf(X)(x)
exp(-exp(-(-mu + x)/beta))


References

sympy.stats.Kumaraswamy(name, a, b)[source]#

Create a Continuous Random Variable with a Kumaraswamy distribution.

Parameters:

a : Real number, $$a > 0$$, a shape

b : Real number, $$b > 0$$, a shape

Returns:

RandomSymbol

Explanation

The density of the Kumaraswamy distribution is given by

$f(x) := a b x^{a-1} (1-x^a)^{b-1}$

with $$x \in [0,1]$$.

Examples

>>> from sympy.stats import Kumaraswamy, density, cdf
>>> from sympy import Symbol, pprint

>>> a = Symbol("a", positive=True)
>>> b = Symbol("b", positive=True)
>>> z = Symbol("z")

>>> X = Kumaraswamy("x", a, b)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
b - 1
a - 1 /     a\
a*b*z     *\1 - z /

>>> cdf(X)(z)
Piecewise((0, z < 0), (1 - (1 - z**a)**b, z <= 1), (1, True))


References

sympy.stats.Laplace(name, mu, b)[source]#

Create a continuous random variable with a Laplace distribution.

Parameters:

mu : Real number or a list/matrix, the location (mean) or the

location vector

b : Real number or a positive definite matrix, representing a scale

or the covariance matrix.

Returns:

RandomSymbol

Explanation

The density of the Laplace distribution is given by

$f(x) := \frac{1}{2 b} \exp \left(-\frac{|x-\mu|}b \right)$

Examples

>>> from sympy.stats import Laplace, density, cdf
>>> from sympy import Symbol, pprint

>>> mu = Symbol("mu")
>>> b = Symbol("b", positive=True)
>>> z = Symbol("z")

>>> X = Laplace("x", mu, b)

>>> density(X)(z)
exp(-Abs(mu - z)/b)/(2*b)

>>> cdf(X)(z)
Piecewise((exp((-mu + z)/b)/2, mu > z), (1 - exp((mu - z)/b)/2, True))

>>> L = Laplace('L', [1, 2], [[1, 0], [0, 1]])
>>> pprint(density(L)(1, 2), use_unicode=False)
5        /     ____\
e *besselk\0, \/ 35 /
---------------------
pi


References

sympy.stats.Levy(name, mu, c)[source]#

Create a continuous random variable with a Levy distribution.

The density of the Levy distribution is given by

$f(x) := \sqrt(\frac{c}{2 \pi}) \frac{\exp -\frac{c}{2 (x - \mu)}}{(x - \mu)^{3/2}}$
Parameters:

mu : Real number

The location parameter.

c : Real number, $$c > 0$$

A scale parameter.

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Levy, density, cdf
>>> from sympy import Symbol

>>> mu = Symbol("mu", real=True)
>>> c = Symbol("c", positive=True)
>>> z = Symbol("z")

>>> X = Levy("x", mu, c)

>>> density(X)(z)
sqrt(2)*sqrt(c)*exp(-c/(-2*mu + 2*z))/(2*sqrt(pi)*(-mu + z)**(3/2))

>>> cdf(X)(z)
erfc(sqrt(c)*sqrt(1/(-2*mu + 2*z)))


References

sympy.stats.Logistic(name, mu, s)[source]#

Create a continuous random variable with a logistic distribution.

Parameters:

mu : Real number, the location (mean)

s : Real number, $$s > 0$$, a scale

Returns:

RandomSymbol

Explanation

The density of the logistic distribution is given by

$f(x) := \frac{e^{-(x-\mu)/s}} {s\left(1+e^{-(x-\mu)/s}\right)^2}$

Examples

>>> from sympy.stats import Logistic, density, cdf
>>> from sympy import Symbol

>>> mu = Symbol("mu", real=True)
>>> s = Symbol("s", positive=True)
>>> z = Symbol("z")

>>> X = Logistic("x", mu, s)

>>> density(X)(z)
exp((mu - z)/s)/(s*(exp((mu - z)/s) + 1)**2)

>>> cdf(X)(z)
1/(exp((mu - z)/s) + 1)


References

sympy.stats.LogLogistic(name, alpha, beta)[source]#

Create a continuous random variable with a log-logistic distribution. The distribution is unimodal when beta > 1.

Parameters:

alpha : Real number, $$\alpha > 0$$, scale parameter and median of distribution

beta : Real number, $$\beta > 0$$, a shape parameter

Returns:

RandomSymbol

Explanation

The density of the log-logistic distribution is given by

$f(x) := \frac{(\frac{\beta}{\alpha})(\frac{x}{\alpha})^{\beta - 1}} {(1 + (\frac{x}{\alpha})^{\beta})^2}$

Examples

>>> from sympy.stats import LogLogistic, density, cdf, quantile
>>> from sympy import Symbol, pprint

>>> alpha = Symbol("alpha", positive=True)
>>> beta = Symbol("beta", positive=True)
>>> p = Symbol("p")
>>> z = Symbol("z", positive=True)

>>> X = LogLogistic("x", alpha, beta)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
beta - 1
/  z  \
beta*|-----|
\alpha/
------------------------
2
/       beta    \
|/  z  \        |
alpha*||-----|     + 1|
\\alpha/        /

>>> cdf(X)(z)
1/(1 + (z/alpha)**(-beta))

>>> quantile(X)(p)
alpha*(p/(1 - p))**(1/beta)


References

sympy.stats.LogNormal(name, mean, std)[source]#

Create a continuous random variable with a log-normal distribution.

Parameters:

mu : Real number

The log-scale.

sigma : Real number

A shape. ($$\sigma^2 > 0$$)

Returns:

RandomSymbol

Explanation

The density of the log-normal distribution is given by

$f(x) := \frac{1}{x\sqrt{2\pi\sigma^2}} e^{-\frac{\left(\ln x-\mu\right)^2}{2\sigma^2}}$

with $$x \geq 0$$.

Examples

>>> from sympy.stats import LogNormal, density
>>> from sympy import Symbol, pprint

>>> mu = Symbol("mu", real=True)
>>> sigma = Symbol("sigma", positive=True)
>>> z = Symbol("z")

>>> X = LogNormal("x", mu, sigma)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
2
-(-mu + log(z))
-----------------
2
___      2*sigma
\/ 2 *e
------------------------
____
2*\/ pi *sigma*z

>>> X = LogNormal('x', 0, 1) # Mean 0, standard deviation 1

>>> density(X)(z)
sqrt(2)*exp(-log(z)**2/2)/(2*sqrt(pi)*z)


References

sympy.stats.Lomax(name, alpha, lamda)[source]#

Create a continuous random variable with a Lomax distribution.

Parameters:

alpha : Real Number, $$\alpha > 0$$

Shape parameter

lamda : Real Number, $$\lambda > 0$$

Scale parameter

Returns:

RandomSymbol

Explanation

The density of the Lomax distribution is given by

$f(x) := \frac{\alpha}{\lambda}\left[1+\frac{x}{\lambda}\right]^{-(\alpha+1)}$

Examples

>>> from sympy.stats import Lomax, density, cdf, E
>>> from sympy import symbols
>>> a, l = symbols('a, l', positive=True)
>>> X = Lomax('X', a, l)
>>> x = symbols('x')
>>> density(X)(x)
a*(1 + x/l)**(-a - 1)/l
>>> cdf(X)(x)
Piecewise((1 - 1/(1 + x/l)**a, x >= 0), (0, True))
>>> a = 2
>>> X = Lomax('X', a, l)
>>> E(X)
l


References

sympy.stats.Maxwell(name, a)[source]#

Create a continuous random variable with a Maxwell distribution.

Parameters:

a : Real number, $$a > 0$$

Returns:

RandomSymbol

Explanation

The density of the Maxwell distribution is given by

$f(x) := \sqrt{\frac{2}{\pi}} \frac{x^2 e^{-x^2/(2a^2)}}{a^3}$

with $$x \geq 0$$.

Examples

>>> from sympy.stats import Maxwell, density, E, variance
>>> from sympy import Symbol, simplify

>>> a = Symbol("a", positive=True)
>>> z = Symbol("z")

>>> X = Maxwell("x", a)

>>> density(X)(z)
sqrt(2)*z**2*exp(-z**2/(2*a**2))/(sqrt(pi)*a**3)

>>> E(X)
2*sqrt(2)*a/sqrt(pi)

>>> simplify(variance(X))
a**2*(-8 + 3*pi)/pi


References

sympy.stats.Moyal(name, mu, sigma)[source]#

Create a continuous random variable with a Moyal distribution.

Parameters:

mu : Real number

Location parameter

sigma : Real positive number

Scale parameter

Returns:

RandomSymbol

Explanation

The density of the Moyal distribution is given by

$f(x) := \frac{\exp-\frac{1}{2}\exp-\frac{x-\mu}{\sigma}-\frac{x-\mu}{2\sigma}}{\sqrt{2\pi}\sigma}$

with $$x \in \mathbb{R}$$.

Examples

>>> from sympy.stats import Moyal, density, cdf
>>> from sympy import Symbol, simplify
>>> mu = Symbol("mu", real=True)
>>> sigma = Symbol("sigma", positive=True, real=True)
>>> z = Symbol("z")
>>> X = Moyal("x", mu, sigma)
>>> density(X)(z)
sqrt(2)*exp(-exp((mu - z)/sigma)/2 - (-mu + z)/(2*sigma))/(2*sqrt(pi)*sigma)
>>> simplify(cdf(X)(z))
1 - erf(sqrt(2)*exp((mu - z)/(2*sigma))/2)


References

sympy.stats.Nakagami(name, mu, omega)[source]#

Create a continuous random variable with a Nakagami distribution.

Parameters:

mu : Real number, $$\mu \geq \frac{1}{2}$$, a shape

omega : Real number, $$\omega > 0$$, the spread

Returns:

RandomSymbol

Explanation

The density of the Nakagami distribution is given by

$f(x) := \frac{2\mu^\mu}{\Gamma(\mu)\omega^\mu} x^{2\mu-1} \exp\left(-\frac{\mu}{\omega}x^2 \right)$

with $$x > 0$$.

Examples

>>> from sympy.stats import Nakagami, density, E, variance, cdf
>>> from sympy import Symbol, simplify, pprint

>>> mu = Symbol("mu", positive=True)
>>> omega = Symbol("omega", positive=True)
>>> z = Symbol("z")

>>> X = Nakagami("x", mu, omega)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
2
-mu*z
-------
mu      -mu  2*mu - 1  omega
2*mu  *omega   *z        *e
----------------------------------
Gamma(mu)

>>> simplify(E(X))
sqrt(mu)*sqrt(omega)*gamma(mu + 1/2)/gamma(mu + 1)

>>> V = simplify(variance(X))
>>> pprint(V, use_unicode=False)
2
omega*Gamma (mu + 1/2)
omega - -----------------------
Gamma(mu)*Gamma(mu + 1)

>>> cdf(X)(z)
Piecewise((lowergamma(mu, mu*z**2/omega)/gamma(mu), z > 0),
(0, True))


References

sympy.stats.Normal(name, mean, std)[source]#

Create a continuous random variable with a Normal distribution.

Parameters:

mu : Real number or a list representing the mean or the mean vector

sigma : Real number or a positive definite square matrix,

$$\sigma^2 > 0$$, the variance

Returns:

RandomSymbol

Explanation

The density of the Normal distribution is given by

$f(x) := \frac{1}{\sigma\sqrt{2\pi}} e^{ -\frac{(x-\mu)^2}{2\sigma^2} }$

Examples

>>> from sympy.stats import Normal, density, E, std, cdf, skewness, quantile, marginal_distribution
>>> from sympy import Symbol, simplify, pprint

>>> mu = Symbol("mu")
>>> sigma = Symbol("sigma", positive=True)
>>> z = Symbol("z")
>>> y = Symbol("y")
>>> p = Symbol("p")
>>> X = Normal("x", mu, sigma)

>>> density(X)(z)
sqrt(2)*exp(-(-mu + z)**2/(2*sigma**2))/(2*sqrt(pi)*sigma)

>>> C = simplify(cdf(X))(z) # it needs a little more help...
>>> pprint(C, use_unicode=False)
/  ___          \
|\/ 2 *(-mu + z)|
erf|---------------|
\    2*sigma    /   1
-------------------- + -
2             2

>>> quantile(X)(p)
mu + sqrt(2)*sigma*erfinv(2*p - 1)

>>> simplify(skewness(X))
0

>>> X = Normal("x", 0, 1) # Mean 0, standard deviation 1
>>> density(X)(z)
sqrt(2)*exp(-z**2/2)/(2*sqrt(pi))

>>> E(2*X + 1)
1

>>> simplify(std(2*X + 1))
2

>>> m = Normal('X', [1, 2], [[2, 1], [1, 2]])
>>> pprint(density(m)(y, z), use_unicode=False)
2          2
y    y*z   z
- -- + --- - -- + z - 1
___    3     3    3
\/ 3 *e
------------------------------
6*pi

>>> marginal_distribution(m, m)(1)
1/(2*sqrt(pi))


References

sympy.stats.Pareto(name, xm, alpha)[source]#

Create a continuous random variable with the Pareto distribution.

Parameters:

xm : Real number, $$x_m > 0$$, a scale

alpha : Real number, $$\alpha > 0$$, a shape

Returns:

RandomSymbol

Explanation

The density of the Pareto distribution is given by

$f(x) := \frac{\alpha\,x_m^\alpha}{x^{\alpha+1}}$

with $$x \in [x_m,\infty]$$.

Examples

>>> from sympy.stats import Pareto, density
>>> from sympy import Symbol

>>> xm = Symbol("xm", positive=True)
>>> beta = Symbol("beta", positive=True)
>>> z = Symbol("z")

>>> X = Pareto("x", xm, beta)

>>> density(X)(z)
beta*xm**beta*z**(-beta - 1)


References

sympy.stats.PowerFunction(name, alpha, a, b)[source]#

Creates a continuous random variable with a Power Function Distribution.

Parameters:

alpha : Positive number, $$0 < \alpha$$, the shape parameter

a : Real number, $$-\infty < a$$, the left boundary

b : Real number, $$a < b < \infty$$, the right boundary

Returns:

RandomSymbol

Explanation

The density of PowerFunction distribution is given by

$f(x) := \frac{{\alpha}(x - a)^{\alpha - 1}}{(b - a)^{\alpha}}$

with $$x \in [a,b]$$.

Examples

>>> from sympy.stats import PowerFunction, density, cdf, E, variance
>>> from sympy import Symbol
>>> alpha = Symbol("alpha", positive=True)
>>> a = Symbol("a", real=True)
>>> b = Symbol("b", real=True)
>>> z = Symbol("z")

>>> X = PowerFunction("X", 2, a, b)

>>> density(X)(z)
(-2*a + 2*z)/(-a + b)**2

>>> cdf(X)(z)
Piecewise((a**2/(a**2 - 2*a*b + b**2) - 2*a*z/(a**2 - 2*a*b + b**2) +
z**2/(a**2 - 2*a*b + b**2), a <= z), (0, True))

>>> alpha = 2
>>> a = 0
>>> b = 1
>>> Y = PowerFunction("Y", alpha, a, b)

>>> E(Y)
2/3

>>> variance(Y)
1/18


References

Create a Continuous Random Variable with a U-quadratic distribution.

Parameters:

a : Real number

b : Real number, $$a < b$$

Returns:

RandomSymbol

Explanation

The density of the U-quadratic distribution is given by

$f(x) := \alpha (x-\beta)^2$

with $$x \in [a,b]$$.

Examples

>>> from sympy.stats import QuadraticU, density
>>> from sympy import Symbol, pprint

>>> a = Symbol("a", real=True)
>>> b = Symbol("b", real=True)
>>> z = Symbol("z")

>>> X = QuadraticU("x", a, b)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
/                2
|   /  a   b    \
|12*|- - - - + z|
|   \  2   2    /
<-----------------  for And(b >= z, a <= z)
|            3
|    (-a + b)
|
\        0                 otherwise


References

sympy.stats.RaisedCosine(name, mu, s)[source]#

Create a Continuous Random Variable with a raised cosine distribution.

Parameters:

mu : Real number

s : Real number, $$s > 0$$

Returns:

RandomSymbol

Explanation

The density of the raised cosine distribution is given by

$f(x) := \frac{1}{2s}\left(1+\cos\left(\frac{x-\mu}{s}\pi\right)\right)$

with $$x \in [\mu-s,\mu+s]$$.

Examples

>>> from sympy.stats import RaisedCosine, density
>>> from sympy import Symbol, pprint

>>> mu = Symbol("mu", real=True)
>>> s = Symbol("s", positive=True)
>>> z = Symbol("z")

>>> X = RaisedCosine("x", mu, s)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
/   /pi*(-mu + z)\
|cos|------------| + 1
|   \     s      /
<---------------------  for And(z >= mu - s, z <= mu + s)
|         2*s
|
\          0                        otherwise


References

sympy.stats.Rayleigh(name, sigma)[source]#

Create a continuous random variable with a Rayleigh distribution.

Parameters:

sigma : Real number, $$\sigma > 0$$

Returns:

RandomSymbol

Explanation

The density of the Rayleigh distribution is given by

$f(x) := \frac{x}{\sigma^2} e^{-x^2/2\sigma^2}$

with $$x > 0$$.

Examples

>>> from sympy.stats import Rayleigh, density, E, variance
>>> from sympy import Symbol

>>> sigma = Symbol("sigma", positive=True)
>>> z = Symbol("z")

>>> X = Rayleigh("x", sigma)

>>> density(X)(z)
z*exp(-z**2/(2*sigma**2))/sigma**2

>>> E(X)
sqrt(2)*sqrt(pi)*sigma/2

>>> variance(X)
-pi*sigma**2/2 + 2*sigma**2


References

sympy.stats.Reciprocal(name, a, b)[source]#

Creates a continuous random variable with a reciprocal distribution.

Parameters:

a : Real number, $$0 < a$$

b : Real number, $$a < b$$

Returns:

RandomSymbol

Examples

>>> from sympy.stats import Reciprocal, density, cdf
>>> from sympy import symbols
>>> a, b, x = symbols('a, b, x', positive=True)
>>> R = Reciprocal('R', a, b)

>>> density(R)(x)
1/(x*(-log(a) + log(b)))
>>> cdf(R)(x)
Piecewise((log(a)/(log(a) - log(b)) - log(x)/(log(a) - log(b)), a <= x), (0, True))


Reference

sympy.stats.StudentT(name, nu)[source]#

Create a continuous random variable with a student’s t distribution.

Parameters:

nu : Real number, $$\nu > 0$$, the degrees of freedom

Returns:

RandomSymbol

Explanation

The density of the student’s t distribution is given by

$f(x) := \frac{\Gamma \left(\frac{\nu+1}{2} \right)} {\sqrt{\nu\pi}\Gamma \left(\frac{\nu}{2} \right)} \left(1+\frac{x^2}{\nu} \right)^{-\frac{\nu+1}{2}}$

Examples

>>> from sympy.stats import StudentT, density, cdf
>>> from sympy import Symbol, pprint

>>> nu = Symbol("nu", positive=True)
>>> z = Symbol("z")

>>> X = StudentT("x", nu)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
nu   1
- -- - -
2    2
/     2\
|    z |
|1 + --|
\    nu/
-----------------
____  /     nu\
\/ nu *B|1/2, --|
\     2 /

>>> cdf(X)(z)
1/2 + z*gamma(nu/2 + 1/2)*hyper((1/2, nu/2 + 1/2), (3/2,),
-z**2/nu)/(sqrt(pi)*sqrt(nu)*gamma(nu/2))


References

sympy.stats.ShiftedGompertz(name, b, eta)[source]#

Create a continuous random variable with a Shifted Gompertz distribution.

Parameters:

b : Real number, $$b > 0$$, a scale

eta : Real number, $$\eta > 0$$, a shape

Returns:

RandomSymbol

Explanation

The density of the Shifted Gompertz distribution is given by

$f(x) := b e^{-b x} e^{-\eta \exp(-b x)} \left[1 + \eta(1 - e^(-bx)) \right]$

with $$x \in [0, \infty)$$.

Examples

>>> from sympy.stats import ShiftedGompertz, density
>>> from sympy import Symbol

>>> b = Symbol("b", positive=True)
>>> eta = Symbol("eta", positive=True)
>>> x = Symbol("x")

>>> X = ShiftedGompertz("x", b, eta)

>>> density(X)(x)
b*(eta*(1 - exp(-b*x)) + 1)*exp(-b*x)*exp(-eta*exp(-b*x))


References

sympy.stats.Trapezoidal(name, a, b, c, d)[source]#

Create a continuous random variable with a trapezoidal distribution.

Parameters:

a : Real number, $$a < d$$

b : Real number, $$a \le b < c$$

c : Real number, $$b < c \le d$$

d : Real number

Returns:

RandomSymbol

Explanation

The density of the trapezoidal distribution is given by

$\begin{split}f(x) := \begin{cases} 0 & \mathrm{for\ } x < a, \\ \frac{2(x-a)}{(b-a)(d+c-a-b)} & \mathrm{for\ } a \le x < b, \\ \frac{2}{d+c-a-b} & \mathrm{for\ } b \le x < c, \\ \frac{2(d-x)}{(d-c)(d+c-a-b)} & \mathrm{for\ } c \le x < d, \\ 0 & \mathrm{for\ } d < x. \end{cases}\end{split}$

Examples

>>> from sympy.stats import Trapezoidal, density
>>> from sympy import Symbol, pprint

>>> a = Symbol("a")
>>> b = Symbol("b")
>>> c = Symbol("c")
>>> d = Symbol("d")
>>> z = Symbol("z")

>>> X = Trapezoidal("x", a,b,c,d)

>>> pprint(density(X)(z), use_unicode=False)
/        -2*a + 2*z
|-------------------------  for And(a <= z, b > z)
|(-a + b)*(-a - b + c + d)
|
|           2
|     --------------        for And(b <= z, c > z)
<     -a - b + c + d
|
|        2*d - 2*z
|-------------------------  for And(d >= z, c <= z)
|(-c + d)*(-a - b + c + d)
|
\            0                     otherwise


References

sympy.stats.Triangular(name, a, b, c)[source]#

Create a continuous random variable with a triangular distribution.

Parameters:

a : Real number, $$a \in \left(-\infty, \infty\right)$$

b : Real number, $$a < b$$

c : Real number, $$a \leq c \leq b$$

Returns:

RandomSymbol

Explanation

The density of the triangular distribution is given by

$\begin{split}f(x) := \begin{cases} 0 & \mathrm{for\ } x < a, \\ \frac{2(x-a)}{(b-a)(c-a)} & \mathrm{for\ } a \le x < c, \\ \frac{2}{b-a} & \mathrm{for\ } x = c, \\ \frac{2(b-x)}{(b-a)(b-c)} & \mathrm{for\ } c < x \le b, \\ 0 & \mathrm{for\ } b < x. \end{cases}\end{split}$

Examples

>>> from sympy.stats import Triangular, density
>>> from sympy import Symbol, pprint

>>> a = Symbol("a")
>>> b = Symbol("b")
>>> c = Symbol("c")
>>> z = Symbol("z")

>>> X = Triangular("x", a,b,c)

>>> pprint(density(X)(z), use_unicode=False)
/    -2*a + 2*z
|-----------------  for And(a <= z, c > z)
|(-a + b)*(-a + c)
|
|       2
|     ------              for c = z
<     -a + b
|
|   2*b - 2*z
|----------------   for And(b >= z, c < z)
|(-a + b)*(b - c)
|
\        0                otherwise


References

sympy.stats.Uniform(name, left, right)[source]#

Create a continuous random variable with a uniform distribution.

Parameters:

a : Real number, $$-\infty < a$$, the left boundary

b : Real number, $$a < b < \infty$$, the right boundary

Returns:

RandomSymbol

Explanation

The density of the uniform distribution is given by

$\begin{split}f(x) := \begin{cases} \frac{1}{b - a} & \text{for } x \in [a,b] \\ 0 & \text{otherwise} \end{cases}\end{split}$

with $$x \in [a,b]$$.

Examples

>>> from sympy.stats import Uniform, density, cdf, E, variance
>>> from sympy import Symbol, simplify

>>> a = Symbol("a", negative=True)
>>> b = Symbol("b", positive=True)
>>> z = Symbol("z")

>>> X = Uniform("x", a, b)

>>> density(X)(z)
Piecewise((1/(-a + b), (b >= z) & (a <= z)), (0, True))

>>> cdf(X)(z)
Piecewise((0, a > z), ((-a + z)/(-a + b), b >= z), (1, True))

>>> E(X)
a/2 + b/2

>>> simplify(variance(X))
a**2/12 - a*b/6 + b**2/12


References

sympy.stats.UniformSum(name, n)[source]#

Create a continuous random variable with an Irwin-Hall distribution.

Parameters:

n : A positive integer, $$n > 0$$

Returns:

RandomSymbol

Explanation

The probability distribution function depends on a single parameter $$n$$ which is an integer.

The density of the Irwin-Hall distribution is given by

$f(x) := \frac{1}{(n-1)!}\sum_{k=0}^{\left\lfloor x\right\rfloor}(-1)^k \binom{n}{k}(x-k)^{n-1}$

Examples

>>> from sympy.stats import UniformSum, density, cdf
>>> from sympy import Symbol, pprint

>>> n = Symbol("n", integer=True)
>>> z = Symbol("z")

>>> X = UniformSum("x", n)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
floor(z)
___
\  
\         k         n - 1 /n\
)    (-1) *(-k + z)     *| |
/                         \k/
/__,
k = 0
--------------------------------
(n - 1)!

>>> cdf(X)(z)
Piecewise((0, z < 0), (Sum((-1)**_k*(-_k + z)**n*binomial(n, _k),
(_k, 0, floor(z)))/factorial(n), n >= z), (1, True))


Compute cdf with specific ‘x’ and ‘n’ values as follows : >>> cdf(UniformSum(“x”, 5), evaluate=False)(2).doit() 9/40

The argument evaluate=False prevents an attempt at evaluation of the sum for general n, before the argument 2 is passed.

References

sympy.stats.VonMises(name, mu, k)[source]#

Create a Continuous Random Variable with a von Mises distribution.

Parameters:

mu : Real number

Measure of location.

k : Real number

Measure of concentration.

Returns:

RandomSymbol

Explanation

The density of the von Mises distribution is given by

$f(x) := \frac{e^{\kappa\cos(x-\mu)}}{2\pi I_0(\kappa)}$

with $$x \in [0,2\pi]$$.

Examples

>>> from sympy.stats import VonMises, density
>>> from sympy import Symbol, pprint

>>> mu = Symbol("mu")
>>> k = Symbol("k", positive=True)
>>> z = Symbol("z")

>>> X = VonMises("x", mu, k)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
k*cos(mu - z)
e
------------------
2*pi*besseli(0, k)


References

sympy.stats.Wald(name, mean, shape)[source]#

Create a continuous random variable with an Inverse Gaussian distribution. Inverse Gaussian distribution is also known as Wald distribution.

Parameters:

mu :

Positive number representing the mean.

lambda :

Positive number representing the shape parameter.

Returns:

RandomSymbol

Explanation

The density of the Inverse Gaussian distribution is given by

$f(x) := \sqrt{\frac{\lambda}{2\pi x^3}} e^{-\frac{\lambda(x-\mu)^2}{2x\mu^2}}$

Examples

>>> from sympy.stats import GaussianInverse, density, E, std, skewness
>>> from sympy import Symbol, pprint

>>> mu = Symbol("mu", positive=True)
>>> lamda = Symbol("lambda", positive=True)
>>> z = Symbol("z", positive=True)
>>> X = GaussianInverse("x", mu, lamda)

>>> D = density(X)(z)
>>> pprint(D, use_unicode=False)
2
-lambda*(-mu + z)
-------------------
2
___   ________        2*mu *z
\/ 2 *\/ lambda *e
-------------------------------------
____  3/2
2*\/ pi *z

>>> E(X)
mu

>>> std(X).expand()
mu**(3/2)/sqrt(lambda)

>>> skewness(X).expand()
3*sqrt(mu)/sqrt(lambda)


References

sympy.stats.Weibull(name, alpha, beta)[source]#

Create a continuous random variable with a Weibull distribution.

Parameters:

lambda : Real number, $$\lambda > 0$$, a scale

k : Real number, $$k > 0$$, a shape

Returns:

RandomSymbol

Explanation

The density of the Weibull distribution is given by

$\begin{split}f(x) := \begin{cases} \frac{k}{\lambda}\left(\frac{x}{\lambda}\right)^{k-1} e^{-(x/\lambda)^{k}} & x\geq0\\ 0 & x<0 \end{cases}\end{split}$

Examples

>>> from sympy.stats import Weibull, density, E, variance
>>> from sympy import Symbol, simplify

>>> l = Symbol("lambda", positive=True)
>>> k = Symbol("k", positive=True)
>>> z = Symbol("z")

>>> X = Weibull("x", l, k)

>>> density(X)(z)
k*(z/lambda)**(k - 1)*exp(-(z/lambda)**k)/lambda

>>> simplify(E(X))
lambda*gamma(1 + 1/k)

>>> simplify(variance(X))
lambda**2*(-gamma(1 + 1/k)**2 + gamma(1 + 2/k))


References

sympy.stats.WignerSemicircle(name, R)[source]#

Create a continuous random variable with a Wigner semicircle distribution.

Parameters:

R : Real number, $$R > 0$$, the radius

Returns:

A RandomSymbol.

Explanation

The density of the Wigner semicircle distribution is given by

$f(x) := \frac2{\pi R^2}\,\sqrt{R^2-x^2}$

with $$x \in [-R,R]$$.

Examples

>>> from sympy.stats import WignerSemicircle, density, E
>>> from sympy import Symbol

>>> R = Symbol("R", positive=True)
>>> z = Symbol("z")

>>> X = WignerSemicircle("x", R)

>>> density(X)(z)
2*sqrt(R**2 - z**2)/(pi*R**2)

>>> E(X)
0


References

sympy.stats.ContinuousRV(symbol, density, set=Interval(-oo, oo), **kwargs)[source]#

Create a Continuous Random Variable given the following:

Parameters:

symbol : Symbol

Represents name of the random variable.

density : Expression containing symbol

Represents probability density function.

set : set/Interval

Represents the region where the pdf is valid, by default is real line.

check : bool

If True, it will check whether the given density integrates to 1 over the given set. If False, it will not perform this check. Default is False.

Returns:

RandomSymbol

Many common continuous random variable types are already implemented.

This function should be necessary only very rarely.

Examples

>>> from sympy import Symbol, sqrt, exp, pi
>>> from sympy.stats import ContinuousRV, P, E

>>> x = Symbol("x")

>>> pdf = sqrt(2)*exp(-x**2/2)/(2*sqrt(pi)) # Normal distribution
>>> X = ContinuousRV(x, pdf)

>>> E(X)
0
>>> P(X>0)
1/2


### Joint Types#

sympy.stats.JointRV(symbol, pdf, _set=None)[source]#

Create a Joint Random Variable where each of its component is continuous, given the following:

Parameters:

symbol : Symbol

Represents name of the random variable.

pdf : A PDF in terms of indexed symbols of the symbol given

as the first argument

Returns:

RandomSymbol

Note

As of now, the set for each component for a JointRV is equal to the set of all integers, which cannot be changed.

Examples

>>> from sympy import exp, pi, Indexed, S
>>> from sympy.stats import density, JointRV
>>> x1, x2 = (Indexed('x', i) for i in (1, 2))
>>> pdf = exp(-x1**2/2 + x1 - x2**2/2 - S(1)/2)/(2*pi)
>>> N1 = JointRV('x', pdf) #Multivariate Normal distribution
>>> density(N1)(1, 2)
exp(-2)/(2*pi)

sympy.stats.marginal_distribution(rv, *indices)[source]#

Marginal distribution function of a joint random variable.

Parameters:

rv : A random variable with a joint probability distribution.

indices : Component indices or the indexed random symbol

for which the joint distribution is to be calculated

Returns:

A Lambda expression in $$sym$$.

Examples

>>> from sympy.stats import MultivariateNormal, marginal_distribution
>>> m = MultivariateNormal('X', [1, 2], [[2, 1], [1, 2]])
>>> marginal_distribution(m, m)(1)
1/(2*sqrt(pi))

sympy.stats.MultivariateNormal(name, mu, sigma)[source]#

Creates a continuous random variable with Multivariate Normal Distribution.

The density of the multivariate normal distribution can be found at .

Parameters:

mu : List representing the mean or the mean vector

sigma : Positive semidefinite square matrix

Represents covariance Matrix. If $$\sigma$$ is noninvertible then only sampling is supported currently

Returns:

RandomSymbol

Examples

>>> from sympy.stats import MultivariateNormal, density, marginal_distribution
>>> from sympy import symbols, MatrixSymbol
>>> X = MultivariateNormal('X', [3, 4], [[2, 1], [1, 2]])
>>> y, z = symbols('y z')
>>> density(X)(y, z)
sqrt(3)*exp(-y**2/3 + y*z/3 + 2*y/3 - z**2/3 + 5*z/3 - 13/3)/(6*pi)
>>> density(X)(1, 2)
sqrt(3)*exp(-4/3)/(6*pi)
>>> marginal_distribution(X, X)(y)
exp(-(y - 4)**2/4)/(2*sqrt(pi))
>>> marginal_distribution(X, X)(y)
exp(-(y - 3)**2/4)/(2*sqrt(pi))


The example below shows that it is also possible to use symbolic parameters to define the MultivariateNormal class.

>>> n = symbols('n', integer=True, positive=True)
>>> Sg = MatrixSymbol('Sg', n, n)
>>> mu = MatrixSymbol('mu', n, 1)
>>> obs = MatrixSymbol('obs', n, 1)
>>> X = MultivariateNormal('X', mu, Sg)


The density of a multivariate normal can be calculated using a matrix argument, as shown below.

>>> density(X)(obs)
(exp(((1/2)*mu.T - (1/2)*obs.T)*Sg**(-1)*(-mu + obs))/sqrt((2*pi)**n*Determinant(Sg)))[0, 0]


References

sympy.stats.MultivariateLaplace(name, mu, sigma)[source]#

Creates a continuous random variable with Multivariate Laplace Distribution.

The density of the multivariate Laplace distribution can be found at .

Parameters:

mu : List representing the mean or the mean vector

sigma : Positive definite square matrix

Represents covariance Matrix

Returns:

RandomSymbol

Examples

>>> from sympy.stats import MultivariateLaplace, density
>>> from sympy import symbols
>>> y, z = symbols('y z')
>>> X = MultivariateLaplace('X', [2, 4], [[3, 1], [1, 3]])
>>> density(X)(y, z)
sqrt(2)*exp(y/4 + 5*z/4)*besselk(0, sqrt(15*y*(3*y/8 - z/8)/2 + 15*z*(-y/8 + 3*z/8)/2))/(4*pi)
>>> density(X)(1, 2)
sqrt(2)*exp(11/4)*besselk(0, sqrt(165)/4)/(4*pi)


References

sympy.stats.GeneralizedMultivariateLogGamma(syms, delta, v, lamda, mu)[source]#

Creates a joint random variable with generalized multivariate log gamma distribution.

The joint pdf can be found at .

Parameters:

syms : list/tuple/set of symbols for identifying each component

delta : A constant in range $$[0, 1]$$

v : Positive real number

lamda : List of positive real numbers

mu : List of positive real numbers

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density
>>> from sympy.stats.joint_rv_types import GeneralizedMultivariateLogGamma
>>> from sympy import symbols, S
>>> v = 1
>>> l, mu = [1, 1, 1], [1, 1, 1]
>>> d = S.Half
>>> y = symbols('y_1:4', positive=True)
>>> Gd = GeneralizedMultivariateLogGamma('G', d, v, l, mu)
>>> density(Gd)(y, y, y)
Sum(exp((n + 1)*(y_1 + y_2 + y_3) - exp(y_1) - exp(y_2) -
exp(y_3))/(2**n*gamma(n + 1)**3), (n, 0, oo))/2


Note

If the GeneralizedMultivariateLogGamma is too long to type use,

>>> from sympy.stats.joint_rv_types import GeneralizedMultivariateLogGamma as GMVLG
>>> Gd = GMVLG('G', d, v, l, mu)


If you want to pass the matrix omega instead of the constant delta, then use GeneralizedMultivariateLogGammaOmega.

References

sympy.stats.GeneralizedMultivariateLogGammaOmega(syms, omega, v, lamda, mu)[source]#

Extends GeneralizedMultivariateLogGamma.

Parameters:

syms : list/tuple/set of symbols

For identifying each component

omega : A square matrix

Every element of square matrix must be absolute value of square root of correlation coefficient

v : Positive real number

lamda : List of positive real numbers

mu : List of positive real numbers

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density
>>> from sympy.stats.joint_rv_types import GeneralizedMultivariateLogGammaOmega
>>> from sympy import Matrix, symbols, S
>>> omega = Matrix([[1, S.Half, S.Half], [S.Half, 1, S.Half], [S.Half, S.Half, 1]])
>>> v = 1
>>> l, mu = [1, 1, 1], [1, 1, 1]
>>> G = GeneralizedMultivariateLogGammaOmega('G', omega, v, l, mu)
>>> y = symbols('y_1:4', positive=True)
>>> density(G)(y, y, y)
sqrt(2)*Sum((1 - sqrt(2)/2)**n*exp((n + 1)*(y_1 + y_2 + y_3) - exp(y_1) -
exp(y_2) - exp(y_3))/gamma(n + 1)**3, (n, 0, oo))/2


Notes

If the GeneralizedMultivariateLogGammaOmega is too long to type use,

>>> from sympy.stats.joint_rv_types import GeneralizedMultivariateLogGammaOmega as GMVLGO
>>> G = GMVLGO('G', omega, v, l, mu)


References

sympy.stats.Multinomial(syms, n, *p)[source]#

Creates a discrete random variable with Multinomial Distribution.

The density of the said distribution can be found at .

Parameters:

n : Positive integer

Represents number of trials

p : List of event probabilities

Must be in the range of $$[0, 1]$$.

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density, Multinomial, marginal_distribution
>>> from sympy import symbols
>>> x1, x2, x3 = symbols('x1, x2, x3', nonnegative=True, integer=True)
>>> p1, p2, p3 = symbols('p1, p2, p3', positive=True)
>>> M = Multinomial('M', 3, p1, p2, p3)
>>> density(M)(x1, x2, x3)
Piecewise((6*p1**x1*p2**x2*p3**x3/(factorial(x1)*factorial(x2)*factorial(x3)),
Eq(x1 + x2 + x3, 3)), (0, True))
>>> marginal_distribution(M, M)(x1).subs(x1, 1)
3*p1*p2**2 + 6*p1*p2*p3 + 3*p1*p3**2


References

sympy.stats.MultivariateBeta(syms, *alpha)[source]#

Creates a continuous random variable with Dirichlet/Multivariate Beta Distribution.

The density of the Dirichlet distribution can be found at .

Parameters:

alpha : Positive real numbers

Signifies concentration numbers.

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density, MultivariateBeta, marginal_distribution
>>> from sympy import Symbol
>>> a1 = Symbol('a1', positive=True)
>>> a2 = Symbol('a2', positive=True)
>>> B = MultivariateBeta('B', [a1, a2])
>>> C = MultivariateBeta('C', a1, a2)
>>> x = Symbol('x')
>>> y = Symbol('y')
>>> density(B)(x, y)
x**(a1 - 1)*y**(a2 - 1)*gamma(a1 + a2)/(gamma(a1)*gamma(a2))
>>> marginal_distribution(C, C)(x)
x**(a1 - 1)*gamma(a1 + a2)/(a2*gamma(a1)*gamma(a2))


References

sympy.stats.MultivariateEwens(syms, n, theta)[source]#

Creates a discrete random variable with Multivariate Ewens Distribution.

The density of the said distribution can be found at .

Parameters:

n : Positive integer

Size of the sample or the integer whose partitions are considered

theta : Positive real number

Denotes Mutation rate

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density, marginal_distribution, MultivariateEwens
>>> from sympy import Symbol
>>> a1 = Symbol('a1', positive=True)
>>> a2 = Symbol('a2', positive=True)
>>> ed = MultivariateEwens('E', 2, 1)
>>> density(ed)(a1, a2)
Piecewise((1/(2**a2*factorial(a1)*factorial(a2)), Eq(a1 + 2*a2, 2)), (0, True))
>>> marginal_distribution(ed, ed)(a1)
Piecewise((1/factorial(a1), Eq(a1, 2)), (0, True))


References

sympy.stats.MultivariateT(syms, mu, sigma, v)[source]#

Creates a joint random variable with multivariate T-distribution.

Parameters:

syms : A symbol/str

For identifying the random variable.

mu : A list/matrix

Representing the location vector

sigma : The shape matrix for the distribution

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density, MultivariateT
>>> from sympy import Symbol

>>> x = Symbol("x")
>>> X = MultivariateT("x", [1, 1], [[1, 0], [0, 1]], 2)

>>> density(X)(1, 2)
2/(9*pi)

sympy.stats.NegativeMultinomial(syms, k0, *p)[source]#

Creates a discrete random variable with Negative Multinomial Distribution.

The density of the said distribution can be found at .

Parameters:

k0 : positive integer

Represents number of failures before the experiment is stopped

p : List of event probabilities

Must be in the range of $$[0, 1]$$

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density, NegativeMultinomial, marginal_distribution
>>> from sympy import symbols
>>> x1, x2, x3 = symbols('x1, x2, x3', nonnegative=True, integer=True)
>>> p1, p2, p3 = symbols('p1, p2, p3', positive=True)
>>> N = NegativeMultinomial('M', 3, p1, p2, p3)
>>> N_c = NegativeMultinomial('M', 3, 0.1, 0.1, 0.1)
>>> density(N)(x1, x2, x3)
p1**x1*p2**x2*p3**x3*(-p1 - p2 - p3 + 1)**3*gamma(x1 + x2 +
x3 + 3)/(2*factorial(x1)*factorial(x2)*factorial(x3))
>>> marginal_distribution(N_c, N_c)(1).evalf().round(2)
0.25


References

sympy.stats.NormalGamma(sym, mu, lamda, alpha, beta)[source]#

Creates a bivariate joint random variable with multivariate Normal gamma distribution.

Parameters:

sym : A symbol/str

For identifying the random variable.

mu : A real number

The mean of the normal distribution

lamda : A positive integer

Parameter of joint distribution

alpha : A positive integer

Parameter of joint distribution

beta : A positive integer

Parameter of joint distribution

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density, NormalGamma
>>> from sympy import symbols

>>> X = NormalGamma('x', 0, 1, 2, 3)
>>> y, z = symbols('y z')

>>> density(X)(y, z)
9*sqrt(2)*z**(3/2)*exp(-3*z)*exp(-y**2*z/2)/(2*sqrt(pi))


References

### Stochastic Processes#

class sympy.stats.DiscreteMarkovChain(sym, state_space=None, trans_probs=None)[source]#

Represents a finite discrete time-homogeneous Markov chain.

This type of Markov Chain can be uniquely characterised by its (ordered) state space and its one-step transition probability matrix.

Parameters:

sym:

The name given to the Markov Chain

state_space:

Optional, by default, Range(n)

trans_probs:

Optional, by default, MatrixSymbol(‘_T’, n, n)

Examples

>>> from sympy.stats import DiscreteMarkovChain, TransitionMatrixOf, P, E
>>> from sympy import Matrix, MatrixSymbol, Eq, symbols
>>> T = Matrix([[0.5, 0.2, 0.3],[0.2, 0.5, 0.3],[0.2, 0.3, 0.5]])
>>> Y = DiscreteMarkovChain("Y", [0, 1, 2], T)
>>> YS = DiscreteMarkovChain("Y")

>>> Y.state_space
{0, 1, 2}
>>> Y.transition_probabilities
Matrix([
[0.5, 0.2, 0.3],
[0.2, 0.5, 0.3],
[0.2, 0.3, 0.5]])
>>> TS = MatrixSymbol('T', 3, 3)
>>> P(Eq(YS, 2), Eq(YS, 1) & TransitionMatrixOf(YS, TS))
T[0, 2]*T[1, 0] + T[1, 1]*T[1, 2] + T[1, 2]*T[2, 2]
>>> P(Eq(Y, 2), Eq(Y, 1)).round(2)
0.36


Probabilities will be calculated based on indexes rather than state names. For example, with the Sunny-Cloudy-Rainy model with string state names:

>>> from sympy.core.symbol import Str
>>> Y = DiscreteMarkovChain("Y", [Str('Sunny'), Str('Cloudy'), Str('Rainy')], T)
>>> P(Eq(Y, 2), Eq(Y, 1)).round(2)
0.36


This gives the same answer as the [0, 1, 2] state space. Currently, there is no support for state names within probability and expectation statements. Here is a work-around using Str:

>>> P(Eq(Str('Rainy'), Y), Eq(Y, Str('Cloudy'))).round(2)
0.36


Symbol state names can also be used:

>>> sunny, cloudy, rainy = symbols('Sunny, Cloudy, Rainy')
>>> Y = DiscreteMarkovChain("Y", [sunny, cloudy, rainy], T)
>>> P(Eq(Y, rainy), Eq(Y, cloudy)).round(2)
0.36


Expectations will be calculated as follows:

>>> E(Y, Eq(Y, cloudy))
0.38*Cloudy + 0.36*Rainy + 0.26*Sunny


Probability of expressions with multiple RandomIndexedSymbols can also be calculated provided there is only 1 RandomIndexedSymbol in the given condition. It is always better to use Rational instead of floating point numbers for the probabilities in the transition matrix to avoid errors.

>>> from sympy import Gt, Le, Rational
>>> T = Matrix([[Rational(5, 10), Rational(3, 10), Rational(2, 10)], [Rational(2, 10), Rational(7, 10), Rational(1, 10)], [Rational(3, 10), Rational(3, 10), Rational(4, 10)]])
>>> Y = DiscreteMarkovChain("Y", [0, 1, 2], T)
>>> P(Eq(Y, Y), Eq(Y, 0)).round(3)
0.409
>>> P(Gt(Y, Y), Eq(Y, 0)).round(2)
0.36
>>> P(Le(Y, Y), Eq(Y, 2)).round(7)
0.6963328


Symbolic probability queries are also supported

>>> a, b, c, d = symbols('a b c d')
>>> T = Matrix([[Rational(1, 10), Rational(4, 10), Rational(5, 10)], [Rational(3, 10), Rational(4, 10), Rational(3, 10)], [Rational(7, 10), Rational(2, 10), Rational(1, 10)]])
>>> Y = DiscreteMarkovChain("Y", [0, 1, 2], T)
>>> query = P(Eq(Y[a], b), Eq(Y[c], d))
>>> query.subs({a:10, b:2, c:5, d:1}).round(4)
0.3096
>>> P(Eq(Y, 2), Eq(Y, 1)).evalf().round(4)
0.3096
>>> query_gt = P(Gt(Y[a], b), Eq(Y[c], d))
>>> query_gt.subs({a:21, b:0, c:5, d:0}).evalf().round(5)
0.64705
>>> P(Gt(Y, 0), Eq(Y, 0)).round(5)
0.64705


There is limited support for arbitrarily sized states:

>>> n = symbols('n', nonnegative=True, integer=True)
>>> T = MatrixSymbol('T', n, n)
>>> Y = DiscreteMarkovChain("Y", trans_probs=T)
>>> Y.state_space
Range(0, n, 1)
>>> query = P(Eq(Y[a], b), Eq(Y[c], d))
>>> query.subs({a:10, b:2, c:5, d:1})
(T**5)[1, 2]


References

absorbing_probabilities()[source]#

Computes the absorbing probabilities, i.e. the ij-th entry of the matrix denotes the probability of Markov chain being absorbed in state j starting from state i.

canonical_form() Tuple[List[Basic], ImmutableDenseMatrix][source]#

Reorders the one-step transition matrix so that recurrent states appear first and transient states appear last. Other representations include inserting transient states first and recurrent states last.

Returns:

states, P_new

states is the list that describes the order of the new states in the matrix so that the ith element in states is the state of the ith row of A. P_new is the new transition matrix in canonical form.

Examples

>>> from sympy.stats import DiscreteMarkovChain
>>> from sympy import Matrix, S


You can convert your chain into canonical form:

>>> T = Matrix([[S(1)/2, S(1)/2, 0,      0,      0],
...             [S(2)/5, S(1)/5, S(2)/5, 0,      0],
...             [0,      0,      1,      0,      0],
...             [0,      0,      S(1)/2, S(1)/2, 0],
...             [S(1)/2, 0,      0,      0, S(1)/2]])
>>> X = DiscreteMarkovChain('X', list(range(1, 6)), trans_probs=T)
>>> states, new_matrix = X.canonical_form()
>>> states
[3, 1, 2, 4, 5]

>>> new_matrix
Matrix([
[  1,   0,   0,   0,   0],
[  0, 1/2, 1/2,   0,   0],
[2/5, 2/5, 1/5,   0,   0],
[1/2,   0,   0, 1/2,   0],
[  0, 1/2,   0,   0, 1/2]])


The new states are [3, 1, 2, 4, 5] and you can create a new chain with this and its canonical form will remain the same (since it is already in canonical form).

>>> X = DiscreteMarkovChain('X', states, new_matrix)
>>> states, new_matrix = X.canonical_form()
>>> states
[3, 1, 2, 4, 5]

>>> new_matrix
Matrix([
[  1,   0,   0,   0,   0],
[  0, 1/2, 1/2,   0,   0],
[2/5, 2/5, 1/5,   0,   0],
[1/2,   0,   0, 1/2,   0],
[  0, 1/2,   0,   0, 1/2]])


This is not limited to absorbing chains:

>>> T = Matrix([[0, 5,  5, 0,  0],
...             [0, 0,  0, 10, 0],
...             [5, 0,  5, 0,  0],
...             [0, 10, 0, 0,  0],
...             [0, 3,  0, 3,  4]])/10
>>> X = DiscreteMarkovChain('X', trans_probs=T)
>>> states, new_matrix = X.canonical_form()
>>> states
[1, 3, 0, 2, 4]

>>> new_matrix
Matrix([
[   0,    1,   0,   0,   0],
[   1,    0,   0,   0,   0],
[ 1/2,    0,   0, 1/2,   0],
[   0,    0, 1/2, 1/2,   0],
[3/10, 3/10,   0,   0, 2/5]])


References

communication_classes() List[Tuple[List[Basic], Boolean, Integer]][source]#

Returns the list of communication classes that partition the states of the markov chain.

A communication class is defined to be a set of states such that every state in that set is reachable from every other state in that set. Due to its properties this forms a class in the mathematical sense. Communication classes are also known as recurrence classes.

Returns:

classes

The classes are a list of tuples. Each tuple represents a single communication class with its properties. The first element in the tuple is the list of states in the class, the second element is whether the class is recurrent and the third element is the period of the communication class.

Examples

>>> from sympy.stats import DiscreteMarkovChain
>>> from sympy import Matrix
>>> T = Matrix([[0, 1, 0],
...             [1, 0, 0],
...             [1, 0, 0]])
>>> X = DiscreteMarkovChain('X', [1, 2, 3], T)
>>> classes = X.communication_classes()
>>> for states, is_recurrent, period in classes:
...     states, is_recurrent, period
([1, 2], True, 2)
(, False, 1)


From this we can see that states 1 and 2 communicate, are recurrent and have a period of 2. We can also see state 3 is transient with a period of 1.

Notes

The algorithm used is of order O(n**2) where n is the number of states in the markov chain. It uses Tarjan’s algorithm to find the classes themselves and then it uses a breadth-first search algorithm to find each class’s periodicity. Most of the algorithm’s components approach O(n) as the matrix becomes more and more sparse.

References

decompose() [source]#

Decomposes the transition matrix into submatrices with special properties.

The transition matrix can be decomposed into 4 submatrices: - A - the submatrix from recurrent states to recurrent states. - B - the submatrix from transient to recurrent states. - C - the submatrix from transient to transient states. - O - the submatrix of zeros for recurrent to transient states.

Returns:

states, A, B, C

states - a list of state names with the first being the recurrent states and the last being the transient states in the order of the row names of A and then the row names of C. A - the submatrix from recurrent states to recurrent states. B - the submatrix from transient to recurrent states. C - the submatrix from transient to transient states.

Examples

>>> from sympy.stats import DiscreteMarkovChain
>>> from sympy import Matrix, S


One can decompose this chain for example:

>>> T = Matrix([[S(1)/2, S(1)/2, 0,      0,      0],
...             [S(2)/5, S(1)/5, S(2)/5, 0,      0],
...             [0,      0,      1,      0,      0],
...             [0,      0,      S(1)/2, S(1)/2, 0],
...             [S(1)/2, 0,      0,      0, S(1)/2]])
>>> X = DiscreteMarkovChain('X', trans_probs=T)
>>> states, A, B, C = X.decompose()
>>> states
[2, 0, 1, 3, 4]

>>> A   # recurrent to recurrent
Matrix([])

>>> B  # transient to recurrent
Matrix([
[  0],
[2/5],
[1/2],
[  0]])

>>> C  # transient to transient
Matrix([
[1/2, 1/2,   0,   0],
[2/5, 1/5,   0,   0],
[  0,   0, 1/2,   0],
[1/2,   0,   0, 1/2]])


This means that state 2 is the only absorbing state (since A is a 1x1 matrix). B is a 4x1 matrix since the 4 remaining transient states all merge into reccurent state 2. And C is the 4x4 matrix that shows how the transient states 0, 1, 3, 4 all interact.

References

fixed_row_vector()[source]#

A wrapper for stationary_distribution().

fundamental_matrix()[source]#

Each entry fundamental matrix can be interpreted as the expected number of times the chains is in state j if it started in state i.

References

property limiting_distribution#

The fixed row vector is the limiting distribution of a discrete Markov chain.

sample()[source]#
Returns:

sample: iterator object

iterator object containing the sample

stationary_distribution(condition_set=False) [source]#

The stationary distribution is any row vector, p, that solves p = pP, is row stochastic and each element in p must be nonnegative. That means in matrix form: $$(P-I)^T p^T = 0$$ and $$(1, \dots, 1) p = 1$$ where P is the one-step transition matrix.

All time-homogeneous Markov Chains with a finite state space have at least one stationary distribution. In addition, if a finite time-homogeneous Markov Chain is irreducible, the stationary distribution is unique.

Parameters:

condition_set : bool

If the chain has a symbolic size or transition matrix, it will return a Lambda if False and return a ConditionSet if True.

Examples

>>> from sympy.stats import DiscreteMarkovChain
>>> from sympy import Matrix, S


An irreducible Markov Chain

>>> T = Matrix([[S(1)/2, S(1)/2, 0],
...             [S(4)/5, S(1)/5, 0],
...             [1, 0, 0]])
>>> X = DiscreteMarkovChain('X', trans_probs=T)
>>> X.stationary_distribution()
Matrix([[8/13, 5/13, 0]])


A reducible Markov Chain

>>> T = Matrix([[S(1)/2, S(1)/2, 0],
...             [S(4)/5, S(1)/5, 0],
...             [0, 0, 1]])
>>> X = DiscreteMarkovChain('X', trans_probs=T)
>>> X.stationary_distribution()
Matrix([[8/13 - 8*tau0/13, 5/13 - 5*tau0/13, tau0]])

>>> Y = DiscreteMarkovChain('Y')
>>> Y.stationary_distribution()
Lambda((wm, _T), Eq(wm*_T, wm))

>>> Y.stationary_distribution(condition_set=True)
ConditionSet(wm, Eq(wm*_T, wm))


References

property transition_probabilities#

Transition probabilities of discrete Markov chain, either an instance of Matrix or MatrixSymbol.

class sympy.stats.ContinuousMarkovChain(sym, state_space=None, gen_mat=None)[source]#

Represents continuous time Markov chain.

Parameters:

sym : Symbol/str

state_space : Set

Optional, by default, S.Reals

gen_mat : Matrix/ImmutableMatrix/MatrixSymbol

Optional, by default, None

Examples

>>> from sympy.stats import ContinuousMarkovChain, P
>>> from sympy import Matrix, S, Eq, Gt
>>> G = Matrix([[-S(1), S(1)], [S(1), -S(1)]])
>>> C = ContinuousMarkovChain('C', state_space=[0, 1], gen_mat=G)
>>> C.limiting_distribution()
Matrix([[1/2, 1/2]])
>>> C.state_space
{0, 1}
>>> C.generator_matrix
Matrix([
[-1,  1],
[ 1, -1]])


Probability queries are supported

>>> P(Eq(C(1.96), 0), Eq(C(0.78), 1)).round(5)
0.45279
>>> P(Gt(C(1.7), 0), Eq(C(0.82), 1)).round(5)
0.58602


Probability of expressions with multiple RandomIndexedSymbols can also be calculated provided there is only 1 RandomIndexedSymbol in the given condition. It is always better to use Rational instead of floating point numbers for the probabilities in the generator matrix to avoid errors.

>>> from sympy import Gt, Le, Rational
>>> G = Matrix([[-S(1), Rational(1, 10), Rational(9, 10)], [Rational(2, 5), -S(1), Rational(3, 5)], [Rational(1, 2), Rational(1, 2), -S(1)]])
>>> C = ContinuousMarkovChain('C', state_space=[0, 1, 2], gen_mat=G)
>>> P(Eq(C(3.92), C(1.75)), Eq(C(0.46), 0)).round(5)
0.37933
>>> P(Gt(C(3.92), C(1.75)), Eq(C(0.46), 0)).round(5)
0.34211
>>> P(Le(C(1.57), C(3.14)), Eq(C(1.22), 1)).round(4)
0.7143


Symbolic probability queries are also supported

>>> from sympy import symbols
>>> a,b,c,d = symbols('a b c d')
>>> G = Matrix([[-S(1), Rational(1, 10), Rational(9, 10)], [Rational(2, 5), -S(1), Rational(3, 5)], [Rational(1, 2), Rational(1, 2), -S(1)]])
>>> C = ContinuousMarkovChain('C', state_space=[0, 1, 2], gen_mat=G)
>>> query = P(Eq(C(a), b), Eq(C(c), d))
>>> query.subs({a:3.65, b:2, c:1.78, d:1}).evalf().round(10)
0.4002723175
>>> P(Eq(C(3.65), 2), Eq(C(1.78), 1)).round(10)
0.4002723175
>>> query_gt = P(Gt(C(a), b), Eq(C(c), d))
>>> query_gt.subs({a:43.2, b:0, c:3.29, d:2}).evalf().round(10)
0.6832579186
>>> P(Gt(C(43.2), 0), Eq(C(3.29), 2)).round(10)
0.6832579186


References

class sympy.stats.BernoulliProcess(sym, p, success=1, failure=0)[source]#

The Bernoulli process consists of repeated independent Bernoulli process trials with the same parameter $$p$$. It’s assumed that the probability $$p$$ applies to every trial and that the outcomes of each trial are independent of all the rest. Therefore Bernoulli Process is Discrete State and Discrete Time Stochastic Process.

Parameters:

sym : Symbol/str

success : Integer/str

The event which is considered to be success. Default: 1.

failure: Integer/str

The event which is considered to be failure. Default: 0.

p : Real Number between 0 and 1

Represents the probability of getting success.

Examples

>>> from sympy.stats import BernoulliProcess, P, E
>>> from sympy import Eq, Gt
>>> B = BernoulliProcess("B", p=0.7, success=1, failure=0)
>>> B.state_space
{0, 1}
>>> (B.p).round(2)
0.70
>>> B.success
1
>>> B.failure
0
>>> X = B + B + B
>>> P(Eq(X, 0)).round(2)
0.03
>>> P(Eq(X, 2)).round(2)
0.44
>>> P(Eq(X, 4)).round(2)
0
>>> P(Gt(X, 1)).round(2)
0.78
>>> P(Eq(B, 0) & Eq(B, 1) & Eq(B, 0) & Eq(B, 1)).round(2)
0.04
>>> B.joint_distribution(B, B)
(0.3, Eq(B, 0)), (0, True))*Piecewise((0.7, Eq(B, 1)), (0.3, Eq(B, 0)),
(0, True))))
>>> E(2*B + B).round(2)
2.10
>>> P(B < 1).round(2)
0.30


References

expectation(expr, condition=None, evaluate=True, **kwargs)[source]#

Computes expectation.

Parameters:

expr : RandomIndexedSymbol, Relational, Logic

Condition for which expectation has to be computed. Must contain a RandomIndexedSymbol of the process.

condition : Relational, Logic

The given conditions under which computations should be done.

Returns:

Expectation of the RandomIndexedSymbol.

probability(condition, given_condition=None, evaluate=True, **kwargs)[source]#

Computes probability.

Parameters:

condition : Relational

Condition for which probability has to be computed. Must contain a RandomIndexedSymbol of the process.

given_condition : Relational, Logic

The given conditions under which computations should be done.

Returns:

Probability of the condition.

class sympy.stats.PoissonProcess(sym, lamda)[source]#

The Poisson process is a counting process. It is usually used in scenarios where we are counting the occurrences of certain events that appear to happen at a certain rate, but completely at random.

Parameters:

sym : Symbol/str

lamda : Positive number

Rate of the process, lambda > 0

Examples

>>> from sympy.stats import PoissonProcess, P, E
>>> from sympy import symbols, Eq, Ne, Contains, Interval
>>> X = PoissonProcess("X", lamda=3)
>>> X.state_space
Naturals0
>>> X.lamda
3
>>> t1, t2 = symbols('t1 t2', positive=True)
>>> P(X(t1) < 4)
(9*t1**3/2 + 9*t1**2/2 + 3*t1 + 1)*exp(-3*t1)
>>> P(Eq(X(t1), 2) | Ne(X(t1), 4), Contains(t1, Interval.Ropen(2, 4)))
1 - 36*exp(-6)
>>> P(Eq(X(t1), 2) & Eq(X(t2), 3), Contains(t1, Interval.Lopen(0, 2))
... & Contains(t2, Interval.Lopen(2, 4)))
648*exp(-12)
>>> E(X(t1))
3*t1
>>> E(X(t1)**2 + 2*X(t2),  Contains(t1, Interval.Lopen(0, 1))
... & Contains(t2, Interval.Lopen(1, 2)))
18
>>> P(X(3) < 1, Eq(X(1), 0))
exp(-6)
>>> P(Eq(X(4), 3), Eq(X(2), 3))
exp(-6)
>>> P(X(2) <= 3, X(1) > 1)
5*exp(-3)


Merging two Poisson Processes

>>> Y = PoissonProcess("Y", lamda=4)
>>> Z = X + Y
>>> Z.lamda
7


Splitting a Poisson Process into two independent Poisson Processes

>>> N, M = Z.split(l1=2, l2=5)
>>> N.lamda, M.lamda
(2, 5)


References

class sympy.stats.WienerProcess(sym)[source]#

The Wiener process is a real valued continuous-time stochastic process. In physics it is used to study Brownian motion and it is often also called Brownian motion due to its historical connection with physical process of the same name originally observed by Scottish botanist Robert Brown.

Parameters:

sym : Symbol/str

Examples

>>> from sympy.stats import WienerProcess, P, E
>>> from sympy import symbols, Contains, Interval
>>> X = WienerProcess("X")
>>> X.state_space
Reals
>>> t1, t2 = symbols('t1 t2', positive=True)
>>> P(X(t1) < 7).simplify()
erf(7*sqrt(2)/(2*sqrt(t1)))/2 + 1/2
>>> P((X(t1) > 2) | (X(t1) < 4), Contains(t1, Interval.Ropen(2, 4))).simplify()
-erf(1)/2 + erf(2)/2 + 1
>>> E(X(t1))
0
>>> E(X(t1) + 2*X(t2),  Contains(t1, Interval.Lopen(0, 1))
... & Contains(t2, Interval.Lopen(1, 2)))
0


References

class sympy.stats.GammaProcess(sym, lamda, gamma)[source]#

A Gamma process is a random process with independent gamma distributed increments. It is a pure-jump increasing Levy process.

Parameters:

sym : Symbol/str

lamda : Positive number

Jump size of the process, lamda > 0

gamma : Positive number

Rate of jump arrivals, $$\gamma > 0$$

Examples

>>> from sympy.stats import GammaProcess, E, P, variance
>>> from sympy import symbols, Contains, Interval, Not
>>> t, d, x, l, g = symbols('t d x l g', positive=True)
>>> X = GammaProcess("X", l, g)
>>> E(X(t))
g*t/l
>>> variance(X(t)).simplify()
g*t/l**2
>>> X = GammaProcess('X', 1, 2)
>>> P(X(t) < 1).simplify()
lowergamma(2*t, 1)/gamma(2*t)
>>> P(Not((X(t) < 5) & (X(d) > 3)), Contains(t, Interval.Ropen(2, 4)) &
... Contains(d, Interval.Lopen(7, 8))).simplify()
-4*exp(-3) + 472*exp(-8)/3 + 1
>>> E(X(2) + x*E(X(5)))
10*x + 4


References

### Matrix Distributions#

sympy.stats.MatrixGamma(symbol, alpha, beta, scale_matrix)[source]#

Creates a random variable with Matrix Gamma Distribution.

The density of the said distribution can be found at .

Parameters:

alpha: Positive Real number

Shape Parameter

beta: Positive Real number

Scale Parameter

scale_matrix: Positive definite real square matrix

Scale Matrix

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density, MatrixGamma
>>> from sympy import MatrixSymbol, symbols
>>> a, b = symbols('a b', positive=True)
>>> M = MatrixGamma('M', a, b, [[2, 1], [1, 2]])
>>> X = MatrixSymbol('X', 2, 2)
>>> density(M)(X).doit()
exp(Trace(Matrix([
[-2/3,  1/3],
[ 1/3, -2/3]])*X)/b)*Determinant(X)**(a - 3/2)/(3**a*sqrt(pi)*b**(2*a)*gamma(a)*gamma(a - 1/2))
>>> density(M)([[1, 0], [0, 1]]).doit()
exp(-4/(3*b))/(3**a*sqrt(pi)*b**(2*a)*gamma(a)*gamma(a - 1/2))


References

sympy.stats.Wishart(symbol, n, scale_matrix)[source]#

Creates a random variable with Wishart Distribution.

The density of the said distribution can be found at .

Parameters:

n: Positive Real number

Represents degrees of freedom

scale_matrix: Positive definite real square matrix

Scale Matrix

Returns:

RandomSymbol

Examples

>>> from sympy.stats import density, Wishart
>>> from sympy import MatrixSymbol, symbols
>>> n = symbols('n', positive=True)
>>> W = Wishart('W', n, [[2, 1], [1, 2]])
>>> X = MatrixSymbol('X', 2, 2)
>>> density(W)(X).doit()
exp(Trace(Matrix([
[-1/3,  1/6],
[ 1/6, -1/3]])*X))*Determinant(X)**(n/2 - 3/2)/(2**n*3**(n/2)*sqrt(pi)*gamma(n/2)*gamma(n/2 - 1/2))
>>> density(W)([[1, 0], [0, 1]]).doit()
exp(-2/3)/(2**n*3**(n/2)*sqrt(pi)*gamma(n/2)*gamma(n/2 - 1/2))


References

sympy.stats.MatrixNormal(symbol, location_matrix, scale_matrix_1, scale_matrix_2)[source]#

Creates a random variable with Matrix Normal Distribution.

The density of the said distribution can be found at .

Parameters:

location_matrix: Real n x p matrix

Represents degrees of freedom

scale_matrix_1: Positive definite matrix

Scale Matrix of shape n x n

scale_matrix_2: Positive definite matrix

Scale Matrix of shape p x p

Returns:

RandomSymbol

Examples

>>> from sympy import MatrixSymbol
>>> from sympy.stats import density, MatrixNormal
>>> M = MatrixNormal('M', [[1, 2]], , [[1, 0], [0, 1]])
>>> X = MatrixSymbol('X', 1, 2)
>>> density(M)(X).doit()
exp(-Trace((Matrix([
[-1],
[-2]]) + X.T)*(Matrix([[-1, -2]]) + X))/2)/(2*pi)
>>> density(M)([[3, 4]]).doit()
exp(-4)/(2*pi)


References

### Compound Distribution#

class sympy.stats.compound_rv.CompoundDistribution(dist)[source]#

Class for Compound Distributions.

Parameters:

dist : Distribution

Distribution must contain a random parameter

Examples

>>> from sympy.stats.compound_rv import CompoundDistribution
>>> from sympy.stats.crv_types import NormalDistribution
>>> from sympy.stats import Normal
>>> from sympy.abc import x
>>> X = Normal('X', 2, 4)
>>> N = NormalDistribution(X, 4)
>>> C = CompoundDistribution(N)
>>> C.set
Interval(-oo, oo)
>>> C.pdf(x, evaluate=True).simplify()
exp(-x**2/64 + x/16 - 1/16)/(8*sqrt(pi))


References

## Interface#

sympy.stats.P(condition, given_condition=None, numsamples=None, evaluate=True, **kwargs)[source]#

Probability that a condition is true, optionally given a second condition.

Parameters:

condition : Combination of Relationals containing RandomSymbols

The condition of which you want to compute the probability

given_condition : Combination of Relationals containing RandomSymbols

A conditional expression. P(X > 1, X > 0) is expectation of X > 1 given X > 0

numsamples : int

Enables sampling and approximates the probability with this many samples

evaluate : Bool (defaults to True)

In case of continuous systems return unevaluated integral

Examples

>>> from sympy.stats import P, Die
>>> from sympy import Eq
>>> X, Y = Die('X', 6), Die('Y', 6)
>>> P(X > 3)
1/2
>>> P(Eq(X, 5), X > 2) # Probability that X == 5 given that X > 2
1/4
>>> P(X > Y)
5/12

class sympy.stats.Probability(prob, condition=None, **kwargs)[source]#

Symbolic expression for the probability.

Examples

>>> from sympy.stats import Probability, Normal
>>> from sympy import Integral
>>> X = Normal("X", 0, 1)
>>> prob = Probability(X > 1)
>>> prob
Probability(X > 1)


Integral representation:

>>> prob.rewrite(Integral)
Integral(sqrt(2)*exp(-_z**2/2)/(2*sqrt(pi)), (_z, 1, oo))


Evaluation of the integral:

>>> prob.evaluate_integral()
sqrt(2)*(-sqrt(2)*sqrt(pi)*erf(sqrt(2)/2) + sqrt(2)*sqrt(pi))/(4*sqrt(pi))

sympy.stats.E(expr, condition=None, numsamples=None, evaluate=True, **kwargs)[source]#

Returns the expected value of a random expression.

Parameters:

expr : Expr containing RandomSymbols

The expression of which you want to compute the expectation value

given : Expr containing RandomSymbols

A conditional expression. E(X, X>0) is expectation of X given X > 0

numsamples : int

Enables sampling and approximates the expectation with this many samples

evalf : Bool (defaults to True)

If sampling return a number rather than a complex expression

evaluate : Bool (defaults to True)

In case of continuous systems return unevaluated integral

Examples

>>> from sympy.stats import E, Die
>>> X = Die('X', 6)
>>> E(X)
7/2
>>> E(2*X + 1)
8

>>> E(X, X > 3) # Expectation of X given that it is above 3
5

class sympy.stats.Expectation(expr, condition=None, **kwargs)[source]#

Symbolic expression for the expectation.

Examples

>>> from sympy.stats import Expectation, Normal, Probability, Poisson
>>> from sympy import symbols, Integral, Sum
>>> mu = symbols("mu")
>>> sigma = symbols("sigma", positive=True)
>>> X = Normal("X", mu, sigma)
>>> Expectation(X)
Expectation(X)
>>> Expectation(X).evaluate_integral().simplify()
mu


To get the integral expression of the expectation:

>>> Expectation(X).rewrite(Integral)
Integral(sqrt(2)*X*exp(-(X - mu)**2/(2*sigma**2))/(2*sqrt(pi)*sigma), (X, -oo, oo))


The same integral expression, in more abstract terms:

>>> Expectation(X).rewrite(Probability)
Integral(x*Probability(Eq(X, x)), (x, -oo, oo))


To get the Summation expression of the expectation for discrete random variables:

>>> lamda = symbols('lamda', positive=True)
>>> Z = Poisson('Z', lamda)
>>> Expectation(Z).rewrite(Sum)
Sum(Z*lamda**Z*exp(-lamda)/factorial(Z), (Z, 0, oo))


This class is aware of some properties of the expectation:

>>> from sympy.abc import a
>>> Expectation(a*X)
Expectation(a*X)
>>> Y = Normal("Y", 1, 2)
>>> Expectation(X + Y)
Expectation(X + Y)


To expand the Expectation into its expression, use expand():

>>> Expectation(X + Y).expand()
Expectation(X) + Expectation(Y)
>>> Expectation(a*X + Y).expand()
a*Expectation(X) + Expectation(Y)
>>> Expectation(a*X + Y)
Expectation(a*X + Y)
>>> Expectation((X + Y)*(X - Y)).expand()
Expectation(X**2) - Expectation(Y**2)


To evaluate the Expectation, use doit():

>>> Expectation(X + Y).doit()
mu + 1
>>> Expectation(X + Expectation(Y + Expectation(2*X))).doit()
3*mu + 1


To prevent evaluating nested Expectation, use doit(deep=False)

>>> Expectation(X + Expectation(Y)).doit(deep=False)
mu + Expectation(Expectation(Y))
>>> Expectation(X + Expectation(Y + Expectation(2*X))).doit(deep=False)
mu + Expectation(Expectation(Y + Expectation(2*X)))

sympy.stats.density(expr, condition=None, evaluate=True, numsamples=None, **kwargs)[source]#

Probability density of a random expression, optionally given a second condition.

Parameters:

expr : Expr containing RandomSymbols

The expression of which you want to compute the density value

condition : Relational containing RandomSymbols

A conditional expression. density(X > 1, X > 0) is density of X > 1 given X > 0

numsamples : int

Enables sampling and approximates the density with this many samples

Explanation

This density will take on different forms for different types of probability spaces. Discrete variables produce Dicts. Continuous variables produce Lambdas.

Examples

>>> from sympy.stats import density, Die, Normal
>>> from sympy import Symbol

>>> x = Symbol('x')
>>> D = Die('D', 6)
>>> X = Normal(x, 0, 1)

>>> density(D).dict
{1: 1/6, 2: 1/6, 3: 1/6, 4: 1/6, 5: 1/6, 6: 1/6}
>>> density(2*D).dict
{2: 1/6, 4: 1/6, 6: 1/6, 8: 1/6, 10: 1/6, 12: 1/6}
>>> density(X)(x)
sqrt(2)*exp(-x**2/2)/(2*sqrt(pi))

sympy.stats.entropy(expr, condition=None, **kwargs)[source]#

Calculuates entropy of a probability distribution.

Parameters:

expression : the random expression whose entropy is to be calculated

condition : optional, to specify conditions on random expression

b: base of the logarithm, optional

By default, it is taken as Euler’s number

Returns:

result : Entropy of the expression, a constant

Examples

>>> from sympy.stats import Normal, Die, entropy
>>> X = Normal('X', 0, 1)
>>> entropy(X)
log(2)/2 + 1/2 + log(pi)/2

>>> D = Die('D', 4)
>>> entropy(D)
log(4)


References

sympy.stats.given(expr, condition=None, **kwargs)[source]#

Conditional Random Expression.

Explanation

From a random expression and a condition on that expression creates a new probability space from the condition and returns the same expression on that conditional probability space.

Examples

>>> from sympy.stats import given, density, Die
>>> X = Die('X', 6)
>>> Y = given(X, X > 3)
>>> density(Y).dict
{4: 1/3, 5: 1/3, 6: 1/3}


Following convention, if the condition is a random symbol then that symbol is considered fixed.

>>> from sympy.stats import Normal
>>> from sympy import pprint
>>> from sympy.abc import z

>>> X = Normal('X', 0, 1)
>>> Y = Normal('Y', 0, 1)
>>> pprint(density(X + Y, Y)(z), use_unicode=False)
2
-(-Y + z)
-----------
___       2
\/ 2 *e
------------------
____
2*\/ pi

sympy.stats.where(condition, given_condition=None, **kwargs)[source]#

Returns the domain where a condition is True.

Examples

>>> from sympy.stats import where, Die, Normal
>>> from sympy import And

>>> D1, D2 = Die('a', 6), Die('b', 6)
>>> a, b = D1.symbol, D2.symbol
>>> X = Normal('x', 0, 1)

>>> where(X**2<1)
Domain: (-1 < x) & (x < 1)

>>> where(X**2<1).set
Interval.open(-1, 1)

>>> where(And(D1<=D2, D2<3))
Domain: (Eq(a, 1) & Eq(b, 1)) | (Eq(a, 1) & Eq(b, 2)) | (Eq(a, 2) & Eq(b, 2))

sympy.stats.variance(X, condition=None, **kwargs)[source]#

Variance of a random expression.

$variance(X) = E((X-E(X))^{2})$

Examples

>>> from sympy.stats import Die, Bernoulli, variance
>>> from sympy import simplify, Symbol

>>> X = Die('X', 6)
>>> p = Symbol('p')
>>> B = Bernoulli('B', p, 1, 0)

>>> variance(2*X)
35/3

>>> simplify(variance(B))
p*(1 - p)

class sympy.stats.Variance(arg, condition=None, **kwargs)[source]#

Symbolic expression for the variance.

Examples

>>> from sympy import symbols, Integral
>>> from sympy.stats import Normal, Expectation, Variance, Probability
>>> mu = symbols("mu", positive=True)
>>> sigma = symbols("sigma", positive=True)
>>> X = Normal("X", mu, sigma)
>>> Variance(X)
Variance(X)
>>> Variance(X).evaluate_integral()
sigma**2


Integral representation of the underlying calculations:

>>> Variance(X).rewrite(Integral)
Integral(sqrt(2)*(X - Integral(sqrt(2)*X*exp(-(X - mu)**2/(2*sigma**2))/(2*sqrt(pi)*sigma), (X, -oo, oo)))**2*exp(-(X - mu)**2/(2*sigma**2))/(2*sqrt(pi)*sigma), (X, -oo, oo))


Integral representation, without expanding the PDF:

>>> Variance(X).rewrite(Probability)
-Integral(x*Probability(Eq(X, x)), (x, -oo, oo))**2 + Integral(x**2*Probability(Eq(X, x)), (x, -oo, oo))


Rewrite the variance in terms of the expectation

>>> Variance(X).rewrite(Expectation)
-Expectation(X)**2 + Expectation(X**2)


Some transformations based on the properties of the variance may happen:

>>> from sympy.abc import a
>>> Y = Normal("Y", 0, 1)
>>> Variance(a*X)
Variance(a*X)


To expand the variance in its expression, use expand():

>>> Variance(a*X).expand()
a**2*Variance(X)
>>> Variance(X + Y)
Variance(X + Y)
>>> Variance(X + Y).expand()
2*Covariance(X, Y) + Variance(X) + Variance(Y)

sympy.stats.covariance(X, Y, condition=None, **kwargs)[source]#

Covariance of two random expressions.

Explanation

The expectation that the two variables will rise and fall together

$covariance(X,Y) = E((X-E(X)) (Y-E(Y)))$

Examples

>>> from sympy.stats import Exponential, covariance
>>> from sympy import Symbol

>>> rate = Symbol('lambda', positive=True, real=True)
>>> X = Exponential('X', rate)
>>> Y = Exponential('Y', rate)

>>> covariance(X, X)
lambda**(-2)
>>> covariance(X, Y)
0
>>> covariance(X, Y + rate*X)
1/lambda

class sympy.stats.Covariance(arg1, arg2, condition=None, **kwargs)[source]#

Symbolic expression for the covariance.

Examples

>>> from sympy.stats import Covariance
>>> from sympy.stats import Normal
>>> X = Normal("X", 3, 2)
>>> Y = Normal("Y", 0, 1)
>>> Z = Normal("Z", 0, 1)
>>> W = Normal("W", 0, 1)
>>> cexpr = Covariance(X, Y)
>>> cexpr
Covariance(X, Y)


Evaluate the covariance, $$X$$ and $$Y$$ are independent, therefore zero is the result:

>>> cexpr.evaluate_integral()
0


Rewrite the covariance expression in terms of expectations:

>>> from sympy.stats import Expectation
>>> cexpr.rewrite(Expectation)
Expectation(X*Y) - Expectation(X)*Expectation(Y)


In order to expand the argument, use expand():

>>> from sympy.abc import a, b, c, d
>>> Covariance(a*X + b*Y, c*Z + d*W)
Covariance(a*X + b*Y, c*Z + d*W)
>>> Covariance(a*X + b*Y, c*Z + d*W).expand()
a*c*Covariance(X, Z) + a*d*Covariance(W, X) + b*c*Covariance(Y, Z) + b*d*Covariance(W, Y)


This class is aware of some properties of the covariance:

>>> Covariance(X, X).expand()
Variance(X)
>>> Covariance(a*X, b*Y).expand()
a*b*Covariance(X, Y)

sympy.stats.coskewness(X, Y, Z, condition=None, **kwargs)[source]#

Calculates the co-skewness of three random variables.

Parameters:

X : RandomSymbol

Random Variable used to calculate coskewness

Y : RandomSymbol

Random Variable used to calculate coskewness

Z : RandomSymbol

Random Variable used to calculate coskewness

condition : Expr containing RandomSymbols

A conditional expression

Returns:

coskewness : The coskewness of the three random variables

Explanation

Mathematically Coskewness is defined as

$coskewness(X,Y,Z)=\frac{E[(X-E[X]) * (Y-E[Y]) * (Z-E[Z])]} {\sigma_{X}\sigma_{Y}\sigma_{Z}}$

Examples

>>> from sympy.stats import coskewness, Exponential, skewness
>>> from sympy import symbols
>>> p = symbols('p', positive=True)
>>> X = Exponential('X', p)
>>> Y = Exponential('Y', 2*p)
>>> coskewness(X, Y, Y)
0
>>> coskewness(X, Y + X, Y + 2*X)
16*sqrt(85)/85
>>> coskewness(X + 2*Y, Y + X, Y + 2*X, X > 3)
9*sqrt(170)/85
>>> coskewness(Y, Y, Y) == skewness(Y)
True
>>> coskewness(X, Y + p*X, Y + 2*p*X)
4/(sqrt(1 + 1/(4*p**2))*sqrt(4 + 1/(4*p**2)))


References

sympy.stats.median(X, evaluate=True, **kwargs)[source]#

Calculuates the median of the probability distribution.

Parameters:

X: The random expression whose median is to be calculated.

Returns:

The FiniteSet or an Interval which contains the median of the

random expression.

Explanation

Mathematically, median of Probability distribution is defined as all those values of $$m$$ for which the following condition is satisfied

$P(X\leq m) \geq \frac{1}{2} \text{ and} \text{ } P(X\geq m)\geq \frac{1}{2}$

Examples

>>> from sympy.stats import Normal, Die, median
>>> N = Normal('N', 3, 1)
>>> median(N)
{3}
>>> D = Die('D')
>>> median(D)
{3, 4}


References

sympy.stats.std(X, condition=None, **kwargs)[source]#

Standard Deviation of a random expression

$std(X) = \sqrt(E((X-E(X))^{2}))$

Examples

>>> from sympy.stats import Bernoulli, std
>>> from sympy import Symbol, simplify

>>> p = Symbol('p')
>>> B = Bernoulli('B', p, 1, 0)

>>> simplify(std(B))
sqrt(p*(1 - p))

sympy.stats.quantile(expr, evaluate=True, **kwargs)[source]#

Return the $$p^{th}$$ order quantile of a probability distribution.

Explanation

Quantile is defined as the value at which the probability of the random variable is less than or equal to the given probability.

$Q(p) = \inf\{x \in (-\infty, \infty) : p \le F(x)\}$

Examples

>>> from sympy.stats import quantile, Die, Exponential
>>> from sympy import Symbol, pprint
>>> p = Symbol("p")

>>> l = Symbol("lambda", positive=True)
>>> X = Exponential("x", l)
>>> quantile(X)(p)
-log(1 - p)/lambda

>>> D = Die("d", 6)
>>> pprint(quantile(D)(p), use_unicode=False)
/nan  for Or(p > 1, p < 0)
|
| 1       for p <= 1/6
|
| 2       for p <= 1/3
|
< 3       for p <= 1/2
|
| 4       for p <= 2/3
|
| 5       for p <= 5/6
|
\ 6        for p <= 1

sympy.stats.sample(expr, condition=None, size=(), library='scipy', numsamples=1, seed=None, **kwargs)[source]#

A realization of the random expression.

Parameters:

expr : Expression of random variables

Expression from which sample is extracted

condition : Expr containing RandomSymbols

A conditional expression

size : int, tuple

Represents size of each sample in numsamples

library : str

• ‘scipy’ : Sample using scipy

• ‘numpy’ : Sample using numpy

• ‘pymc’ : Sample using PyMC

Choose any of the available options to sample from as string, by default is ‘scipy’

numsamples : int

Number of samples, each with size as size.

Deprecated since version 1.9.

The numsamples parameter is deprecated and is only provided for compatibility with v1.8. Use a list comprehension or an additional dimension in size instead. See sympy.stats.sample(numsamples=n) for details.

seed :

An object to be used as seed by the given external library for sampling $$expr$$. Following is the list of possible types of object for the supported libraries,

• ‘scipy’: int, numpy.random.RandomState, numpy.random.Generator

• ‘numpy’: int, numpy.random.RandomState, numpy.random.Generator

• ‘pymc’: int

Optional, by default None, in which case seed settings related to the given library will be used. No modifications to environment’s global seed settings are done by this argument.

Returns:

sample: float/list/numpy.ndarray

one sample or a collection of samples of the random expression.

• sample(X) returns float/numpy.float64/numpy.int64 object.

• sample(X, size=int/tuple) returns numpy.ndarray object.

Examples

>>> from sympy.stats import Die, sample, Normal, Geometric
>>> X, Y, Z = Die('X', 6), Die('Y', 6), Die('Z', 6) # Finite Random Variable
>>> die_roll = sample(X + Y + Z)
>>> die_roll
3
>>> N = Normal('N', 3, 4) # Continuous Random Variable
>>> samp = sample(N)
>>> samp in N.pspace.domain.set
True
>>> samp = sample(N, N>0)
>>> samp > 0
True
>>> samp_list = sample(N, size=4)
>>> [sam in N.pspace.domain.set for sam in samp_list]
[True, True, True, True]
>>> sample(N, size = (2,3))
array([[5.42519758, 6.40207856, 4.94991743],
[1.85819627, 6.83403519, 1.9412172 ]])
>>> G = Geometric('G', 0.5) # Discrete Random Variable
>>> samp_list = sample(G, size=3)
>>> samp_list
[1, 3, 2]
>>> [sam in G.pspace.domain.set for sam in samp_list]
[True, True, True]
>>> MN = Normal("MN", [3, 4], [[2, 1], [1, 2]]) # Joint Random Variable
>>> samp_list = sample(MN, size=4)
>>> samp_list
[array([2.85768055, 3.38954165]),
array([4.11163337, 4.3176591 ]),
array([0.79115232, 1.63232916]),
array([4.01747268, 3.96716083])]
>>> [tuple(sam) in MN.pspace.domain.set for sam in samp_list]
[True, True, True, True]


Changed in version 1.7.0: sample used to return an iterator containing the samples instead of value.

Changed in version 1.9.0: sample returns values or array of values instead of an iterator and numsamples is deprecated.

sympy.stats.sample_iter(expr, condition=None, size=(), library='scipy', numsamples=oo, seed=None, **kwargs)[source]#

Returns an iterator of realizations from the expression given a condition.

Parameters:

expr: Expr

Random expression to be realized

condition: Expr, optional

A conditional expression

size : int, tuple

Represents size of each sample in numsamples

numsamples: integer, optional

Length of the iterator (defaults to infinity)

seed :

An object to be used as seed by the given external library for sampling $$expr$$. Following is the list of possible types of object for the supported libraries,

• ‘scipy’: int, numpy.random.RandomState, numpy.random.Generator

• ‘numpy’: int, numpy.random.RandomState, numpy.random.Generator

• ‘pymc’: int

Optional, by default None, in which case seed settings related to the given library will be used. No modifications to environment’s global seed settings are done by this argument.

Returns:

sample_iter: iterator object

iterator object containing the sample/samples of given expr

Examples

>>> from sympy.stats import Normal, sample_iter
>>> X = Normal('X', 0, 1)
>>> expr = X*X + 3
>>> iterator = sample_iter(expr, numsamples=3)
>>> list(iterator)
[12, 4, 7]

sympy.stats.factorial_moment(X, n, condition=None, **kwargs)[source]#

The factorial moment is a mathematical quantity defined as the expectation or average of the falling factorial of a random variable.

$factorial-moment(X, n) = E(X(X - 1)(X - 2)...(X - n + 1))$
Parameters:

n: A natural number, n-th factorial moment.

condition : Expr containing RandomSymbols

A conditional expression.

Examples

>>> from sympy.stats import factorial_moment, Poisson, Binomial
>>> from sympy import Symbol, S
>>> lamda = Symbol('lamda')
>>> X = Poisson('X', lamda)
>>> factorial_moment(X, 2)
lamda**2
>>> Y = Binomial('Y', 2, S.Half)
>>> factorial_moment(Y, 2)
1/2
>>> factorial_moment(Y, 2, Y > 1) # find factorial moment for Y > 1
2


References

sympy.stats.kurtosis(X, condition=None, **kwargs)[source]#

Characterizes the tails/outliers of a probability distribution.

Parameters:

condition : Expr containing RandomSymbols

A conditional expression. kurtosis(X, X>0) is kurtosis of X given X > 0

Explanation

Kurtosis of any univariate normal distribution is 3. Kurtosis less than 3 means that the distribution produces fewer and less extreme outliers than the normal distribution.

$kurtosis(X) = E(((X - E(X))/\sigma_X)^{4})$

Examples

>>> from sympy.stats import kurtosis, Exponential, Normal
>>> from sympy import Symbol
>>> X = Normal('X', 0, 1)
>>> kurtosis(X)
3
>>> kurtosis(X, X > 0) # find kurtosis given X > 0
(-4/pi - 12/pi**2 + 3)/(1 - 2/pi)**2

>>> rate = Symbol('lamda', positive=True, real=True)
>>> Y = Exponential('Y', rate)
>>> kurtosis(Y)
9


References

sympy.stats.skewness(X, condition=None, **kwargs)[source]#

Measure of the asymmetry of the probability distribution.

Parameters:

condition : Expr containing RandomSymbols

A conditional expression. skewness(X, X>0) is skewness of X given X > 0

Explanation

Positive skew indicates that most of the values lie to the right of the mean.

$skewness(X) = E(((X - E(X))/\sigma_X)^{3})$

Examples

>>> from sympy.stats import skewness, Exponential, Normal
>>> from sympy import Symbol
>>> X = Normal('X', 0, 1)
>>> skewness(X)
0
>>> skewness(X, X > 0) # find skewness given X > 0
(-sqrt(2)/sqrt(pi) + 4*sqrt(2)/pi**(3/2))/(1 - 2/pi)**(3/2)

>>> rate = Symbol('lambda', positive=True, real=True)
>>> Y = Exponential('Y', rate)
>>> skewness(Y)
2

sympy.stats.correlation(X, Y, condition=None, **kwargs)[source]#

Correlation of two random expressions, also known as correlation coefficient or Pearson’s correlation.

Explanation

The normalized expectation that the two variables will rise and fall together

$correlation(X,Y) = E((X-E(X))(Y-E(Y)) / (\sigma_x \sigma_y))$

Examples

>>> from sympy.stats import Exponential, correlation
>>> from sympy import Symbol

>>> rate = Symbol('lambda', positive=True, real=True)
>>> X = Exponential('X', rate)
>>> Y = Exponential('Y', rate)

>>> correlation(X, X)
1
>>> correlation(X, Y)
0
>>> correlation(X, Y + rate*X)
1/sqrt(1 + lambda**(-2))

sympy.stats.rv.sampling_density(expr, given_condition=None, library='scipy', numsamples=1, seed=None, **kwargs)[source]#

Sampling version of density.

sympy.stats.rv.sampling_P(condition, given_condition=None, library='scipy', numsamples=1, evalf=True, seed=None, **kwargs)[source]#

Sampling version of P.

sympy.stats.rv.sampling_E(expr, given_condition=None, library='scipy', numsamples=1, evalf=True, seed=None, **kwargs)[source]#

Sampling version of E.

class sympy.stats.Moment(X, n, c=0, condition=None, **kwargs)[source]#

Symbolic class for Moment

Examples

>>> from sympy import Symbol, Integral
>>> from sympy.stats import Normal, Expectation, Probability, Moment
>>> mu = Symbol('mu', real=True)
>>> sigma = Symbol('sigma', positive=True)
>>> X = Normal('X', mu, sigma)
>>> M = Moment(X, 3, 1)


To evaluate the result of Moment use $$doit$$:

>>> M.doit()
mu**3 - 3*mu**2 + 3*mu*sigma**2 + 3*mu - 3*sigma**2 - 1


Rewrite the Moment expression in terms of Expectation:

>>> M.rewrite(Expectation)
Expectation((X - 1)**3)


Rewrite the Moment expression in terms of Probability:

>>> M.rewrite(Probability)
Integral((x - 1)**3*Probability(Eq(X, x)), (x, -oo, oo))


Rewrite the Moment expression in terms of Integral:

>>> M.rewrite(Integral)
Integral(sqrt(2)*(X - 1)**3*exp(-(X - mu)**2/(2*sigma**2))/(2*sqrt(pi)*sigma), (X, -oo, oo))

sympy.stats.moment(X, n, c=0, condition=None, *, evaluate=True, **kwargs)[source]#

Return the nth moment of a random expression about c.

$moment(X, c, n) = E((X-c)^{n})$

Default value of c is 0.

Examples

>>> from sympy.stats import Die, moment, E
>>> X = Die('X', 6)
>>> moment(X, 1, 6)
-5/2
>>> moment(X, 2)
91/6
>>> moment(X, 1) == E(X)
True

class sympy.stats.CentralMoment(X, n, condition=None, **kwargs)[source]#

Symbolic class Central Moment

Examples

>>> from sympy import Symbol, Integral
>>> from sympy.stats import Normal, Expectation, Probability, CentralMoment
>>> mu = Symbol('mu', real=True)
>>> sigma = Symbol('sigma', positive=True)
>>> X = Normal('X', mu, sigma)
>>> CM = CentralMoment(X, 4)


To evaluate the result of CentralMoment use $$doit$$:

>>> CM.doit().simplify()
3*sigma**4


Rewrite the CentralMoment expression in terms of Expectation:

>>> CM.rewrite(Expectation)
Expectation((X - Expectation(X))**4)


Rewrite the CentralMoment expression in terms of Probability:

>>> CM.rewrite(Probability)
Integral((x - Integral(x*Probability(True), (x, -oo, oo)))**4*Probability(Eq(X, x)), (x, -oo, oo))


Rewrite the CentralMoment expression in terms of Integral:

>>> CM.rewrite(Integral)
Integral(sqrt(2)*(X - Integral(sqrt(2)*X*exp(-(X - mu)**2/(2*sigma**2))/(2*sqrt(pi)*sigma), (X, -oo, oo)))**4*exp(-(X - mu)**2/(2*sigma**2))/(2*sqrt(pi)*sigma), (X, -oo, oo))

sympy.stats.cmoment(X, n, condition=None, *, evaluate=True, **kwargs)[source]#

Return the nth central moment of a random expression about its mean.

$cmoment(X, n) = E((X - E(X))^{n})$

Examples

>>> from sympy.stats import Die, cmoment, variance
>>> X = Die('X', 6)
>>> cmoment(X, 3)
0
>>> cmoment(X, 2)
35/12
>>> cmoment(X, 2) == variance(X)
True

class sympy.stats.ExpectationMatrix(expr, condition=None)[source]#

Expectation of a random matrix expression.

Examples

>>> from sympy.stats import ExpectationMatrix, Normal
>>> from sympy.stats.rv import RandomMatrixSymbol
>>> from sympy import symbols, MatrixSymbol, Matrix
>>> k = symbols("k")
>>> A, B = MatrixSymbol("A", k, k), MatrixSymbol("B", k, k)
>>> X, Y = RandomMatrixSymbol("X", k, 1), RandomMatrixSymbol("Y", k, 1)
>>> ExpectationMatrix(X)
ExpectationMatrix(X)
>>> ExpectationMatrix(A*X).shape
(k, 1)


To expand the expectation in its expression, use expand():

>>> ExpectationMatrix(A*X + B*Y).expand()
A*ExpectationMatrix(X) + B*ExpectationMatrix(Y)
>>> ExpectationMatrix((X + Y)*(X - Y).T).expand()
ExpectationMatrix(X*X.T) - ExpectationMatrix(X*Y.T) + ExpectationMatrix(Y*X.T) - ExpectationMatrix(Y*Y.T)


To evaluate the ExpectationMatrix, use doit():

>>> N11, N12 = Normal('N11', 11, 1), Normal('N12', 12, 1)
>>> N21, N22 = Normal('N21', 21, 1), Normal('N22', 22, 1)
>>> M11, M12 = Normal('M11', 1, 1), Normal('M12', 2, 1)
>>> M21, M22 = Normal('M21', 3, 1), Normal('M22', 4, 1)
>>> x1 = Matrix([[N11, N12], [N21, N22]])
>>> x2 = Matrix([[M11, M12], [M21, M22]])
>>> ExpectationMatrix(x1 + x2).doit()
Matrix([
[12, 14],
[24, 26]])

class sympy.stats.VarianceMatrix(arg, condition=None)[source]#

Variance of a random matrix probability expression. Also known as Covariance matrix, auto-covariance matrix, dispersion matrix, or variance-covariance matrix.

Examples

>>> from sympy.stats import VarianceMatrix
>>> from sympy.stats.rv import RandomMatrixSymbol
>>> from sympy import symbols, MatrixSymbol
>>> k = symbols("k")
>>> A, B = MatrixSymbol("A", k, k), MatrixSymbol("B", k, k)
>>> X, Y = RandomMatrixSymbol("X", k, 1), RandomMatrixSymbol("Y", k, 1)
>>> VarianceMatrix(X)
VarianceMatrix(X)
>>> VarianceMatrix(X).shape
(k, k)


To expand the variance in its expression, use expand():

>>> VarianceMatrix(A*X).expand()
A*VarianceMatrix(X)*A.T
>>> VarianceMatrix(A*X + B*Y).expand()
2*A*CrossCovarianceMatrix(X, Y)*B.T + A*VarianceMatrix(X)*A.T + B*VarianceMatrix(Y)*B.T

class sympy.stats.CrossCovarianceMatrix(arg1, arg2, condition=None)[source]#

Covariance of a random matrix probability expression.

Examples

>>> from sympy.stats import CrossCovarianceMatrix
>>> from sympy.stats.rv import RandomMatrixSymbol
>>> from sympy import symbols, MatrixSymbol
>>> k = symbols("k")
>>> A, B = MatrixSymbol("A", k, k), MatrixSymbol("B", k, k)
>>> C, D = MatrixSymbol("C", k, k), MatrixSymbol("D", k, k)
>>> X, Y = RandomMatrixSymbol("X", k, 1), RandomMatrixSymbol("Y", k, 1)
>>> Z, W = RandomMatrixSymbol("Z", k, 1), RandomMatrixSymbol("W", k, 1)
>>> CrossCovarianceMatrix(X, Y)
CrossCovarianceMatrix(X, Y)
>>> CrossCovarianceMatrix(X, Y).shape
(k, k)


To expand the covariance in its expression, use expand():

>>> CrossCovarianceMatrix(X + Y, Z).expand()
CrossCovarianceMatrix(X, Z) + CrossCovarianceMatrix(Y, Z)
>>> CrossCovarianceMatrix(A*X, Y).expand()
A*CrossCovarianceMatrix(X, Y)
>>> CrossCovarianceMatrix(A*X, B.T*Y).expand()
A*CrossCovarianceMatrix(X, Y)*B
>>> CrossCovarianceMatrix(A*X + B*Y, C.T*Z + D.T*W).expand()
A*CrossCovarianceMatrix(X, W)*D + A*CrossCovarianceMatrix(X, Z)*C + B*CrossCovarianceMatrix(Y, W)*D + B*CrossCovarianceMatrix(Y, Z)*C


## Mechanics#

SymPy Stats employs a relatively complex class hierarchy.

RandomDomains are a mapping of variables to possible values. For example, we might say that the symbol Symbol('x') can take on the values $$\{1,2,3,4,5,6\}$$.

class sympy.stats.rv.RandomDomain[source]#

A PSpace, or Probability Space, combines a RandomDomain with a density to provide probabilistic information. For example the above domain could be enhanced by a finite density {1:1/6, 2:1/6, 3:1/6, 4:1/6, 5:1/6, 6:1/6} to fully define the roll of a fair die named x.

class sympy.stats.rv.PSpace[source]#

A RandomSymbol represents the PSpace’s symbol ‘x’ inside of SymPy expressions.

class sympy.stats.rv.RandomSymbol[source]#

The RandomDomain and PSpace classes are almost never directly instantiated. Instead they are subclassed for a variety of situations.

RandomDomains and PSpaces must be sufficiently general to represent domains and spaces of several variables with arbitrarily complex densities. This generality is often unnecessary. Instead we often build SingleDomains and SinglePSpaces to represent single, univariate events and processes such as a single die or a single normal variable.

class sympy.stats.rv.SinglePSpace[source]#
class sympy.stats.rv.SingleDomain[source]#

Another common case is to collect together a set of such univariate random variables. A collection of independent SinglePSpaces or SingleDomains can be brought together to form a ProductDomain or ProductPSpace. These objects would be useful in representing three dice rolled together for example.

class sympy.stats.rv.ProductDomain[source]#
class sympy.stats.rv.ProductPSpace[source]#

The Conditional adjective is added whenever we add a global condition to a RandomDomain or PSpace. A common example would be three independent dice where we know their sum to be greater than 12.

class sympy.stats.rv.ConditionalDomain[source]#

We specialize further into Finite and Continuous versions of these classes to represent finite (such as dice) and continuous (such as normals) random variables.

class sympy.stats.frv.FiniteDomain[source]#
class sympy.stats.frv.FinitePSpace[source]#
class sympy.stats.crv.ContinuousDomain[source]#
class sympy.stats.crv.ContinuousPSpace[source]#

Additionally there are a few specialized classes that implement certain common random variable types. There is for example a DiePSpace that implements SingleFinitePSpace and a NormalPSpace that implements SingleContinuousPSpace.

class sympy.stats.frv_types.DiePSpace#
class sympy.stats.crv_types.NormalPSpace#

RandomVariables can be extracted from these objects using the PSpace.values method.

As previously mentioned SymPy Stats employs a relatively complex class structure. Inheritance is widely used in the implementation of end-level classes. This tactic was chosen to balance between the need to allow SymPy to represent arbitrarily defined random variables and optimizing for common cases. This complicates the code but is structured to only be important to those working on extending SymPy Stats to other random variable types.

Users will not use this class structure. Instead these mechanics are exposed through variable creation functions Die, Coin, FiniteRV, Normal, Exponential, etc…. These build the appropriate SinglePSpaces and return the corresponding RandomVariable. Conditional and Product spaces are formed in the natural construction of SymPy expressions and the use of interface functions E, Given, Density, etc….

sympy.stats.Die()#
sympy.stats.Normal()#

There are some additional functions that may be useful. They are largely used internally.

sympy.stats.rv.random_symbols(expr)[source]#

Returns all RandomSymbols within a SymPy Expression.

sympy.stats.rv.pspace(expr)[source]#

Returns the underlying Probability Space of a random expression.

For internal use.

Examples

>>> from sympy.stats import pspace, Normal
>>> X = Normal('X', 0, 1)
>>> pspace(2*X + 1) == X.pspace
True

sympy.stats.rv.rs_swap(a, b)[source]#

Build a dictionary to swap RandomSymbols based on their underlying symbol.

i.e. if X = ('x', pspace1) and Y = ('x', pspace2) then X and Y match and the key, value pair {X:Y} will appear in the result

Inputs: collections a and b of random variables which share common symbols Output: dict mapping RVs in a to RVs in b